Quantum Mechanics Flashcards

To revise quantum mechanics

You may prefer our related Brainscape-certified flashcards:
1
Q

Define a photon

A

a packet (quanta) of energy

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

State the order of the electromagnetic spectrum, in terms of increasing frequency

A

Radiowaves

Microwaves

Infrared

Visible

Ultraviolet

X-rays

Gamma rays

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What do all electromagnetic waves have in common?

A
  1. They all travel at the speed of light in a vacuum
  2. They are transverse waves.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

How are electromagnetic waves emitted?

A

From a charged particle when it loses energy, this can happen when:

An electrom moves from a higher to a lower energy state

A fast moving electron is stopped e.g. x-rays

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

What is the relationship between photon energy and frequency?

A

Directly proportional

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

What is the relationship between photon energy and wavelength?

A

inversely proportional

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Define an eV

A

1 eV is the energy gained by an electron passing through a potential difference of 1 V

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Describe the photoelectric effect experiment?

A
  1. An insulating rod is given a negative charge.
  2. The negative charge is passed onto a zinc plate.
  3. The charge moves down onto the gold leaf
  4. The gold leaf repels and deflects away from the center
  5. Various light source are shone onto the zinc plate
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Describe the observations of the photoelectric experiment

A
  1. When UV light (high frequency) light is shown on the zinc plate the leaf falls immediately so electrons are being lost from the plate
  2. If a filament lamp (lower frequency) is used the electroscope doesn’t discharge (gold leaf doesn’t move)
  3. When very intense visible light is used, no electrons are emitted (gold leaf doesn’t move)
  4. If very low intensity UV light is used the discharge starts immediately
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Describe the conclusions of the photoelectric experiment

A
  1. There is a threshold frequency (minimum frequency) below which no photoelectrons are released
  2. The light is not interacting as a wave as enough energy would be eventually be transferred and photoelectrons would be released
  3. light is interacting as single photons** with the **surface electrons in an one to one interaction
  4. If the photons have enough energy/frequency (E=hf) then a photoelectron is released.
  5. If the frequency of the wave is to small it won’t have enough energy to release a photoelectron with a one to one interaction
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Define threshold frequency

A

Threshold frequency – minimum frequency of radiation needed to release photoelectrons

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Define work function

A

Work function – energy an electron must gain to be released from the metal

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Define intensity

A

The amount of energy arriving per second per m2

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

In the photoelectric effect what is the affect of increasing the intensity of visible light?

A

No effect, the frequency will be below the threshold frequency so no electrons will be released

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

In the photoelectric effect , if UV radiation is used with a constant frequency but the intensity is increased, what is the effect?

A

More photoelectrons are released each second - If intensity is increasing but each photon has a constant energy (E = hf) then more photons must be arrving and interacting with electrons per second.

Each photoelectron will have a constant kinetic energy as the energy of the incoming photons is constant (E=hf)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

In the photoelectric effect, if UV radiation of constant intensity was used but its frequency was increased what would be the effects?

A

Less electrons would be released each second - the same energy must be arriving per second but each photon has more energy - so less photons must be arriving per second

Each released photoelectron will have more kinetic energy as the incoming photons have more energy (E = hf)

17
Q

Describe the stopping potential experiment

A
  1. Photoelectrons are emitted from a metal surface.
  2. They then have to travel towards the negative terminal of a battery.
  3. This means they have to do work against the potential difference.
  4. The stopping potential is the p.d. needed to stop the fastest electrons with the maximum kinetic energy.
  5. The work done by the p.d. is equal to the initial energy of the electrons.
  6. W = VQ
18
Q

From a graph of kinetic energy against frequency what can be found out?

A

Gradient = h

x intercept = threshold frequency

y intercept = - work function

19
Q

Describe excitation

A

An electron can move up an energy level by gaining energy (e.g. via heating or collisions with other particles). This is called excitation.

20
Q

Describe how excitation happens via collision with electrons

A

Electrons collide with atom transfering some or all of its energy.

If the electron has more energy than the energy difference between the energy levels, then the eletron will take the excess energy away as kinetic energy.

If the electron has the same energy as the difference between energy levels then it will transfer all of its energy and the electron will stop.

If the electron has less energy than then difference between the energy levels then it will be deflected by the atom with no loss in kinetic energy or excitation.

21
Q

Describe excitation by using photons

A

Electrons in an atom absorb a photon and all of its energy. This can only happen if the energy of the photon is exactly equal to the energy the electron would need to gain to move to a higher energy level.

If the photons energy is smaller of larger than the difference between the two energy levels then it wont be absorbed.

22
Q

Describe relaxation

A

An electron can move down to a lower energy level by losing energy. This is done by releasing a photon. This is called relaxation.

23
Q

Define ionisation

A

If an electron gains enough energy it can escape the atom. This is called ionisation.

24
Q

Why do energy levels have negative values?

A
  1. For an electron that is bound to the atom, energy has to be added to release it.
  2. Work has to be done to move an electron to a higher energy level
  3. But we define an electron as just being ionized as having zero energy.
  4. So we say that the electron in an energy level has negative energy.
25
Q

Explain how fluorescent tubes work

A
  1. Fluorescent tubes contain mercury vapour across which a high p.d. is applied.
  2. The high voltage accelerates free electrons and ionise some mercury atoms
  3. The free electrons collide with electrons in the mercury atoms the electrons are excited to a higher energy level.
  4. When these electrons relax they lose high energy photons in the UV range.
  5. A phosphorous coating on the inside of the tube absorbs these photons, which excites the electrons to a higher energy level.
  6. These electrons then relax and release lower energy photons of visible light
26
Q

How is a line emission spectrum produced?

A

Given out by gas atoms which have been excited through discharge of electricity or by heating to high temps.

Seen as discrete lines as they contains only specific energies, frequencies and wavelengths The electrons in the atom can only orbit at certain distances (shells/levels) from the nucleus, i.e. the radius of the orbit is “quantized” An excited electrons will jump down (relax) to a lower energy level. In jumping down the electrons emit a photon of energy equal to the difference in the energy between the two levels. (E= hf)

27
Q

Explain why line spectra are seen as discrete lines

A

Line spectra are seen as discrete lines as they contains only specific energies, frequencies and wavelengths.

The electrons in the atom can only orbit at certain distances (shells/levels) from the nucleus, i.e. the radius of the orbit is “quantized”

An excited electrons will jump down (relax) to a lower energy level.

In jumping down the electrons emit a photon of energy equal to the difference in the energy between the two levels. (E= hf)

28
Q

What is a continuous spectrum?

A

A continuous spectrum is a spectrum in which all wavelengths/frequencies are present between certain limits.

It is given out by hot glowing objects. All wavelengths are present because the electrons are not bound to atoms and are free so they are not confined to specific energy levels.

29
Q

What is an absorption spectrum?

A

Caused by atoms of hot gas absorbing particular frequencies or wavelength as white light passes through. seen as continuous spectra with dark bands

30
Q

State some wave properties

A
  1. Refraction
  2. Diffraction
  3. Interference
  4. Polarisation
31
Q

State some particle properties

A
  1. Light travels in straight lines
  2. Photoelectric effect
  3. Carrying a charge/mass
  4. Deflection by an electric or magnetic field
32
Q

Describe an experiment that showed electrons to behave like a wave

A

Electron diffraction through graphite - Electrons fired from a cathode so they pass through a graphite target. A series of bright rings can be seen on a phosphorescent screen.

33
Q

State the evidence that electrons can act like waves

A

Electrons are being diffracted** as they pass through the graphite. Electrons are **constructively interfering** to produce bright rings. Electrons are **destructively interfering to produce dark rings. The same pattern build up with just one electron at a time.

34
Q

What is the condition required for noticeable diffraction?

A

For diffraction to be noticeable the wavelength must be similar to the size of the gap it is passing through

35
Q

Describe the two main methods that cause excitation

A
  1. Collision with electrons
  2. Absorbing a photon