Renal Physio and Diuretics 1 Flashcards
Total body fluids account for
60% of body weight; person weighing 70 kg with approx 42 L of water (ICF 40%, ECF 20%, TBW 60%); IVF = 7% of body weight (5 L with 55% plasma, or 3L; and plasma is approx 25% of ECF; extravascular, or interstitial fluid approx 75% of ECF, or 11L)
Solute composition of ICF and ECF is different, but; raipd gains and losses in body weight reflect
solute concentration/osmoliarity of ICF and ECF is essentially the same (300 mOsm/L); osmolality and osmolarity essentially equivalent;
change in TBW and distribution of TBW
In 70 kg adult man, what is CO, RBF, RPF, GFR, urine output? What do they maean?
- CO = 5-6 L per min (approx equivalent to blood volume or 7% of body weight)
- RBF: 1-1.2 L/min (20% of CO perfuses the kidney)
- RPF = 600-720 ml/min (55% of RBF is this RPF and 20% of renal plasma flow is filtered in the glomeruli)
- GFR: 125 ml/min (daily, kidney filters 180 L of plasma daily, more than 10 times the ECF volume)
- Urine output: 14 L/day
Normal kidney function assessed by
ability to increase and decrease urine output in response to volume expansion and volume contraction, respectively
____ is the major solute determining
Na (Cl); ECF osmolarity and total amount of Na in ECF determines ECF volume; more Na in ECF results in larger ECF volume (expansion) and less Na in ECF results in smaller ECF volume (contraction)
What are volume receptors?
In vasculature, CNS, liver and kidneys (detects increase or decrease of ECF volume; expansion of ECF volume results in compensatory increase in Na and water output in urine, and contraction results in opposite)
Severe ECF volume contraction can
induce a decrease in GFR (for ECF volume expansion, won’t see a change in GFR)
How can we maintain sodium balance as we restrict how much Na we consume?
- 250 mEq/day of Na enters, then 250 mEq/day eliminated
- Down to 90, you have 160 eliminated, meaning 70 extra is eliminated, along with 70 of chloride, or 140 mOsmoles/day; here, to maintain ECF osmolarity constant (280 mOsm/L), need to contract ECF volume by amount equivalent to volume of urine necessary to eliminate excess Na and Cl isoosmotically (or .5L)
- With decrease in ECF volume and Na amount, kidney increases Na and water reabsorption and decreases amount of Na and water in urine (120/day); now need contraction of ECF volume by approx .2 L to maintain ECF osmolarity constant
Edema:
- Excess accumulation of fluid in interstitial space due to cardiac (CHF and increased hydrostatic pressure), renal (nephrotic syndrome with decreased oncotic pressure), hepatic (decreased oncotic pressure in liver disease), or endocrine dysfunction (hyperaldosteronism)
- imbalance of hydrostatic and oncotic pressures across capillary wall induces a shift in fluid distribution from intravascular space to extravascular space resulting in isotonic retention of Na and water, and decreased circulating volume
- Decreased circulating volume decreases renal perfusion pressure, RAA activated, and increases Na retention and maintains edema
- Approx ___ of filtered Na is reabsorbed in
66%; proximal tubule (use leaky epi to have isoosmotic reabsorption of H2O and solutes in proximal tubule; this water and solutes go to circulation through renal vein)
- Approx ____ of filtered Na reabsorbed in
25%; thick ascending loop of Henle; thin and thick ascending limb are impermeable to water (unlike thin descending limb), diluting the tubular fluid and reducing solute concentration/osmolarity of tubular fluid
Thick ascending limb of Loop of Henle is
solute transport engine driving and maintaining counter current multiplication of interstitial solute concentration difference or solute concentration gradient going from cortex to medulla surrounding CD
Distal tubule reabsorbs
6-8% of filtered Na, and in late distal tubule regulated by circulating levels of aldosterone; early distal impermeable to water, but late distal tubule permeable to water when induced by interaction with ADH
FF is; FEwater is
fraction of plasma flowing through glomeruli, which is ultrafiltered to form tubular fluid (ratio of GFR to RPF);
ratio of urine flow rate to GFR (clearance of inulin can estimate GFR), ultimately Pcreat/Ucreat or Pin/Uin
Amount of inulin filtered is; amount if inulin excreted in urine is
GFR x Pin; V x Uin; Cin = GFR = Uin x V/Pin