Questionnaire Flashcards
What is the mass of a protium ( hydrogen without a neutron) isotope.
Solution:
Mass of protium = mass of proton+mass of electron
Mass = 1.67x10–²⁷ + 9.11x10-³¹
Mass = 1.67*10-²⁷ kg
What is 77°F in Kelvin units?
Solution:
(77°F - 32) x 5/9 + 273.15 = 298.15 K
What is the value of the universal gas constant in cal/mol-K?
Solution:
R= 8.3145 J/mol·K x (1 cal/4.184 J)
R= 1.987 cal/mol·K
What is the temperature of one mol of van der Waals gas at 49.6 atm at 0.536 L?
P= (nRT)/(V-nb) - n²a/v²
a= 3.61 L²·atm·mol²
b=0.0428L/mol
R=0.0821 L·atm/mol·K
Solution:
49.6 atm=[(1mol x 0.0821 L·atm/mol·K)/(0.536 L - (1 mol x 0.0428 L/mol)) ] - [(1 mol)² x 3.61 L²·atm·mol²)/0.536 L²]
49.6 atm=0.16646 atm/K - 12.56544 atm
49.6 atm - 12.56544 atm= 0.16646 atm/K
T= 373.45 K
A liquid has a density of 59.1 lb/ft³. What is its density in SI units?
Solution:
59.1 lb/ft³ x 0.45359 kg/lb x 1000 g/kg x 1 ft³/(0.3048 m)³
= 946.7 kg/m³
Nitrogen-15 (15.000108 amu) and Nitrogen-14 (14.003074 amu) comprises the majority of all the naturally-occurring isotopes. What is the fractional relative abundance of N-14? Let X be the relative abundance of N-14 and M be the atomic masses of the isotopes.
Solution:
M(N-14)X + M(N-15)(1-X) = 14.01
14.003074X + 15.000108(1-X) = 14.01
14.003074X - 15.000108X + 15.000108 - 14.01 = 0
-0.997X + 0.990 = 0
-0.997X = -0.990
X=0.993%
Calculate the mass of NaCl using the equations below obtained from a certain gravimetric analysis.
M(KCl) + M(NaCl) = 2.3 g
0.61M(KCl) + 0.48M(NaCl) = 1.27 g
Solution:
=> from eq.1,
M(KCl) = 2.3 - M(NaCl)
=> from eq.2,
0.61 (2.3 - M(NaCl)) + 0.48M(NaCl) = 1.27 g
1.403 g - 0.61M(NaCl) + 0.48M(NaCl)= 1.27 g
1.403 g - 1.27 g = 0.13M(NaCl))
M(NaCl) = 1.023 g
Calculate the pH of a 0.20 M solution of HF (Ka = 3.4 x 10–⁴).
Solution:
Ka = [H+]²/0.20- [H+]
3.4 x 10–⁴= x²/0.20 - x
3.4 x 10–⁴ (0.20 - x) = x²
6.85 x 10–⁵ - 3.4 x 10–⁴x= x²
x² + 3.4 x 10–⁴x - 6.85 x 10–⁵ = 0
X = 0.008
pH = -log(X)
pH = 2.09
What is the resulting expression if —log is applied to both sides of the equation?
Ka= [H+][A–]/ [HA]
Solution:
-logKa = -log( [H+][A–]/ [HA] )
pKa = pH - log([A–]/ [HA])
A beaker holds a 153 (±2) mL of liquid, then a 62 (±1) mL potion was removed. What is the uncertainty of the remaining liquid volume?
Solution:
E² = 2² + 1²
E= 2.23
What is the pH of a solution that contains 0.0053 ± 0.0004 M hydronium ion?
Solution:
pH = -log(0.0053) ±1/ln10 x 0.0004/0.0053
pH = 2.28 ± 0.03
What is the second derivative of the given function?
f(x) = sin x + cos x
Solution:
1st derivative: cos x - sin x
2nd derivative: -sin x - cos x
What is the result of the differential of the equation, H= U + PV is taken?
Solution:
H = U + PV
dH = dU + PdV + VdP
What is the (dV/dT)p of the modified van der Waals equation?
_
V = RT/P - a/RT + b
Solution:
(dV/dT)p = d/dT (RT/P) - d/dT (a/RT) + d/dT (b)
(dV/dT)p = R/P + a/T²
The work associated with isothermal reversible expansion or compression of gas is given by the equation below. Calculate the work associated if 52 mol gas is compressed from 30 to 10 L at 260 K.
Solution:
v2
W = -∫ nRT/V dV
** v1**
W = -nRT ∫1/v dV
W = -nRT (ln v)|¹⁰
³⁰
W = - 52 mol · 8.314 J/ mol·K ·260K (ln30 - ln10)
W = 123,489 J
What are examples of physical change?
-melting
-change of size/shape
-volume
-density
-crystal form
What are examples of chemical change?
- change in color
- change in temperature
- change in odor
- burning
- digestion
- decomposition
what is the % abundance of Cl-35 and Cl-37 if the average atomic mass of chlorine is 35.45 amu?
Solution:
Let x = % abundance of Cl-35
Let 1-x = % abundance of Cl-37
35.45 = 35(x) + 37(1-x)
35.45 = 35x - 37x + 37
35.45 - 37 = 35x -37x
-1.55 = -2x
x = 0.775 or 77.5%
1-x = 0.225 or 22.5%
Who postulated the energy emission of an electron when it drops from higher to lower energy level?
Neils Bohr
The Bohr model postulates that electrons orbit the nucleus at fixed energy levels. Orbits further from the nucleus exist at higher energy levels. When electrons return to a lower energy level, they emit energy in the form of light.
Electrons are ejected when a certain metal is irradiated with radiation with a frequency of 5.5x10¹⁴/s. If the work function of the metal is 2.9x10–¹⁹ J, what is the kinetic energy of each ejected electrons?
Solution:
Planck’s constant = 6.626 x 10–³⁴ J·s
KE= (5.5 x 10¹⁴/s) · (6.626 x 10–³⁴ J·s) - (2.9 x 10–¹⁹ J)
KE = 7.443 x 10–²⁰ J
He postulated that all matter is made up of small indestructible units called atoms.
Democritus
He proposed the Atomic Theory which states;
- Each element is made up of atoms.
- Atoms of a given element are identical.
- Compounds are formed when atoms combine with each other.
- Chemical reactions involve reorganization of the atoms.
John Dalton
He created the periodic table and discovered that the properties of elements were periodic functions of their atomic weights.
Dmitri Mendeleev
He proposed the Theory of Electromagnetism and made the connection between light and electromagnetic waves.
James Clark Maxwell