Reaction Cycles Flashcards

1
Q

Name some charged ligands

A

X-, H-, CH3-, OH-, NR2-

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2
Q

How to find d electron count

A

Group number - oxidation state

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3
Q

How to know if a complex is low spin

A

Metal is 2nd/3rd row
Strong field ligands
High metal charge

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4
Q

Octahedral splitting is high (tetrahedral is …)

A

Tetrahedral splitting is low = square planar

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5
Q

How to know if complex is high spin

A

Metal is 1st row
Weak field ligands
Low metal charge

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6
Q

Octahedral splitting is low (tetrahedral is …)

A

Tetrahedral is high = tetrahedral

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7
Q

Counting electrons structure (NEUTRAL)

A

dn metal = n electrons
Total ligands electrons
Overall complex charge: + = -1e, - = +1e

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8
Q

vacant site H
| |
M——(H) —> M=—

A

B-Hydride elimination:
Cis vacant site
Planar space for alkene
Stable alkene

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9
Q

CO O=CMe O=CMe
/ / /
M —> M —> M
\ \ \
Me Vacant site R

A

Migratory Insertion:
Bulky ligands increase rate
More positive carbon increase rate
Eth or Meth are best at migrating

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10
Q

A
/
M —> M + A—B
\
B

A

Reductive elimination:
Oxidation state= -2
d electrons= +2
Coordinatively saturated
Electron withdrawing groups on metal

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11
Q

A
/
M + A—B ——> M
\
B

A

Oxidative addition:
Oxidation state =+2
d electrons =-2
Neutral molecule added
Coordinately unsaturated complex
EDG ligands

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12
Q

Pre catalyst —> active catalyst

A

Thermal or photolysis ligand dissociation

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13
Q

How to selectively increase the rate

A

Donor solvent for migratory insertion
Less substituted alkene
Conjugated alkene
Increase temperature

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14
Q

Define Productivity

A

Grams made per mole of catalyst per unit of time

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15
Q

Define Turn over number

A

Number of cycles catalyst completes in a set time
Nproduct / Ncatalyst = TON

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16
Q

Define Turn over frequency

A

Moles of product by moles of catalyst over time

TON / time = TOF

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17
Q

Why is selectivity the most important for a catalyst

A

Industrial processes are continuous, side products are a loss so a low yield can be fixed by recycling the starting material, increasing the catalyst loading and increasing the time for the reaction. Side products cannot be fixed.

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18
Q

Methanol carbonylation

A

Methanol + CO —> methanonic acid

19
Q

Draw the catalytic cycle for methanol carbonylation.

A

Organic cycle :
Methanol to methyl-iodide
Methylcarbonyl-iodide to methanoic acid
Organometallic cycle
Oxidative addition
Migratory insertion of CO
Reductive elimination

20
Q

Rds for methanol carbonylation

A

Oxidative addition: Rh
Migratory insertion: Ir

21
Q

Hydroformulation

A

Alkene to aldehyde

22
Q

Draw the catalytic cycle for hydroformylation

A

Activation to 16e
Alkene insertion
1,2 migratory insertion of H
Ligand coordination
Migratory insertion of CO
Oxidative addition of H2
B-hydride elimination

23
Q

What is the rds for hydroformylation

A

Oxidative addititon

24
Q

Cross coupling reactions (Suzuki)

A

Aromatic-X + R-B(OH)2 —> Aromatic-R

25
Draw the catalytic cycle for Suzuki cross coupling reaction
Activation to 16e Oxidative addition Transmetalation Reductive elimination
26
Cross coupling reactions (Heck - alkene/arom)
R-Alkene + Aromatic-X —> R-Alkene-Aromatic Basic conditions
27
Cross coupling reactions (Heck - Alkene/Alkene)
R-Alkene + Alkene-X —> R-Conjugated Alkene
28
Draw the catalytic cycle for Heck Reaction mechanism
Activate catalyst to 14e Oxidative addition of Aromatic-X Ligand substitution for alkene 2,1 migratory insertion B-hydride elimination Ligand substitution of product Reductive elimination of HX
29
Cross coupling reaction (Amination)
Aromatic-X + NHR2 —> Aromatic-NR2 Strong base
30
Draw the catalytic cycle for Amination
Catalyst activation 16e Oxidative addition of Aromatic-X Ligand substitution of H for NHR2 Deprotination of NHR2 Reductive elimination of Aromatic-NR2
31
What is a cationic catalyst cycle
Alkene coordination THEN Oxidative Addition Chelating phosphene ligand Weakly coordinating ligand Overall positive charge on the complex
32
How to make chiral alkane
Prochiral alkene Stereoisomer phosphene ligands, one side bulky other side less bulky After reaction two stereoisomers made depending on what face of prochiral alkene is attacked
33
How to control stereoselectivity
Phosphene ligands have different sized substituents that cannot interconvert Phosphene ligands have the same sized substituents that cannot interconvert due to chiral backbone that sets the conformation The diastereoisomers that are formed are of different energies and stabilises
34
What is the main complication with controlling the stereoselectivity of catalysis
The most stable diastereoisomer doesn’t always lead to the major product, eg the rate of addition may be faster than that of the stable product so it progresses to form the product and the stable one doesn’t.
35
What are the different types of chiral ligands
Chiral backbone P-chiral (chelating phosphene ligands substituents are chiral) Chiral substituents Planar chirality Atropisomer
36
How do you control regioselectivity for a branches isomer in hydroformylation
Electron withdrawing R groups on the substituent
37
What is cooperative catalysis
One catalyst and one catalytic cycle but substrate activation happens across two sites
38
How does hydrogenation work in cooperative catalysis
The catalyst has 2 active sites the metal and a ligand with lone pair H2 binds and is split Metal H: Hydride Lone pair H: Proton The different reactivities bind ti the carbonyl group and control the reaction geometry
39
Asymmetric hydrogenation using different metals
Fe, needs CO ligand to make more Fe+ character Ru, for amides Rh is el clasico
40
Methoxy carbonylation
= + CO + MeOH —> MeCH2C(O)OMe + H2O + O=CH2 —> CH2C(=)C(O)OMe 100% atom efficiency and cheap
41
What’s the catalytic mechanism for methoxycarbonylation
Oxidative addition of = to form alkane Oxidative addition of CO to form carbonyl Reductive elimination with MeOH to form product and hydrated catalyst
42
What is the structure of the catalyst in the second step of methoxycarbonylation (polymerisation)
Pd catalyst with chelating phosphenes H+X-
43
Polymerisation mechanism of methoxycarbonylation
Rate of = and CO insertion (looped reaction for polymerisation) faster than termination step (reductive elimination)
44
How do you increase the selectivity for methoxycarbonylation (mechanism)
Pd with bulky t-butyl substituents keep selectivity to methyl propanoate But has poor stability = insertion CO insertion MeOH coordination and elimination of products (methanolysis)