Reaction Mechanisms Flashcards
For Exam 2
What is an elementary process?
- It expresses how molecules or ions react with each other at the molecular level, not the overall reaction.
- A series of elementary processes makes up a reaction mechanism
- Based on numbers of molecules involved in the elementary step, there are three kinds of elementary steps: unimolecular process, bimolecular process, and trimolecular process.
How do you write the rate law for an elementary process?
- The exponent for the concentration is the same as the coefficient in the chemical equation for that elementary process
- Ex: 2NO2 –> NO3 + NO
- rate = k[NO2]2
- (And if we don’t have the chemical equation for the elementary process, we need to get it experimentally.)
What is a rate-determining step?
(aka rate-limiting step)
- It’s the slow step in a mechanism. The reaction can’t go any faster.
- The order for the rate-determining step is the same as the order of the overall reaction
- So the rate law for the rate-determining step is directly related to the rate law for the overall reaction
What is a reaction mechanism?
- A series of elementary processes
- We know that there are multiple steps if the experimentally determined rate law does not correspond to the coefficients in the chemical equation
- The overall rate law corresponds with the rate of the slowest step
Molecularity
What are unimolecular, bimolecular, and trimolecular processes?
Molecularity = how many molecules are involved on the reactant side.
3 types of elementary processes:
-
Unimolecular - when a molecule or ion decomposes by itself
- 1st order
- Ex: O3 –> O2 + O Rate = k [O3]
-
Bimolecular - two reacting molecules or ions. Most common.
- 2nd order
- A + A = B + C Rate = k [A]2
A + B = X + Y Rate = k [A] [B]
-
Termolecular - 3 molecules. Statistically very unlikely.
- 3rd order
- A + A + A = products Rate = k [A]3
A + A + B = products Rate = k [A]2 [B]
A + B + C = products Rate = k [A] [B] [C]
What is a catalyst?
- A substance that changes the rate of a chemical reaction without being used up (not part of rxn)
- Provides a path to the products that has a rate-detmining step with a lower activation energy, allowing more of the reactant molecules to have the minimum energy needed
Extra from book:
- Positive catalysts: speed up reactions
- Negative catalysts (inhibitors): slow down
- Homogenous catalysts: same phase as reactants
-
Heterogenous catalysts: different phase from reactants
- Usually a solid. Promotes rxn through adsorption.
What are enzymes?
- Biological catalysts, facilitate almost every reaction
- They have active sites
The orders in a rate law have to match what?
- The order of the rate determining step
- If the rate determining step is the first step, then it’s easy! The exponents for the rate law will be the stoich coefficients of that step.
- Ex: 2NO2 → NO3 + NO (slow)
- NO3 + CO → NO2 + CO2 (fast)
Rate=k[NO2]2
- If the rate determining step is later, have to use SSA or prequilibrium assumption to substitute out the intermediate
How do you make sure a rate law is correct?
- The order of the rate law should match the order / molecularity of the rate determining step.
- No intermediates in the rate law.
- (This is because we don’t know their concentrations, and we want to write in terms of reactants.)
What are reaction intermediates?
- Product of the first step, reactant of the second step
- Notation: they are written in the mechanism, but cancelled for the BCE
- Graph: The local minimum of the new action pathway is where you would find the intermediates.
- Difference from transition state: a transition state is a very unstable combination of two species. Whereas n intermediate is isolatable, something you could potentially actually find in the beaker.
Interpret graph of reaction mechanism.
What do the peaks and valleys represent?
- Number of peaks is the number of steps.
- The highest peak is the step with the highest activation barrier and will have the lowest rate.
- The valleys are the intermediates.
What is steady state approximation?
- When there is not much of the intermediate in the beaker because as soon as it’s produced, it is consumed immediately. (See graph.)
- Assumption: Δ [intermediate] / Δ time = 0
- Δ = production - consumption
- Assumption: Δ [intermediate] / Δ time = 0
- Different from preequilibrium assumption because we aren’t assuming equilibrium
- Steps:
- Write the rate law from the rate determining step.
- Recognize the intermediate.
- Set up the assumption: Δ [intermediate] / Δ time = 0.
- Solve for [intermediate].
- Plug into the rate law.
What is the preequilibrium assumption?
- When the equilibrium is the fast step (before the rate determining step)
- Assumes that the reactants and intermediates have reached equilibrium
- Set the rates of the forward and reverse reactions equal to each other, solve for the intermediate
- Plug into the rate law
The rate constant is ____ if the step is faster.
The rate constant is ________ if the step is slower.
bigger
smaller
How do you make sure a reaction mechanism is valid?
- The individual elementary steps should add up to the overall reaction. (After cancelling out intermediates.)
- The rate determining step should match the order of the experimental rate law.