Quant Mixed Practice (Can Try Without Paper) Flashcards
What is the formula for counting the number of possible Pairs, from a group of N people/teams/etc? (We could be counting # of handshakes, games between teams, etc)
What do we know about the median and average of an evenly spaced set?
What is the formula for the sum of an evenly spaced set?
Median and Average are the same!
Sum = Number of values * Average Value
= N * (First + Last) / 2
What is the formula for the number of multiples of a number in a certain range?
If 10 < x < 100, for how many values of x is x/3 an integer?
(Last - First) / Increment + 1
x/3 is an integer is another way of saying “multiples of 3”
(Last - First) / Increment + 1
First is 12. Last is 99. Increment is 3.
(99 - 12) / 3 + 1 = 87/3 + 1 = 30
What is the average of x and y?
(1) The average of 2x and y is 8
(2) The average of x and 3y is 10
C- Together
Combo Question: If we know (x + y), it’s sufficient.
We have 2 unique equations, so we can solve for both variables.
DON’T ACTUALLY CALCULATE!
What is the average of x and y?
(1) The average of 4x and 4y is 8
(2) The average of x and 3y is 10
A- (1) Alone
Combo Question: If we know (x + y), it’s sufficient.
If one equation is a multiple of the combo, (or can be manipulated to isolate the combo), it’s sufficient:
(1): (4x + 4y) / 2 = 8
2x + 2y = 4
Divide by 2: x + y = 2
We don’t need to write out the equations above, if we are looking for a multiple of the combo and notice it.
What is the average of x and y?
(1) The average of 2x and 6y is 20
(2) The average of x and 3y is 10
E - Not Sufficient
Combo Question: If we know (x + y), it’s sufficient.
If we have 2 unique equations, we can solve for both variables.
But we need to check that equations are unique. Also check that they’re not a multiple of the combo.
(1) (2x + 6y) / 2 = 20
Divide by 2 on both sides:
(x+3y) / 2 = 10 –> (1) and (2) are the same equation, not unique!
What is 2x - 3y ?
(1) 4x - 6y = 8
(2) -9y + 6x = 12
D- Each Statement Alone
Check if the statements can be manipulated to isolate the combo “2x - 3y”:
(1) 4x - 6y = 8
Divide by 2: 2x - 3y = 4 –> Sufficient
(2) -9y + 6x = 12
Divide by 3: -3y + 2x = 4
Order of addition is reversed, this is same as 2x - 3y = 4 –> Sufficient
At a fish market, 1/4 are cod and 1/6 are salmon. How many of the fish are cod?
(1) There are 108 salmon.
(2) There are 3 cod for every 2 salmon.
A –> (1) Alone
F = Total Fish
Rephrase: C = 1/4 F, S = 1/6 F, C =?
We have 2 unique equations, 3 variables. With 1 more unique equation we can solve.
(1) S = 108 –> Sufficient DON’T CALCULATE!
(2) Insufficent. Trap–> not unique, same info as prompt! We already have the ratio of cod to salmon:
(1/4) / (1/6) = (3/12) / (2/12) = 3/2
What is the most important way to reduce careless errors?
READING– Double check what it’s asking for!
Examples:
“Increasing” vs “Decreasing” order
“Shaded” vs “Unshaded” area
Solving for X, but question asks for Y
Before you hit “Confirm”, that can be a good cue to check that you answered the right question.
Also, read the constraints carefully!
Example: “If x is a POSITIVE integer,…”
1) Multiply the powers
2) Order of operations requires doing the 32 first.
xy < xz
Is y < z?
Yes, if x is positive.
No, if x is negative.
Remember, with inequalities, we flip the sign if we multiply or divide by a negative number.
Is the average of the following greater than 50?
40, 45, 45, 50, 50, 52, 57, 58
For speed, use the over/under method– find the total difference less than 50, and compare to the total difference greater than 50.
Under: 40, 45, 45 –> 10 + 5 + 5 = 20 under
Over: 52, 57, 58 –> 2 + 7 + 8 = 17 over
More under than over –> NO, average is less than 50.
What is the formula for finding the midpoint of a line between 2 points?
(Average of the x values, Average of the y values)
For what values of x is x2 < x ?
Drawing / Visualizing the number line can be helpful!
If x is negative, x2 is positive, so x2 is greater.
If x is > 1, x2 is greater
If 0 < x < 1, x2 is LESS than x
For what values of x is x3 < x2
If x < 1, x3 is less than x2
If x is negative, x3 is negative & x2 is positive
If x is between 0 and 1, x3 will be less than x2, because multiplying by x each time makes it smaller