Quiz 9 Flashcards

1
Q

What does the back side condition INSULATED mean in FDS?

A

That a virtual layer is applied to the back of the wall with 100% insulating capability. Therefore no heatloss through the wall.

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2
Q

What does the back side condition VOID mean in FDS?

A

That the back side of the wall connects to ambient properties. Heat loss is present and lost from the simulation to the void.

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3
Q

What does the back side condition EXPOSED mean in FDS?

A

Heat is transported to the back side of the wall and able to do heat exchange with the surrounding fluid.

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4
Q

What criteria have to be met for FDS to accept the EXPOSED back side condition?

A

The wall can be a maximum of 1 cell thick and some computational domain must be present on the other side.

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5
Q

Are there any practical problems in FDS with walls that are not symmetrical (as in same composition regardless of viewpoint)? If so, how do you solve it?

A

o Yes, FDS uses a left-to-right standard when telling it what layers are present. Therefore an innermost layer will be facing the outside if heat returns through the layers.
o To deal with this one must create two SURF:s with layers in correct order from where heat is transferred.

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6
Q

By default in FDS, how many dimensions does the solid phase heat transfer model use? Can you name a few pros and cons of this approach?

A

o 1D
o fast calculations, good approximation when homogenous boundary conditions
o No distribution of heat within the material to the “neighbouring sides”/lateral heat transfer. Not good when inhomogeneous boundary condition present (e.g. flame against wall)

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7
Q

Does FDS allow for temperature dependent material properties? If so, how is it implemented?

A

Yes, through the ramp function one can apply dependent properties at points that FDS then interpolates between.

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8
Q

What is the difference between THICKNESS defined on a SURF line and the thickness you define on an OBST line? Which one does FDS use for heat transfer in the solid using the standard heat transfer model?

A

SURF thickness is used for conduction heat transfer. OBST thickness obstructs the fluid flow.

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9
Q

Do you see any practical limitations (besides computational cost) with using the 3D heat transfer model in FDS?

A

o Thin and multi-layered walls are a problem since the thermal properties must be uniform within each cell. Hence one must use many cells to get the resolution needed or try to mix with the thermal properties.
o Needs very fine cells to properly model heat wave

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