reagents Flashcards

1
Q

TsCl , Py or NEt3

A

good leaving group, doesnt invert chirality center

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2
Q

MCPBA

A

conver alkene to an epoxide, syn

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3
Q

HBr

A

SN1 mostly for converting OH to halide

protonates OH first to make water that leaves

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4
Q

NaOH

A

strong base so E2, favors zaitsev product (more substituted alkene)

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5
Q

tBuOK

A

E1, non Nuc base, bulky so favor hoffman product

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6
Q

NaH

A

E2 reaction
base, so will eliminate beta H to create alkene
also can use to deprotonate OH groups and then make the OH group thing now a base to add to stuff

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7
Q
conc H2SO4 (hot)
(start with OH group)
A

E1 elimination, because protic solvent,

usually to convert OH to alkene because first protonate OH and then water will remove beta H to get alkene

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8
Q

H3O+ (start with alkene)

A

adds OH to the alkene, usually markovnikov addition

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9
Q

Br2 H2O

A

brominium ion intermediate is formed, it gets water will attack the more substitured

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10
Q

1) O3

2) DMS or Zn HOAc

A

will take the double bond and break to create carbonyls

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11
Q

1) OsO4

2) NaHSO4

A

syn addition of 2 OH to alkene

+ Enantiomer

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12
Q

KMnO4, NaOH cold dilute

A

syn addition of 2 OH to alkene

+ Enantiomer

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13
Q

1) RCO3H

2) H3O+

A

epoxide formed

anti addition of 2 OH

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14
Q

H2, Pt

A

syn addition

full reduction of alkyne to alkane or alkene to alkane

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15
Q

1) BH3*THF

2) H2O2, NaOH

A

syn addition of H and OH to an alkene
antimarkovnikov
+ En

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16
Q

1) Hg(OAc)2, H2O

2) NaBH2

A

alkene to alcohol

markovnikov addition

17
Q

xs HX

A

converts alkyne to dihalide

18
Q

1) xs NaNH2

2) H2O

A

converts dihalides to alkynes

water is there to protonate the alkyne again because the NH2 could keep deprotonating it

19
Q

H2, Lindlar

A

only can reduce alkyne to Z alkene (cis)

20
Q

Na NH3 (l)

A

alkyne to E alkene (Z)

21
Q

HgSO4, H2SO4 H2O

A

alkyne to ketone with a methyl at one end (other end would be what ever what originally at the other end of the alkyne)

22
Q

1) R2BH or BH3

2) H2O2, NaOH

A

alkyne to ketone but one end is H (other end would be what ever what originally at the other end of the alkyne)

23
Q

xs X2, CCl4

A

alkyne to alkane with 4 halides attached

24
Q

i equiv. X2, CCl4

A

E alkene (trans) with 2 halides attached

25
Q

Br2, ROOR

A

radical mechanisms

Br radical will rip off H, pi bond wont do anything in this reaction

26
Q

HBr, ROOR

A

radical mechanism

pi bond reactions with Br radical

27
Q

Cl2 heat/ hv

A

not as selective, eveything is made

28
Q

Br2 heat/hv

A

selective because slower reaction