recombination and DNA damage Flashcards

1
Q

genetic stability vs genetic diversity

A

stability: allows genome conservation, DNA repair and avoid cancer/genome disorders
Diversity: occurs through meiosis, antibody diversity, adaptation and evolution

both important

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2
Q

what are the 5 mechanisms of genetic recombination?

A

homologous recombination (HR)
non-homologous end joining (NHEJ)
transpositions
site-specific recombination
independent assortment

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3
Q

what 2 ways can Holliday junctions be resolved?

A

non-crossover- both cleaving points the same orientation
crossover - both cleaving points opposite orientation causes ‘start’ and ‘end’ parts of the new strands to be from different initial strands

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4
Q

what proteins aid (d.s DNA break repair) homologous recombination and explain their functions

A

RecBCD- nuclease which aid to generate s.s. DNA
Rec A- recombinase which coats s.s DNA to condense DNA
RuvABC- resolves Holliday junction by cleavage, causing the crossover or non-crossover arrangement

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5
Q

what protein aids s.s break repair in homologous recombination?

A

only recA. which coats the single-stranded DNA

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6
Q

explain recBCD process AND the function of each molecule

A

rec C- chi scanning
rec B- degrades the 3’ prime more that 5’ prime
recD is faster than recB

1) ATP-dependent binding at DS end and digests 3’ more than 5’
2) when chi sequence reached 3’ no longer degraded, but 5’ is
3) once recA loaded, it coats DNA until chi is reached and results in the 5’ having much larger fragments than 3’

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7
Q

explain each ruvABC molecules function

A

ruvC- cleavage
ruvA- holds strands in square planar formation
ruvB- catalyses migration of junction, pulling the strands

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8
Q

explain NHEJ process and molecules involved

A

non-homologous end joining
after DS break:
1) ku recognises and binds to broken ends to keep them in place
2)lig 4 ligates the two ends together, or sometimes they are directly ligated together

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9
Q

explain the two processes of site-specific recombination

A

head-to-head–> inversion
—–>—a—b—<——- ——>—b—a—-<—-
the strands fold together where arrows align and the sequence in between, is inverted, and new ‘arrows’ are comprised of half DNA of both initial ones.

head-to-tail—> deletion or integration
—–>–a–b—>——
forms a plasmid of circular DNA (comprising of a and b) and a linear DNA
- reversible process
- new ‘arrows’ are comprised of half DNA of both initial ones.

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10
Q

explain E.coli chromosome dimer resolution and the two possible outcomes.

A

ds circular DNA is broken and new DNA strands are formed by nucleotide pairing.
-when no crossover- 2 identical ds circular DNA molecules are produced, one with original DNA and one with new DNA, these can go into two separate daughter cells.
-when crossover, linked DNA formed, these cannot go into two separate daughter cells. needs to have one more crossover site– XerCD recombinase used (site-specific recombination used) now two separate daughter cells are formed, they both have new and original DNA.

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11
Q

what are the three ways DNA replication can cause damage?

A
  • nicks/gaps lead to REPLICATION FORK COLLAPSE
  • replication fork reversal and restart
  • over replication
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12
Q

which are RuvABC dependent?
- nicks/gaps lead to REPLICATION FORK COLLAPSE
- replication fork reversal and restart
- over replication

A

only the replication fork reversal and re-start, but all use this even if not dependent

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13
Q

explain over replication and what molecules involved

A

occurs when DNA is re-started even though DNA forks are blocked and unfused
they run into Ter regions (unreplicated DNA) and continue replication
molecules: RecBC, recA and RuvABC (but is ruvABC independent)

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14
Q

what does priA do?

A

priA is the initiator of replication when away from ori
allows for replication re-start
it targets replication and recombination structures

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15
Q

what leads to replication fork collapse and what molecules are involved.

A

nick or gaps in DNA
when regulatory proteins fail to stabilize it
uses priA DNA repair enzyme to re-start replication once resolved
molecules: RecBC, recA and RuvABC (but is ruvABC independent)

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16
Q

what causes replication fork reversal and re-start? what molecules are involved and explain their function?

A

causes: transcription collision, replication defects, strong binding of proteins on DNA
ruvAB facilitates reversal and strands ‘walk back’
ruvC cuts DNA and creates ds-break, which can be resolved by DNA repair
recA sometimes helps reverse lagging strand before ruvAB binding
THUS RUVABC DEPENDENT
pri A used to re-start replication.

17
Q

what were the three hypothesised models of homologous recombination?

A
  • break-join (no DNA synthesis)
  • copy- choice (no DNA break)
  • break-copy (DNA synthesis and break)
18
Q

How was the copy-choice mechanism disproven?

A

Meselson and weigle experiment
- DNA breakage occurs as the experiment resulted in recombination between two genes close together

19
Q

does recombination at one locus have an effect on the recombination frequency at a nearby locus?

A

YES
closer together–> increased recombination rate

20
Q

does recombination leave a scar on DNA?

A

yes due to heteroduplex DNA formation
- colour and size were stained by ‘heavy’ isotopes and in recombination, small percentage of heavy DNA was left– scar of heteroduplex DNA

21
Q

what is a heteroduplex DNA?

A

double-stranded molecule of nucleic acid originated through the genetic recombination of single complementary strands derived from different sources, such as from different homologous chromosomes.

22
Q

calculation
recombination frequency

A

R(AB)= number of recombinants (where ab are the same= ABc+abC+abc+ABC) / total

23
Q

how do you determine the parental genes in a cross?

A

parental are always highest frequency

24
Q

calculation
R(double observed)

A

(abc + ABC) (wildtype and double mutant)/Total

25
Q

calculation
R(double expected)

A

R(AB) X R(BC) (furthest away from each other on genome)

26
Q

calculation
coeficient of coincidence (S)

A

R(dO)/R(dE)

27
Q

calculation
interference

A

1-S