Radiation and the ISM Flashcards
intensity, flux, placnk function, wien's displacement law, NIR/FIR emission, 21cm hydrogen line, 2.6mm rotational line of CO, molecular clouds/cores/GMCs
Radians
Definition
θ = l/r radians l = arc length r = radius
Steradians
Definition
ω = A/r² steradians A = area on surface of sphere r = radius
What is the energy dEν entering a solid angle dω un time dt?
-the energy dEv in a frequency range v->v+dv, entering a solid angle dω in time dt is:
dEv = IvcosθdAdvdω*dt
-where Iv is the specific intensity
Units of Specific Intensity
-the cgs units of specific intensity are erg/(scm²Hzst) or in metric units: W/(m²Hzst)
Total Intensity in Terms of Specific Intensity
I = ∫ Iv dv
-integrated between 0 and ∞
Intensity and Distance
- intensity is independent of distance as, once inside the beam, radiation stays within it, it is conserved
- as an example, the Sun’s intensity remains unchanged as long as you resolve the radiation that is emitted
Flux of Radiation
Definition
-flux of radiation fv is defined as the amount of energy crossing a unit area per unit time per unit frequency interval
fv = 1/dAdvdt ∫ dEv
-where the integral is taken over the area S
Total Flux in Terms of Flux of Radiation
F = ∫ fv dv
-where the integral is taken between 0 and ∞
Units of Flux
-the units of flux in cgs units are erg cm^(-2) Hz^(-1) or in metric units: J m^(-2) s^(-1) Hz^(-1)
Relationship Between Flux and Intesity
-the relationship between flux and intensity is:
fv = ∫ Iv cosθ dω
Intensity in Thermodynamic Equilibrium
-for blackbodys in thermodynamic equilibrium, the specific intensity is given by:
Iv=Bv
-where Bv is the Planck function
Planck Function
Bv = 2hv³/c² * 1/[exp(hv/kT)-1]
-in units of W m^-2 Hz^-1 st^-1
Total Intensity of a Blackbody in Thermodynamic Equilibrium
B = ∫ Bv dv = σT^4/π W/m²
-where σ is the Stefan-Boltzmann constant:
σ = 5.67 * 10^(-8) W m^-2 K^-4
Flux of a Blackbody in Thermodynamic Equilibrium
-integrating over radiation travelling from a surface in all outwards directions (i.e. over a solid angle equal to half a sphere)
-total flux is given by:
F = πB
Notable Features of the Planck Function on a Log-Log Scale
- straight line portion of the graph at lower frequencies in log-log space
- shift of peak to higher frequency with temperature
Rayleigh-Jeans Law
-a low frequency / high temperature simplification of the Planck function
Bv = 2v²kT/c²
-so for the log scale:
log(Bv) = 2log(v) + log(T) + C
-where C = log(2K/c²) is a constant
-this expression for log(Bv) is essentially the equation for a straight line, the straight portion of the Planck curve
- an increase in log(v) by one order of magnitude results in an increase in log(Bv) by two orders of magnitude
Wien’s Displacement Law
Peak Frequency
-to find the value of frequency at which the peak intensity is reached
-calculate the derivative of the Planck Function and set equal to 0
-solve the resulting equation using numerical methods
=>
vmax/T = 2.82k/h = 5.88*10^8 Hxz/K
Wien’s Displacement Law
Peak Wavelength
-to determine the peak wavelength λmax the law must be derived using the wavelength form of the Planck Function
-the following relation DOES NOT hold:
vmaxλmax=c
-since:
Bλ dλ = Bv dv
-rearrange:
Bλ = Bv * dv/dλ
=>
λmaxT = 0.29cm K
Typical Wavelengths of Dust Cloud Emission
-starlight warms the dust grains to T≈ 10-100K
-thus from Wien’s displacement law:
λmax*T = 0.29cm K
=>
λmax ≈ 30-300µm
-these are far-infrared (FIR) wavelengths
-at these wavelengths, interstellar dust radiates more strongly than stars, so a FIR view of the sky is a view of the location of interstellar dust
Visible vs FIR vs NIR View of the Milky Way
- at visible wavelengths, light suffers from so much interstellar extinction through absorption by dust that the galactic nucleus is obscured from view
- BUT the amount of interstellar extinction is roughly inversely proportional to wavelength
- a FIR view shows up the cold interstellar dust clouds as they emit FIR more strongly than stars
- a NIR view shows up the stars, stars emit more strongly at NIR than FIR
Radio View of the Milky Way
- as radio wavelengths are long, radio waves can penetrate the interstellar medium even more easily than infrared light
- atomic hydrogen, the most abundant element in the universe, emits radio waves even in relatively cold clouds
What is the origin of the 21cm hydrogen line?
- particles such as protons and electrons possess spin
- in the case of atomic hydrogen with a single proton and single electron, the state can change from high energy, both spins aligned, to a lower energy arrangement, opposite spins
- this transition releases a photon of 1420MHz or 21cm wavelength, a radio photon
- this is a tiny energy transition, approximately 10^(-6) times the magnitude of that for electronic transitions
Radio View of the Galactic Disc
- looking within the plane of the galaxy from out position, hydrogen clouds at different locations along our line of site will be moving at slightly different speeds relative to us
- this is because they are at different distances from the galactic centre than us and speed of orbiting clouds increases closer to the galactic centre
- radio waves from these clouds are subject to slightly different Doppler shifts and this allows us to map the morphology of the milky way
Limitations of the Radio View of the Galactic Disc
-gas in the region of the galaxy immediately opposite us is moving perpendicular to our line of sight so does not exhibit a Doppler shift and so we cannot map that part of the galaxy using this technique