Quantum Mechanics Flashcards

1
Q

wavefunction

A

the state of a system is fully described by a mathematical function Ψ,

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2
Q

Probability interpretation of Ψ (Born Interpretation)

A

consider a particle which can move only in the x direction

this particle is described by a wavefunction Ψ(x) - wavefunction only depends on x

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3
Q

assume that the wavefunction is normalized

A

the probability of finding the
particle somewhere along the x direction is 1

the wavefunction itself has no physical meaning
- it may, at any given point in space, be positive or negative, real or complex

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4
Q

observable

A

a measurable property such as bond length, dipole moment, kinetic energy

every observable B is represented by an operator
- all operators can be built from the operators for position and momentum.

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5
Q

operator

A
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6
Q

the Hamiltonian

A

The role of the operator is to operate on a wavefunction to yield information associated with the observable that the operator represents.

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7
Q

eigenvalue equation

A
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8
Q

The Schrödinger equation - for a particle moving in the x direction

A
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9
Q

an exact wavefunction

A

the eigenvalue E is an energy

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10
Q

orthogonal wavefunctions

A

Any two non-degenerate solutions (i.e. solutions of different energy) are orthogonal

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11
Q

orthonormal wavefunctions

A
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12
Q

expectation values

A

The expectation value of an operator B for a wavefunction Ψ is denoted < B > and is defined as:

  • dτ tells us that the integration is being performed over all space.
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13
Q

when a system is described by a wavefunction Ψ, the average value of the observable B in a series of measurements is equal to the expectation value of the corresponding operator Bˆ

when Ψ is an eigenfunction of Bˆ, determination of B always yields one result, b.
When Ψ is not an eigenfunction of Bˆ, a single measurement of B yields a single outcome which is one of the eigenvalues of Bˆ, and a large number of measurements will yield an average of the eigenvalues of Bˆ

A
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14
Q

the variation principle

A

for any trial wavefunction Ψtrial , the expectation value of the energy can never
be less than the true ground state energy E0

The expectation value of the energy is an average of the true energies of the system E0 , E1 , E2 …., and this can never be less than E0

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15
Q

harmonic oscillator

A

harmonic oscillations occur when a system experiences a restoring force proportional to the displacement from equilibrium, e.g. pendulums, vibrating springs.

consider a one-dimensional harmonic oscillator:

k , the constant of proportionality, is called the force constant.

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16
Q

solution for the harmonic oscillator
- determine value of α required for wavefunction Ψ0 to be eigenfunctions of Hamiltonion

A

we seek a wavefunction such that the total energy E is constant as it must be an eigenvalue to be an exact solution.

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17
Q

solution for the harmonic oscillator
- determine the eigenvalues of H operator acting on Ψ0

A
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18
Q

wavefunctions associated with harmonic oscillator

A

the energies have even spacing, ΔE = ℏω

  • If the force constant k increases, ω increases and hence so does ΔE
  • This will also be the case if the mass decreases
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19
Q

zero-point energy

A

the eigenvalue of the ground state E0 ≠ 0.

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20
Q

harmonic oscillator - applications in spectroscopy

A

potential between two atoms in a diatomic molecule can be represented schematically by the plot of V(x) against x

well is very steep for small x due to the large replusion between the nuclei

potential tends to zero at large x as the bond weakens then breaks

harmonic oscillator potential, shown by V^(2)(x) on the plot, is a good approximation to V(x) around the
equilibrium (most stable) internuclear separation xe, but clearly not away from the equilibrium region

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21
Q

Morse potential

A

simple harmonic oscillator is used as a first approximation, and is most accurate for the ground state energy (v = 0), the zero-point energy

Morse potential more realistic for diatomic molecules compared to simple harmonic oscillator

term containing χe in Ev equation: reduces energy from the harmonic oscillator value and becomes increasingly important as v becomes large
Thus the vibrational energy level separation is not constant as for the harmonic oscillator, but converges as v gets larger. The molecule dissociates as v →∞

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22
Q

particle on a ring

A

a particle of mass, m moving at a constant velocity, v around a circle of radius, r in the xy plane

The potential energy is constant - the Hamiltonian for this motion is just the kinetic energy part:

the particle is confined to move at a fixed radius - therefore use polar coordinates.

r is a constant, any term containing a derivative of r will vanish

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23
Q

the Shrodinger equation for particle on a ring - substituting the moment of inertia, I of the particle about the z axis

A
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24
Q

Normalisation constant for particle on a ring

A

N^2(2π) = 1

N = 1/ √2π

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25
Q

angular momentum for particle on a ring

A

The z component of the angular momentum of a particle moving at constant velocity in a circle, Lz , can have only certain values which are multiples of ℏ

The angular momentum is quantized.

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26
Q

Particle on a sphere – rotation in 3 dimensions

A

particle of mass, m which is free to move anywhere on the surface of a sphere, at a fixed distance, r from an origin

the potential energy is constant and can be neglected

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27
Q

the Shrodinger equation for particle on a sphere

A
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28
Q

solutions for particle on a sphere

A

energy is independent of ml and hence for every value of l there are (2l+1) states with the same energy (degenerate)

29
Q

the first nine spherical harmonics - ignoring their normalisation constants

30
Q

degenerate wavefunctions

A

any linear combination of them will have the exact same energy, and be a solution to the corresponding Schrödinger equation.

31
Q

rigid rotor – the rotation of diatomic molecules

A

consider a diatomic molecule AB
- The atoms rotate about the centre of mass
- the motion of the masses about the centre of mass is mathematically equivalent to the rotation of a single particle of reduced mass about a fixed point

distance between the fixed point and the particle is equal to the bond length r
- treat the rotation of a diatomic molecule as if it were the motion of a particle of mass μ on the surface of a sphere

32
Q

energies of the wavefunction for particles on a sphere

A

In rotational spectroscopy we normally use J as the symbol for the quantum number

33
Q

the hydrogen atom

A

consider general case of hydrogenic atoms - so solutions can be extended to He+ and Li2+

Coulomb’s law: gives the potential energy of the electron in the electrostatic
field generated by the nucleus

34
Q

atomic units

A

QM generally uses atomic units

in SI units a0 = 5.29177208x10-11 m.

35
Q

The Hamiltonian for H atom

A

the potential V is independent of the angles θ and φ

the part of the Hamiltonian that depends on these angles will be the same as for the rigid rotor.

The kinetic energy operator only differs in that r can now vary (r is no longer constant)

36
Q

The Schrodinger equation for H atom

A

expression for the energy is in atomic units
- atomic unit of energy is also called a hartree,
(1 Eh = 4.3597438 x 10-18 J = 27.211383 eV).

the energies depend only on the quantum number n
- This is true only for the H atom, or any other atomic ion with only one electron

37
Q

The Hamiltonian for the He atom

A

assume that the repulsion between the two electrons can be mathematically ignored and somehow absorbed into an effective potential (ignore 1/r12 term)

are thus assuming that the electrons move independently of one another
- assign each electron its own hydrogenic wavefunction

38
Q

wavefunction for He

39
Q

electron spin

40
Q

Pauli exclusion principle

A

No two electrons in an atom may have the same set of the four quantum numbers n, l, ml and ms

consider the effect on Ψ(1,2) of interchanging the two electrons,

i.e. Ψ(1,2) → Ψ(2,1)

electrons are indistinguishable and hence this process cannot affect the physical properties of the system

the probability distribution Ψ*Ψ must remain unchanged.
- For this to be true: either Ψ(1,2) = Ψ(2,1) or Ψ(1,2) = -Ψ(2,1)

the second condition is the correct restriction for electrons - therefore the more fundamental form of the Pauli exclusion principle:

the total wavefunction of a system must change sign when any two electrons are interchanged
- the total wavefunction must be antisymmetric

41
Q

the ground state of the He atoms

A

α - spin up
β - spin down

electrons are indistinguishable
- cannot say for sure that electron 1 has α spin and electron 2 has β spin (or vice versa)

when electrons have opposite spins, there must be equal probabilities of α(1)β(2) and α(2)β(1)
- which we can ensure by taking linear combinations of these spin arrangements

combine spin wavefunctions with spatial wavefunction for He atom

The spatial wavefunction is symmetric with respect to the interchange of the two electrons, and hence the spin wavefunction must be antisymmetric. Only the fourth spin function is antisymmetric

fourth wavefunction satisfies Pauli exclusion principle

42
Q

Slater’s determinant - the ground state of the He atoms - written in determinantal form

A

Each term in the determinant has a hydrogenic spatial orbital multiplied by a spin function, and is known as a spin-orbital

43
Q

excited states of the He atom

A

He electron configuration: 1s2

Excited states of He: promote electron from the 1s orbital to the 2s to yield the configuration 1s12s1

44
Q

energy of singlet and triplet states of He atom

A

there is a difference in energy between the singlet and triplet states of 2K where the exchange integral, K > 0, and hence the triplet state is the more stable

45
Q

Born-Oppenheimer approximation

A

the total wavefunction for a molecule can be approximated as: Ψmol = Ψnuc Ψelec

where Ψelec is determined from an electronic Hamiltonian (in atomic units)

i and j refer to the electrons, k and l to the nuclei

Thus, r_ik is the distance from electron i to nucleus k with charge Z_k

R_kl is the fixed internuclear distance.

46
Q

Linear Combination of Atomic Orbitals (LCAO)

47
Q

Linear Combinations of Molecular Orbitals

A

same approach for LCAO is taken for molecular wavefunctions.

the electronic wavefunction for a molecule with n electrons is written as the product of one-electron wavefunctions:

this is not actually a product wavefunction, but the leading diagonal of a Slater determinant

there will be as many molecular orbitals Ψi as there are atomic orbitals φk in the basis set.

48
Q

secular equations

A

consider a diatomic molecule with
- atomic orbital φ1 on atom 1
- atomic orbital φ2 on atom 2

separated by a fixed distance R

Consider also a trial wavefunction for the molecular orbitals (MOs): Ψtrial = c1φ1 + c2φ2

HOW DO WE DETERMINE c1 AND c2

49
Q

secular equations in matrix form

A

secular equations have non-trivial solutions only when the secular determinant equals zero:

50
Q

Two-orbital systems: Identical orbitals and zero overlap

A

φ1 and φ2 are identical
- the combination of any two identical atomic orbitals on adjacent atoms of the same type (e.g. in homonuclear diatomics or the π orbitals of ethene, where φ1 and φ2 are each 2pz orbitals on the C atoms)

φ1 and φ2 are assumed real - we can therefore replace the Coulomb resonance integrals with α and β respectively

51
Q

molecular orbital diagram formed from two identical atomic orbitals when we assume that there is no overlap i.e. S_12 = 0

A

the bonding orbital is stabilised by as much as the antibonding orbital is destabilised.

Coulomb integral, α
- the energy an electron would have in a molecule if it occupied either AO φ1 or φ2
- more negative then the energy electron would have if it occupied φ1 or φ2 in the isolated atoms - due to Coulomb attraction between electron and second nucleus

Resonance Integral,
- energy of interaction between φ1 and φ2 in the molecule
- normally negative
- typically about five times smaller than α for adjacent, identical orbitals

52
Q

normalise coefficients

53
Q

Two-orbital systems: Identical orbitals and non-zero overlap

A

anti-bonding orbital is destabilised by
more than the bonding orbital is stabilised

He2 is not stable
- two electrons in both the bonding and anti-bonding
orbital
- giving an energy of 2E+ + 2E- which is less
stable than the isolated atoms at all separations.

54
Q

Two-orbital systems: Different orbitals and zero overlap

A

in heteronuclear diatomics, φ1 and φ2 are not the same

55
Q

Two-orbital systems: Different orbitals and zero overlap - when φ1 and φ2 have very different energies

A

α1 and α2 will be very different from one another and δ^2&raquo_space; β^2

atomic orbitals will mix together strongly to form molecular orbitals only if

If two atomic orbitals have very different energies (and hence α1 and α2 are very different) then
they will not mix together strongly.

56
Q

Huckel Theory

A

In conjugated organic molecules such as ethene or benzene, the π orbitals usually have higher (i.e. less negative) energies than the σ orbitals
- are the most important in chemical reactions and spectroscopy.

Huckel theory: an approach to the electronic structure of conjugated molecules
- ignores the σ orbitals
(only using them to define the molecular geometry)
- determines the π MOs for systems with n conjugated carbon atoms

57
Q

general approach to Huckel theory

58
Q

approximations in Huckel theory

59
Q

Huckel theory - secular equations written in matrix notation

60
Q

Huckel theory - setting up the matrix

A

α - E along the leading diagonal
β along the off-diagonals when atom j is next to atom k
zero along the off-diagonals when atom j is not next to atom k

61
Q

Huckel theory - coefficients are normalised

62
Q

Huckel theory - total energy of molecule

A

There are n electrons for an uncharged molecule with n C atoms contributing to the π system and these can now be put in pairs into the MOs.

ni (the occupation number of the ith MO) takes the values 0, 1 or 2 (it is the number of electrons)

63
Q

Huckel theory example - the allyl radical

A

there are three 2p orbitals, one on each carbon atom, that can contribute to the π MOs
- π MOs are perpendicular to the molecular plane

there are three atomic orbitals therefore, there must be three π MOs

secular determinant must equal zero for non-trivial solutions

64
Q

Huckel theory example - the allyl radical: for each E value, the MO coefficients are found by substituting E back into the secular equations

65
Q

Huckel theory example - the allyl radical: MO diagram

66
Q

electron population on atom k (the π electron density)

A

since each atom k has a residual nuclear charge of +1. These sort of charge data are useful for determining the most likely position in a molecule for attack by an electrophile or nucleophile

67
Q

π bond order between atoms j and k