Redox Equilibria - 14 Flashcards

1
Q

what does an electrochemical cell consist of

A

*A cell has two half–cells.
*The two half cells have to be connected with a salt bridge.
*Simple half cells will consist of a metal (acts an electrode) and a solution of a compound containing that metal (eg Cu and CuSO4).
*These two half cells will produce a small voltage if connected into a circuit. (i.e. become a Battery or cell).

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2
Q

Why use a high resistance voltmeter?

A
  • The voltmeter needs to be of very high resistance to stop the current from flowing in the circuit.
  • In this state it is possible to measure the maximum possible potential difference (E).
  • The reactions will not be occurring because the very high resistance voltmeter stops the current from flowing.
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3
Q

Why does a voltage form when a zinc half-cell is connected to a copper half-cell?

A
  • When connected together the zinc half-cell has more of a tendency to oxidise to the Zn2+ ion and release electrons than the copper half-cell. (Zn —–> Zn2+ + 2e-)
  • More electrons will therefore build up on the zinc electrode than the copper electrode.
  • A potential difference is created between the two electrodes.
  • The zinc strip is the negative terminal and the copper strip is the positive terminal.
  • This potential difference is measured with a high resistance voltmeter, and is given the symbol E.
  • this same concept applies to any other cell
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4
Q

what is a salt bridge

A

A salt bridge is a piece of filter paper soaked in potassium nitrate

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5
Q

what is the function of a salt bridge

A
  • Completes the circuit by allowing the flow of ions between the half-cells.
  • Maintains electrical neutrality by preventing charge buildup in each half-cell.
  • Allows movement of ions, but does not react with the solutions or interfere with the electrode reactions.

Without a salt bridge, the cell would stop working as charge would build up and prevent electron flow.

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6
Q

why is a wire not used instead of a salt bridge

A

A wire is not used because the metal wire would set up its own electrode system with the solutions and wires do not allow the flow of ions

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7
Q

if a system does not contain an electrode that acts as a metal what can be used instead and why

A
  • Platinum
  • As: It provides a conducting surface for electron transfer
  • it is unreactive and can conduct electricity
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8
Q

what is the standard hydrogen electrode (SHE)

A

is an electrode that assigned the potential of 0 volts which used to measure the potential of all electrodes by comparing their potential to that of the standard hydrogen electrode

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9
Q

what is the hydrogen electrode equilibrium

A

H2 (g) <——> 2H+ (aq) + 2e-

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10
Q

what is the hydrogen electrode represented by in a standard electrode

A

Pt |H2 (g) | H+ (aq)

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11
Q

conditions of standard hydrogen electrode

A
  1. Hydrogen gas at pressure of 100 kPa
  2. Solution containing the hydrogen ion at 1.00 mol dm-3 (solution is usually 1 mol dm-3 HCl)
  3. Temperature at 298K
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12
Q

what does a SHE half cell consist of

A

a platinum wire is used which is coated in finely divided platinum (platinum black) which acts as a catalyst, because it is porous and can absorb the hydrogen gas

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13
Q

Why are secondary standard electrodes used, and what are some common examples?

A
  • The Standard Hydrogen Electrode (SHE) is difficult to use, so easier secondary standards are used instead.
  • These are calibrated (measured in comparison) against the SHE to ensure accuracy.
  • Common secondary standards:
  • Silver/Silver Chloride Electrode (Ag/AgCl)
  • Calomel Electrode (Hg₂Cl₂)
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14
Q

what is the standard electrode potential

A

the potential difference measured between an electrode system and hydrogen electrode system under standard conditions

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15
Q

what are standard conditions

A
  • All ion solutions at 1.00 mol dm-3
  • temperature 298K
  • gases at 100 kPa pressure
  • No current flowing
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16
Q

how to calculate the e cell

A

Ecell = Ered – Eox

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17
Q

how to identify which half cell is being oxidised and reduced

A
  • The more negative half cell will always oxidise
  • The more positive half cell will always reduce
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18
Q

Which half cell always oxidises in a redox reaction?

A

the more negative half cell (so if putting in an equation write it backwards)

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19
Q

Which half cell always reduces in a redox reaction?

A

The more positive half cell (so if putting in an equation write it forwards)

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20
Q

Where are the strongest reducing agents found in the electrochemical series?

A

At the most negative end (right side)

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21
Q

Where are the strongest oxidising agents found in the electrochemical series?

A

At the most positive end (left side)

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22
Q

on the electrochemical series which substance is more likely to reduce and which is more likely to oxidise

A

the more positive electrochemical will reduce (write forwards) and more negative electrochemical will oxidise (write backwards)

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23
Q

What does E°cell measure in a redox cell?

A

How far the reaction is from equilibrium; the more positive the E°cell, the more likely the reaction is to occur.

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24
Q

What happens to E°cell as current flows through a cell?

A

The reaction proceeds, reactant concentrations drop, and E°cell falls to zero as the reaction occurs

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25
Q

What effect does increasing temperature have on E°cell for most cells?

A

It decreases E°cell because most redox reactions are exothermic, so equilibrium shifts backward.

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26
Q

Does a positive E°cell always mean a reaction will occur?

A

No; a reaction might not occur if the activation energy is too high or the reaction is too slow

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27
Q

Why might the actual E°cell differ from the calculated standard E°cell?

A

Because the reaction is carried out under non-standard condition

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28
Q

What do electrochemical cells do?

A

Provide a commercial source of electrical energy by converting chemical energy into electrical energy.

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29
Q

What are the three types of electrochemical cells?

A

Non-rechargeable (irreversible), rechargeable (secondary), and fuel cells.

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30
Q

When is a cell considered non-rechargeable?

A

When the redox reactions inside are non-reversible.

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31
Q

examples of primary non rechargeable cells

A

zinc dry cell
Lithium –manganese dioxide cel

32
Q

example of secondary rechargeable cells

A

Lead acid Cell
nickel–cadmium cells
Lithium ion cell

33
Q

what is the overall reaction for a zinc dry cell and what is being reduced and oxidised

A

overall equation: 2MnO₂ + 2NH₄⁺ + Zn → Mn₂O₃ + 2NH₃ + H₂O + Zn²⁺
Zn is oxidised (E° = -0.76 V)
MnO₂ is reduced (E° = +0.75 V)

34
Q

What is the overall reaction for a lithium-manganese dioxide primary cell?

A

Li + MnO₂ → LiMnO₂

35
Q

Write the conventional cell diagram for a lithium-manganese dioxide cell
Li+(aq) + e- —> Li(s) E=-3.04V
Li+aq + MnO2 (s) +e- —> LiMnO2(s) E = - 0.13 V

A

Li(s) | Li⁺(aq) || Li⁺(aq), MnO₂(s), LiMnO₂(s) | Pt(s)

36
Q

What happens during discharge and charging in a rechargeable cell?

A

Discharge: forward reaction (releases energy)
Charge: reverse reaction (requires energy)

37
Q

What is the overall reaction for a lead–acid cell (discharging)?

A

PbO₂ + Pb + 2SO₄²⁻ + 4H⁺ → 2PbSO₄ + 2H₂O

38
Q

what makes cells reversible

A

due to the products staying attached onto the electrode and do not disperse

39
Q

What is the overall reaction in a nickel–cadmium cell?

A

2NiO(OH) + Cd + 2H₂O → 2Ni(OH)₂ + Cd(OH)₂

40
Q

What is the discharge reaction in a lithium-ion cell?

A

Li + CoO₂ → LiCoO₂

41
Q

how does lithium ion cells work to power cameras and mobile phones

A

The reagents in the cell are absorbed onto powdered graphite that acts as a support medium. The support medium allows the ions to react in the absence of a solvent such as water.

42
Q

Why can’t water be used as a solvent in lithium-ion cells?

A

Water would react with the lithium metal.

43
Q

What is the overall reaction in a hydrogen fuel cell using potassium hydroxide and using acidic electrolyte?

A

2H₂ + O₂ → 2H₂O

44
Q

Why is a higher temperature used in hydrogen fuel cells

A

as using standard conditions: The rate is too slow to produce an current so a higher temperature is used to increase the reaction rate

45
Q

Why can higher temperature decrease the EMF (overall voltage) in hydrogen fuel cells and how can it be counteracted

A

The reaction is exothermic; higher temperature shifts equilibrium, reducing voltage (Le Chatelier’s Principle).
- increasing the pressure can help counteract this

46
Q

Why does voltage remain constant in a hydrogen fuel cell compared to ordinary cells?

A
  • as they are continuously fed with fresh O2 and H2 so maintaining constant concentration of reactants.
  • This differs from ordinary cells where the voltage drops over time as the reactant concentrations drop
47
Q

limitations of hydrogen fuel cell

A
  • hydrogen is very flammable so not safe to store and transport
  • To store hydrogen as a liquid, it needs to be: Cooled and pressurised in strong, heavy containers which is expensive
  • materials store hydrogen through adsorption and absorption, which can wear out the material and may be a slow release of hydrogen from material when needed
  • hydrogen fuel cells have a limited lifetime so require regular replacements and are expensive to make so have a Hugh production cost
  • use of toxic chemicals in their production
48
Q

advantages of hydrogen fuel cells over petrol/diseal

A
  • less pollution and less CO2 as Pure hydrogen emits only water whilst hydrogen-rich fuels produce only small amounts of air pollutants and CO2
  • greater efficiency
49
Q

Name 3 ways hydrogen can be stored

A
  1. As a pressurised liquid
  2. Adsorbed onto a solid
  3. Absorbed within a solid
50
Q

What are the benefits of ethanol fuel cells over hydrogen?

A
  • Made from renewable sources
  • ethanol is less explosive so easier and safer to store than hydrogen
  • Raw materials to produce ethanol by fermentation are abundant
51
Q

What is the anode half-equation in an ethanol fuel cell?

A

C₂H₅OH + 3H₂O → 2CO₂ + 12H⁺ + 12e⁻

52
Q

What is the cathode half-equation in ethanol fuel cells?

A

O₂ + 4H⁺ + 4e⁻ → 2H₂O

53
Q

What is the colour change during the MnO₄⁻/Fe²⁺ titration?

A

Purple (MnO₄⁻) → Colourless (Mn²⁺)

54
Q

Why is the MnO₄⁻/Fe²⁺ titration self-indicating?

A

Because MnO₄⁻ is purple and Mn²⁺ is colourless, giving a clear visible colour change.

55
Q

What practical difficulty occurs when reading MnO₄⁻ in a burette?

A

The purple colour makes it hard to see the bottom of the meniscus.

56
Q

Which acid should be used in manganate titrations and why?

A

Dilute sulfuric acid – it provides enough H⁺ ions (8 per MnO₄⁻) and doesn’t interfere with redox reactions.

57
Q

Why can’t ethanoic acid be used in manganate titrations?

A

It’s too weak to provide enough H⁺ ions — leads to brown MnO₂ forming instead of Mn²⁺ leading to a greater (inaccurate) volume of manganate being used in the titration

58
Q

Why can’t conc. HCl be used in manganate titrations?

A

Cl⁻ gets oxidised to toxic Cl₂ gas by MnO₄⁻, giving an inaccurate greater volume of manganate being used and poisonous Cl2 being produced

59
Q

Why is nitric acid (HNO₃) unsuitable for manganate titrations?

A

It’s an oxidising agent and can oxidise Fe²⁺ to Fe³⁺, reducing the volume of MnO₄⁻ used

60
Q

What is the overall equation for the reaction between MnO₄⁻ and H₂O₂?

A

2MnO₄⁻ + 6H⁺ + 5H₂O₂ → 5O₂ + 2Mn²⁺ + 8H₂O

61
Q

What is the half-equation for the oxidation of ethanedioate ions (C₂O₄²⁻)?

A

C₂O₄²⁻ → 2CO₂ + 2e⁻

62
Q

What is the overall equation for the reaction between MnO₄⁻ and C₂O₄²⁻?

A

2MnO₄⁻ + 16H⁺ + 5C₂O₄²⁻ → 10CO₂ + 2Mn²⁺ + 8H₂O

63
Q

Why is the reaction between MnO₄⁻ and C₂O₄²⁻ slow at first?

A

Both are negative ions, so they repel each other. The rate increases once Mn²⁺ is formed (acts as a catalyst).

64
Q

How can you speed up the MnO₄⁻ and C₂O₄²⁻ reaction in a titration?

A

Heat the conical flask to 60°C before titration begins.

65
Q

What indicator is used in the thiosulfate titration and when is it added?

A

Starch indicator is added near the end point when iodine fades to pale yellow.

66
Q

What is the colour change in the thiosulfate titration when starch is added

A

The colour change is from blue/black to colourless (as iodine is reduced).

67
Q

Why should starch not be added until nearly all the iodine has reacted in the titration?

A

because the blue complex of starch with high concentrations of iodine is insoluble and does not re-dissolve as more thiosulfate is added, leading to inaccurate results

68
Q

what is the colour change in the reaction between I2 and thiosulfate S2O32- before stitch is added

A

yellow brown solution of starch to colourless solution of starch

69
Q

how to calculate percentage uncertainty

A

uncertainty/ measurements made on apparatus x 100

70
Q

ways to decrease apparatus uncertainties

A
  • use apparatus with greater resolution
  • increase the size of the measurements made
71
Q

when do you multiply by 2 when calculation percentage uncertainty

A

when using a burette

72
Q

how to reduce the uncertainty in a burette reading

A

by making the titre a larger volume either by:
- increasing the volume and concentration of the substance in the conical flask
- by decreasing the concentration of the substance in the burette.

73
Q

how to reduce the uncertainty of measuring cylinders

A
  • use a measuring cylinder with a greater resolution
  • Replacing measuring cylinders with pipettes or burettes which have lower apparatus uncertainty will lower the % uncertainty
74
Q

how to reduce the uncertainty when measuring the mass

A
  • Using a balance that measures to more decimal places or using a larger mass will reduce the % uncertainty in weighing a solid.
  • Weighing sample before and after addition and then calculating difference will ensure a more accurate measurement of the mass added.
75
Q

What does it mean if the % uncertainty due to the apparatus is less than the percentage difference between the actual and calculated values?

A

It indicates a discrepancy in the result due to other errors, not the apparatus.

76
Q

What does it mean if the % uncertainty due to the apparatus is greater than the percentage difference between the actual and calculated values?

A

There is no discrepancy, and any differences can be explained by the sensitivity of the equipment.