Receptor theory 2 Flashcards
1
Q
Define Intrinsic activity (efficacy) (α)
A
- Maximal response expressed as a fraction of the maximal response for the entire system (full agonist = 1, full antagonist = 0)
2
Q
Describe receptor-drug interactions
A
- Strength of interaction between a drug and receptor defined by the drug’s affinity for that receptor.
- Forces controlling affinity are thermodynamic
- Result: drug resides within a protein binding pocket in a position of minimal free energy.
- Chemical forces vary according to the distance between drug and receptor binding surface.
- Drug molecules are not static, but approach and dissociate from the protein surface.
- Affinity can be modelled by a simple mathematical equation.
3
Q
What are some chemical forces that affect affinity of drug-receptor
A
- Electrostatic
- Hydrogen bonding
- Van der Waals forces
- Hydrophobic bonds
4
Q
What was Clarks Quantitative Receptor concept
A
- Originator of quantitative receptor theory developed by applying chemical laws to biological phenomena.
- Suggested that measurable drug-evoked responses in tissues resulted from the unimolecular interaction of the drug and a substance on the cell surface. (1:1 interaction)
- it is significant that the quantitative relations between the concentration of acetylcholine and its action on smooth muscle cells, could be most accurately expressed by the formulae devised by Langmuir to express the adsorption of gases on metal filaments
5
Q
What is The basics of Langmuir Adsorption Isotherm
A
- Total area available for binding = 1
- Area already bound = θ1
- Area available for binding = 1 - θ1
- Molecules have a rate of diffusion toward a surface (condensation, α). – not same alpha as earlier
- Molecules have a rate of dissociation away from a surface (evaporation, V1).
6
Q
What was Languir equation for rate of adsorption and rate of evaporation
A
- Rate of adsorption = α.μ.(1 - θ1)
- μ = drug concentration
- Rate of evaporation = V1. θ1
7
Q
What is Langmuir Adsorption Isotherm at equilibrium
A
- . At equilibrium, adsorption = evaporation.
2 . Therefore, α.μ.(1 - θ1) = V1. θ1 - Re-arrange, θ1 = α.μ./(α.μ. + V1)
8
Q
How can the Langmuir Adsorption Isotherm be re-written in pharmacological nomenclature:
A
- ρ =fraction of maximal binding (between 0-1)
- [AR] =amount of drug-receptor complex
- [Rt] =total number of receptor sites
- [A] = concentration of drug
- KA = dissociation constant
- p=[AR]/[Rt]=[A]/[A]+KA
9
Q
Describe agonist receptor interaction
A
- Agonist and receptors form drug receptors complex
- Stimulus causes response
10
Q
What is rate of offset/rate of onset
A
- Rate of offset/rate of onset = k2/k1= rate of evaporation/condensation
11
Q
What is law of mass action
A
- The Law of Mass Action (the rate of reaction is proportional to the product of the concentrations of the reactants) can be applied.
- At equilibrium the forward and reverse rates are equal.
12
Q
How can k1[A][R]=k2[AR] be rearranged given the law of mass action
A
- ([A][R])/[AR]=k2/k1=Ka
13
Q
What does it mean when [A] = KA
A
- KA is a concentration and quantifies affinity.
- If [A] = KA then ρ = 0.5 (i.e. 50% of the total receptor population are bound).
- Assume [drug] and KA are both 10μmol/L
- Thus ρ = 10/(10+10) = 10/20 = 0.5
- KA is therefore the concentration of drug required to occupy 50% of the total receptor population.
14
Q
What does a smaller KA mean
A
- The smaller the KA, the higher the affinity.
15
Q
A
- For drug-receptor interactions the Dissociation constant is KA NOT KD which is obtained from ligand binding studies. ???