Questions from class - Lecture 2 Flashcards

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1
Q

What is the definition of an ideal chain?

A

An ideal chain is a chain where there is no interaction between the monomers.

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2
Q

Which parameters are used to describe the conformation and size of a polymer?

A

Mean-square end to end: = C_∞nl^2
Contour length: R_max = n
l
Radius of gyration: R_g^2 = 1/N*∑(r_i - r_cm)^2

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3
Q

How does the end-to-end distance depend on the degree of polymerization for an ideal chain?

A

R_max = n*l.
Mean-square end to end = C_∞ * nl^2

Proportional with n.

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4
Q

What is the characteristic ratio?

A

The characteristic ratio, denoted C_n, is the average value of C_i which is the sum over all the bond vectors for the i-th monomer.

The sum over all the bond vectors for the i-th monomer will converge to this number C_i, because the angle is only confined for monomers in close proximity.

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5
Q

What is the equivalent freely jointed chain?

A

A chain with same avgR^2 , same R_max, but that is divided into N freely-jointed bonds of length b (Kuhn-length).

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6
Q

What is the freely rotating chain and what is its end-to-end vector?

A

A chain where all the bond lengths and bond angles are fixed, but the torsion angles are free to rotate. All the angles have equal probability. In this case:

avgR^2 = N*b^2 * (1 + cos theta)/(1 - cos theta)

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7
Q

How is the hindered rotation model defined?

A

Here the torsion angles are not all equally probable. The probability of a given torsion angle is proportional to the Boltzmann factor, exp[-U(phi_i)/kT], where U(phi_i) is the energy barrier for the given torsion angle.

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8
Q

What is the definition of the radius of gyration?

A

The radius of gyration is defined as:

R_g^2 = 1/N * ∑(r_i - r_cm)^2,

which is the mean square average distance from the i-th monomer to the polymers centre of mass.

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9
Q

What is the relation between the radius of gyration and the end-to-end distance of an ideal chain?

A

R_g^2 = (Nb^2)/6 = avgR^2/6.

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10
Q

What is the free energy of an ideal chain?

A

F = U - TS, where U = 0 (because no interactions).

F = (3/2)kTR^2/(Nb^2)

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