Reaction Kinetics Flashcards
Steady state approximation
If there are reactive intermediates, their concentration will increase to a point, then remain constant in time
What does the steady state approximation allow us to assume
d[I]/dt = 0
Chain length
The rate of propigation divided by the rate of termination
If there are two possible equations for chain length, which is used
The smallest value answer
If a reaction rate is pressure dependent, what does that mean practically
It is dependent on [M]
Rate equation for the formation of products in a unimolecular reaction
d[products]/dt = k1k3[A][M]/(k2[M] + k3)
Change in uni molecular rate at high pressure
At high pressure, [M] is large and so, k3[M] + k3 is approximately equal to k3[M] as k3 is relatively so small
Change in unimolecular rate at low pressure
[M] is low and so k3[M] + k3 is equal to k3 as k3 is relatively so much larger
Overall changes in unimolecular reaction rate with pressure
First order at high pressure, second order at low pressure
k(infinity) definition
Hugh pressure limiting my rate coefficient - k at infinite pressure
k0 definition
The low pressure limiting rate coefficient
Plot to check validity of the unimolecular rate model
Plot 1/kobs against 1/[M]. Intercept is 1/k(infinity) and gradient is 1/k1
Experimental flaws with the Lindemann mechanism
A high pressure, kobs increases more rapidly than the theory predicts
Assumptions made my the Lindemann model
Assumed that any excited reactant will undergo the same reaction with the same value of k. Generally, the excited energy must be in a degree of freedom related to the reaction e.g. excitation of a vibrational state of the bond due to break
Differences in bath gases
Bath gases impart energy in reagents depending on their degrees of freedom. Translational quanta are small, rotational larger etc. this means the more degrees of freedom, the better the energising properties of the bath gas