quiz math lab dilution (chapter 6) Flashcards
Two parts to a dilution
Sample (solute): the sample to be diluted
Diligent (solvent): the dilution used to perform the dilution
Solute + Solvent = solution
A dilution is often referred to as a “1 to 10” or “1 to 2” dilution
•1 to 10 dilution: for every 1 part of sample, there is a total of 10 parts of the solution.
•1to 10 dilution: for every 1 part of sample, there is a total of 10 parts of the solution.
•1 part of the sample is used and 9 parts of the diluent are used.
• If 10 parts of the diluent are used, then there these there would be a total of 11 partsto the solutions.
A simple dilution uses the following formula:
Sample volume
Sample volume +diluent volume or
Sample volume
Total volume
Simple dilution
Example:
• A 1 to 4 dilution of serum is to be made.
• The total volume of the dilution is to be 100 uL.
• What volumes of serum and diluent ( deionized water) are need?
Solve problem: use ratio and proportion.
1 part sample volume = x part sample volume
4 parts total volume 100 parts total volume
Cross multiplying the equation yields the following:
(1) x (100) = (4) x (x)
100 =4X
100/4=x
25= x
25.0 uL is the sample serum volume
100.0 -25.0, or 75.0 uL, is the diluent volume.
Dilution variations example:
• If you had a dilution in which you added 0.5 parts sample to 9.5 parts diluent, what is the value of the actual dilution you perform?
Dilution variations: To solver this dilution problem :
•because 0.5 is < 10.
5 must be multiplied by 2. (0.5x2=1)
• the denominator value of 10.0 (0.5 sample volume + 9.5 diluent volume) is also multiplied by 2.
(10x2=20)
•The value would be a1 to 20 dilution.
Diluted specimen volues the result
After the has been diluted and analyzed,
The result obtained must be corrected for the dilution.
Use a factor ( the reciprocal of the dilution that was performed) to correct the result.
Example: in a 1to 4 dilution, the factor for these dilution is the reciprocal of 1 to 4, or 4.
Example :
•a1to 5 dilution is performed on a serum specimen. The reanalyzed dilutes creatinine samples result is 4.5 mg/dL. What is the patient actual creatinine result?
Example :
•a1to 5 dilution is performed on a serum specimen. The reanalyzed dilutes creatinine samples result is 4.5 mg/dL. What is the patient actual creatinine result?
•
• The dilutes sample results must be multiplied byte dilation factor to determine the concentration in undiluted sample. 4.5 mg/dLx5(dilution factor) =22.5mg/dL.
•therefore, the patient’s actual creatinine result is 22.5mg/dL, Not 4.5 mg/dL.
Dilutions versus ratios
•A dilution formed by the ratio of sample volume to the total volume..
•ratio 1:4 = 1Part sampled,4 parts di vent
•dilation 1/4 =1 Part sample, 3 parts diluent
• in the above ratio example,a 1.4 ratio is a 1/5 dilation.
Serial and tube dilutions
• serial dilution n -same dilution for each tube in a series
•Very large dilutions of the serums can occurs with only a small amought of serum and diluent used.
•tube dilution series = different dilution for each tube..
In both cases, the final dilutio is the product of each individual dilution.
• final dilutions =( dilution 1)x( dilution 2)x(dilution3) and so on.
Serial dilutions:
Step 1
Step 2
Step3
Step 4
Step1: perform a 1 to 10 dilution of the serum (10uL of serum to 90uL of diluent):tube 1
Step2: perform a 1 to 10 dilution of tube 1(10uL tube 1 to 90uL of diluent in tube 2):tube 2
Step3: perform a 1 to 10 dilution of tube 2(10 uL tube 2 to 90uL of diluent in tube 3):tube 3
Step 4) discard 10uL from tube 3 ( for equivalent volume in all tubes)
Serial dilutions:
Step 1 tube
Step 2 tube
Step 3 tube
Step 4,tube ..
1) tube 1 is diluted 1 to 10.
2) tube 2 is diluted 1 to 100.
3)tube 3 is diluted 1 to 1000
4) 10uL of sample and 270 uL of diluent can make a 1 to 1000 dilution.
Serial dilution
Example: how is a 1 to 1000 dilution done using small volumes of serum and dilution?
Tube dilutions: determine the concentration of each tube
• divide first tube, in a series dilution factor used in it dilution.
•1/5 dilution was performed; factor =5
• the sample concentration in tube 1 is : ( 1650 mg/dL) / 5 or 330 mg /dl
Prefixes. SI system (base unit rated to metric system)
Meter = length
Kilogram = mass
Second= time
Mole=( amount of substance)
Cerisis =(temperature)
Tera = ( symbol = T)
Factor (10^12) = ( Decimal 1 000 000 000 000
Giga ( symbol G)
Factor (10^9) = 1 000 000 000
Mega (symbol M)
Factors (10^) 1 000 000
Kilo (symbol K)
Factor (10^3) decimal 1 000
Hector (symbol D)
Factor 10^2. Decimal 1 00
Dear symbol Da
Factor 10^1 decimal 10
Deci (symbol) D
Factor10^-1 dcimsl 0.1
Centi symbol c
Factor 10^-2 decimal 0.01
Mill symbol m
Factor 10^-3 decimal 0.001
Micro symbol u
Factor 10^-6 decimal 0.000 001