Redox 2 Flashcards

You may prefer our related Brainscape-certified flashcards:
1
Q

Standard electrode potential

A

Potential difference measured when half-cell connected to a standard hydrogen electrode under standard conditions (298K, 100kPa, 1M solutions)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Standard hydrogen electrode drawing

A

Look it up

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Standard conditions

A

298K, 100kPa, 1M solutions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Why is reference electrode necessary

A

Because voltage is relative value so hydrogen chosen as arbitrary reference.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

E cell of hydrogen electrode

A

0.00V

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

When use platinum electrode

A

When not metal and its ion

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

How to calculate E cell value

A

Keep E value of reduced, flip value of oxidised and add.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

+ve E cell meaning

A

Feasible

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How to write E cell diagram

A

Oxidation on left, reduction on right

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Why are conditions important when measuring E cell

A

Each half cell is at equilibrium therefore changing conditions shifts equilibrium. The more electrons are released, the more negative the solution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Why does +ve E cell mean feasible

A

Because it is proportional to S total, which is proportional to lnK.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

How to tell if an ion is stable wrt other ions

A

See if disproportionation is feasible.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Types of cells

A

Non-rechargeable, rechargeable and fuel cell

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Methanol fuel cells half reactions (acidic electrolyte)

A

CH3OH + H2O -> CO2 + 6H+ + 6e- at anode (oxidation)
O2 + 4H+ + 4e- -> 2H2O at cathode (reduction)
Platinum catalyst for both reactions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Acid hydrogen fuel cell half reactions

A

H2 -> 2H+ + 2e- at anode (oxidation)

O2 + 4H+ + 4e- -> 2H2O at cathode (reduction)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Alkali hydrogen fuel cell half reactions

A

O2 + 2H2O + 4e- -> 4OH- at cathode (reduction)

H2 + 2OH- -> 2H2O + 2e- at anode (oxidation)

17
Q

Effect of increasing conc of solutions in E cell

A

Makes cell emf more positive because fewer electrons produced as eq shift

18
Q

Effect of increasing pressure

A

Make cell emf more negative because more electrons produced

19
Q

How does increased oxidation make emf more negative

A

More electrons produced

20
Q

How does increased reduction make emf more positive

A

Fewer electrons produced