Quant-Technical Flashcards

1
Q

|3x – 7| = 5

A

3x – 7 = 5 or 3x – 7 = -5

3x = 12 or 3x = 2

x = 4 or x = 2/3

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2
Q

-1 < x < 9 as an absolute value inequality

A

The first step is to find the midpoint of the region: 4 is exactly halfway between -1 and 9.

Now the distances: 9 is a distance of 5 from 4, and so is -1.

So the distance from 4 (viz. |x – 4|) can’t equal 5, but it can be anything up to 5. Thus

|x – 4|< 5 is the absolute value inequality representation of the region -1 < x < 9

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3
Q

If x + |x| + y = 7 and x + |y| – y = 6 , then x + y =

A

Determine whether x is positive or negative, and whether y is positive or negative. This will help us simplify the initial equations.

To test whether y is positive or negative, we’ll first assume that y is positive. So we’ll plug in a positive number for y. We’ll use “pos” to represent that positive number:

x + |y| – y = 6

x + |pos| – (pos) = 6

We know that if we take the absolute value of a positive number, and subtract that same positive number from that, we get 0. So the terms |pos| and – (pos) cancel out, and we are left with:

x = 6

Now, to test whether this makes sense, let’s plug x=6 into our first equation:

x + |x|+ y = 7

6 + |6|+ y = 7

12 + y = 7

y = –5

So our result shows us that y is negative. But this is a contradiction, because before we assumed that y was positive. So this means that y cannot be positive; we can conclude that Y MUST BE NEGATIVE

Now let’s examine x. Let’s assume that x is a negative number, and see what happens when we plug this into our first equation. We’ll use “neg” to represent a negative number:

x + |x| + y = 7

(neg) + |neg| + y = 7

Here, the terms (neg) and |neg| will cancel out. This is because we are adding a negative number (neg) to the absolute value of that negative number, which is actually positive (because of the absolute value). The result of this is zero. So:

(neg) + |neg| + y = 7

y = 7

However, we earlier determined that y must be a negative number, so here we have a contradiction (since we found that y = 7, which is positive). So therefore, x cannot be negative. Hence we can conclude that X IS POSITIVE.

Now that we know this, we can simplify our equations.

Since x is positive, we know that |x| = x. (Keep in mind that if we take the absolute value of a positive number, the number stays the same). So the equation x + |x| + y = 7 can be simplified to x + x + y = 7, which is 2x + y = 7.

And since we know that y is negative, the equation x + |y| – y = 6 can be simplified to x – 2y = 6. (EXPLAINED BELOW)

Now we have a system of equations:

2x + y = 7

x – 2y = 6

We can plug this value of x into the first equation:

2x + y = 7

2(6 + 2y) + y = 7

12 + 4y + y = 7

12 + 5y = 7

5y = –5

y = –1

Now we can plug this value of y into x = 6 + 2y, to get x = 6 – 2, and x =4.

Therefore x + y = 4 - 1 = 3

**FAQ: why x + |y| – y = 6 doesn’t become x + 2y = 6?

We have a variable y that must represent a negative number:

y = neg

Let’s now replace “y” with “neg” in our equation:

x + |y| – y = 6

x + |neg| – neg = 6

The absolute value of that negative number must result in the positive version of that number. Likewise, subtracting that negative number must result in the positive version of that number. So we end up with the following where “pos” represents the positive version of that number:

x + pos + pos = 6

x + 2 × pos = 6

but y cannot be pos so we can’t sub in y to this above quation, but to make it into a negative multiply by -1 so it equals x + 2 x neg = 6 -> x -2neg = 6 -> x-2y=6

https://gmat.magoosh.com/questions/131/a/413137129#text_explanation

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4
Q

What does it mean to “Express y in terms of x”?

A

The command “Express y in terms of x” means: get y alone, all by itself, on one side of the equation, and the other side should be some algebraic expression involving x.

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5
Q

Can you divide 5x=x^2 by x?

A

No. You cannot divide by a variable if the variable could equal zero. Instead, you have to group on one side and factor out the x:
5x= x2
0= x2-5x=x(x-5)
x=0 or x=5

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6
Q

Is this true or false?

root(P+Q) = root(P) + root(Q)

A

False, we cannot separate radicals by addition

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7
Q

True of False

Given that P >0 and Q>0

root(P x Q) = root(P) x root(Q)

A

True. We can separate radicals by multiplication.

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8
Q

True or False

If x^3 > 0, then x>0

A

True.

The cube of a number has the same sign (negative to negative, and positive to positive), so if the cube of x is positive, then x has to be positive.

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9
Q

The ratio 3 to 5 can be written in what two other ways?

A

3:5 or 3/5

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10
Q

True of False

1/(A/B) = (1/A) / (1/B)

A

True. Both sides of the equation simplify to just B/A.

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11
Q

a 50% increase, followed by a 50% decrease, is equivalent to what single percent change overall?

A

25% decrease

ex: start at 100
100+50% increase = 150

150-50% decrease=75

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12
Q

What is the multiplier for a 30% decrease?

A

Change 30% to a decimal, 0.30, and subtract this from 1.

1 – 0.30 = 0.70

The decimal 0.70 is the multiplier for a 30% decrease. We can decrease anything by 30% when we multiply it by 0.70.

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13
Q

If 120 Gadgets cost $44, then, at the same price, 180 gadgets would cost what?

A

180/120 = x/44
(44*180)/120=x

simplify

(44*18)/12=x

(44*3)/2=x

(22*3)=x

66=x

ANOTHER WAY OF DOING IT

180 is 50% greater than 120, so the cost should be 50% greater than $44.

half of $44 is $22, and 44 + 22 = $66.

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14
Q

What is the formula for percent change (percent increase or percent decrease)?

A

(new-original)/original x100%

=change/original x100%

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15
Q

Whats the difference between a ratio and a proportion?

A

A ratio is a single fraction. A proportion is an equation of the form: fraction equal fraction.

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16
Q

If |x| < 20 and |x – 8| > |x + 4|, which of the following expresses the allowable range for x?

(A) –12 < x < 12

(B) –20 < x < 2

(C) –20 < x < –12 and 12 < x < 20

(D) –20 < x < –8 and 4 < x < 20

(E) –20 < x < –4 and 8 < x < 20

https://magoosh.com/gmat/absolute-value-inequalities/

A

|x – 8| > |x + 4|. All this says is that we are looking for points such that the distance to x = 8 is greater than the distance from x = –4; in other words, we want all the points that are closer to x = –4 and farther from x = 8.

The midpoint between x = –4 and x = 8 is the point x = 2. This point is not included because it’s equidistant from both points, but everything to the left of this point on the number line is closer to x = –4 than it is to x = 8.

Combine that with the first inequality, |x| < 20, which in the negative realm means that x must be greater than –20. Thus, the allowed region is –20 < x < 2.

https://magoosh.com/gmat/absolute-value-inequalities/

B

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17
Q

What is a prime number? Is 1 a prime number?

A

a whole number divisible by only 1 and itself.

1 is not a prime since it only has one divisor

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18
Q

The axis of symmetry of y=ax^2 + bx + c is?

A

x = -b / 2a

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19
Q

what are the prime numbers less than 100?

What is the easy way of memorizing this?

A
2, 3,5,7,
11,    13,  17, 19,
       23,      29,
31,         37,
41,   43, 47
        53,     59
61,          67
71,   73,       79
        83       89
               97

HOW TO MEMORIZE
1. Write down the first three rows as done above

  1. Continue pattern with the 23,29 by adding 30 twice, thus 53,59 83,89
  2. Continue pattern with 11 and 17 by writing 31,37 61,67 and 97 (NEED TO REMEMBER NO 91)
  3. Continue pattern with 11, 13,17 by writing 41,43,47 and 71,73 and then write 79 instead of 77
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20
Q

What is the prime factorization of 75 (using exponential notation)?

A

Step 1. Find the multiplication factor that uses the lowest prime number that goes into 75
3 * 25 = 75

Step 2. Break down that equation further by doing the same as step 1 on the non-prime number until can’t anymore

 3 * 25 = 75
 3 * (5*5) = 75

Step 3. Convert to exponential notation

ANSWER = 3 x (5^2)

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21
Q

What is the prime factorization of 36?

A

Step 1. Find the multiplication factor that uses the lowest prime number that goes into 36
2 * 18

Step 2. Break down that equation further by doing the same as step 1 on the non-prime number until can’t anymore
2 * 18
2 * (29)
2 * (2
(3*3))

Step 3. Convert to exponential notation

ANSWER= 2^2 * 3^2

22
Q

What is the prime factorization of 30 (EXPONENTIAL NOTATION)?

A

Step 1. Find the multiplication factor that uses the lowest prime number that goes into 30
2 * 15

Step 2. Break down that equation further by doing the same as step 1 on the non-prime number until can’t anymore
2 * (3*5)

Step 3. Convert to exponential notation
ANSWER= 235

23
Q

What is the prime factorization of 4200 (EXPONENTIAL NOTATION)?

A

Step 1. Find the multiplication factor that uses the lowest prime number that goes into 4200

 2 * 2100
Step 2. Break down that equation further by doing the same as step 1 on the non-prime number until can't anymore
    2 * (2*1050)
    2 * (2*(2*525)
    2 * (2*(2*(5*105)))
    2 * (2*(2*(5*(5*21)))
    2 * (2*(2*(5*(5*(3*7)))

Step 3. Convert to exponential notation

2^3 * 5^2 * 3 * 7

24
Q

How many factors does 450 have?

A

Step 1. Find the multiplication factor that uses the lowest prime number that goes into 450
450 = 2*225

Step 2. Break down that equation further by doing the same as step 1 on the non-prime number until can't anymore
      450 = 2*225
      450 = 2*(5*45)
      450 = 2*(5*(5*9))
      450 = 2*(5*(5*(3*3)))

Step 3. Convert to exponential notation
450 = 2 * 5^2 * 3*2

Step 4. add 1 to each power and multiply the totals

(1+1)(2+1)(2+1)
(2)(3)(3)
18

ANSWER=450 has 18 factors

25
Q

Find the sum of all factors of 450

A

Step 1. Find the multiplication factor that uses the lowest prime number that goes into 450
450 = 2*225

Step 2. Break down that equation further by doing the same as step 1 on the non-prime number until can't anymore
      450 = 2*225
      450 = 2*(5*45)
      450 = 2*(5*(5*9))
      450 = 2*(5*(5*(3*3)))

Step 3. Convert to exponential notation
450 = 2 * 5^2 * 3*2

Step 4. Plug into equation

[((a^(p+1))-1)((b^(q+1))-1)….. ] / [(a-1)(b-1)….]

= [ ((2^(1+1))-1)((5^(2+1))-1)((3^(2+1))-1) ] / [ (2-1)(5-1)(3-1) ]

= ((2^2)-1)((5^3)-1)((3^3)-1) / (142)

= (4-1)*(125-1)*(27-1) / 8
= 3*124*26 / 8
=3*(1240+1240+(248+248+248)) / 8
=3*(2480+496+248) / 8
=3*(2480+ 744) / 8
=3*(3224) / 8
=9672/8

ANSWER=1209

26
Q

What is the greatest common factor of 105 and 30?

A

Step One: Figure out the prime factors of both

105 = 521=5(73)
30=2
15=2(53)

Step two: see which factors are common between both numbers

Common factors = 3 & 5

Step 3: If theres more than 1, multiply them together

Since there are two common factors, the greatest will be the multiplication of the two.
Therefore GCF = 3*5 = 15

27
Q

What is the LCM(24,300)?

A

Step One: Figure out the prime factors of both

Prime factorization of 24 = 2 × 2 × 2 × 3
Prime factorization of 300 = 2 × 2 × 3 × 5 × 5

Step two: multiply all the factors by the number of times they appear most often

2 x 2 x 2 x 3 x 5 x5 = 600

(2 appears 2 times in the prime factorization of 300, however it shows up 3 times in the prime factorization of 24. Therefore you multiply by 2 three times.)

ANSWER = 600

28
Q

True or false, the number of distinct factors of a perfect square is ALWAYS ODD

A

True

29
Q

True or false, the sum of distinct factors of a perfect square are ALWAYS EVEN

A

False

30
Q

True or false, a perfect square ALWAYS has an ODD number of Odd-factors, and EVEN number of even-factors

A

True

31
Q

How do you tell if a number is divisible by 7?

A

Take the last digit, double it, and subtract it from the rest of the number, if the answer is divisible by 7
(including 0), then the number is divisible by 7.

32
Q

How do you tell if a number is divisible by 6?

A

If the number is divisible by both 3 and 2, it is also divisible by 6.

33
Q

How do you tell if a number is divisible by 9?

A

If the sum of the digits is divisible by 9, so is the number.

34
Q

How do you tell if a number is divisible by 11?

A

If you sum every second digit and then subtract all other digits and the answer is: 0, or is divisible by 11, then
the number is divisible by 11.

35
Q

Is 9,488,699 divisible by 11?

A

Yes, because:

Step 1: Sum every second digit

4+8+9=21

Step 2: Subtract the sum of the other digits

21-(9+8+6+9)= -11

Step 3: determine if the solution is 0 or divisible by 11

Since -11 is divisible by 11, 9,488,699 IS DIVISIBLE BY 11

36
Q

How do you tell if a number is divisible by 12?

A

If the number is divisible by both 3 and 4, it is also divisible by 12.

37
Q

How many zeros are in the end (after which no other digits follow) of 32! ?

A

Step 1: Enter 32 into equation: n/5 + n/5^2 + ….. (you go until 5^k

38
Q

What is the power of 2 in 25!

?

A

Step 1: Enter the power of # and factorial into the equation

n/p+n/p^2…. until P^t

39
Q

How many powers of 900 are in 50! ?

A

Step 1: Determine prime factorization of 900

900 = 2*450
900 = 2*(2*225)
900 = 2*(2*(5*45)
900 = 2*(2*(5*(5*9)
900 = 2*(2*(5*(5*(3*3))))

900 = 2^2 * 5^2 * 3*2

Step 2: Find the power of 2 in 50! using equation
n/p+n/p^2…. until P^t

40
Q

What is the sum of {-3, -2, -1, 0, 1,2 (use the method, don’t just calc)

A

Step 1. calculate the mean

mean = (-3+2)/2 = -(1/2)

Step 2. Multiple by the number of integers in the set

-(1/2) * 6 = -3

41
Q

True or False

Any set of n consecutive integers will contain exactly one number divisible by n

A

True

42
Q

True or False

if we have an even number of consecutive integers, the evens and odds have to be evenly split.

A

True

43
Q

True or False

If n is an odd number, then the sum of n consecutive integers isn’t divisible by n.

A

False, if n is an odd number the sum IS divisible by n

ex: 9,10,11

9+11/2 = 20/2 = 10
10*3 = 30 ; 30 is divisible by 3
44
Q

True or False

If n is even, the sum of consecutive integers is never divisible by n.

A

True

ex: 9,10,11,12

9+12/2=21/2

21/2 * 4 = 42; not divisible by 4

45
Q

True or False

THe product of n consecutive integers is always divisbile by n!

A

True

Given n=4 consecutive integers: {3,4,5,6} . The product of 345*6 is 360, which is divisible by 4!=24.

46
Q

If N = 255 is the lowest of a set of 23 consecutive multiples of 15, what is the range of this set?

(A) 315
(B) 330
(C) 345
(D) 360
(E) 375
A

When we have a set of consecutive integers or consecutive multiples of the number, the range depends only on the size of the set, how many members, not where on the number line the set starts or ends.

(For example, any seven consecutive integers will have a range of 6, whether it’s 1 through 7 or 51 through 57. Thus, we can ignore the starting number, 255, which is just there to confuse us. We can pick any more convenient starting value.)

Let’s start at a1 = 15 = 151. Then a2 = 152 = 30, and a3 = 153 = 45. Continuing in this pattern, the last number would be a23 = 1523. Don’t multiply that yet. The range would be highest minus the lowest:

range = (a23) – (a1) = 1523 – 151 = 15(23 – 1) = 1522

Now, use the doubling & halving trick. Half of 22 is 11, and twice 15 is 30, so

1522 = 3011 = 330

THEREFORE B

47
Q

For a set of consecutive integers, or for any set of evenly spaced numbers, is the mean and the median equal?

What if its an odd number in the list of consecutive numbers?

A

Yes

If odd, then the mean and median do not equal. The median would be the middle number This means that its NOT an integer

48
Q

Set N is a series of six consecutive odd integers. In set N, the lowest value is n^2 and the highest value is 7n. What is the median of the set N?

(A) 5
(B) 10
(C) 25
(D) 30
(E) 35
A

We know that odd integers are spaced two apart: if we have one odd integer, we can add 2 to get the next one. Starting from the given expression for the first member of the set, we can say:

first member = n^2
second = n^2 + 2
third= n^2 + 4
fourth = n^2 + 6
fifth = n^2 + 8
sixth = n^2 + 10

since answer says highest value in this set of 6 is 7n, we can equate

n^2 + 10 = 7n
(n-2)*(n-5) = 0

therefore n=2 or n=5

if n=2, then first member would be 4 which is even therefore incorrect. So n must be 5

therefore by subbing into the n equations above we get that the set is:
[25,27,29,31,33,35]

median thus is 30

ANSWER = D

49
Q

Admit Master: 1205^2 - 1195^2 = ?

(A) 10
(B) 100
(C) 24,000
(D) 1,428,025
(E) 1,452,025
A

C

2 strategies you can use:
(1) Quadratic
   (X+Y)(X-Y)=(X-Y)^2
   (1205+1195)(1205-1195)
   (2400)(10)
    24,000

(2) units digit strategy
1205^2 has a units digit of 5 always
1195^2 has a units digit of 5 always

5-5=0

Therefore units digit of solution must be 0, 10 and 100 don't make sense considering the size of the numbers therefore C must be the right answer
50
Q

what is the percent change formula?

A

old - new / old

51
Q

What is the units digit pattern length in exponents for digits from 0-9?

A
0 = 1
1 = 1
2 = 4
3 = 4
4 = 2
5 = 1
6 = 1
7 = 4
8 = 4
9 = 2