Qualitative inorganic analysis Flashcards

1
Q

Hydroxides trend down group 2

A

Solubility increases down the grouo

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2
Q

Carbonates trend down group 2

A

No trend

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3
Q

Sulphates trend down group 2

A

Solubility decreases down group 2

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4
Q

Test to identify ammonium

A

NaOH, gently heat, hold damp red litmus over
Production of ammonia gas, litmus turns blue

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5
Q

Test to identify carbonate

A

HCl/H2SO4, test gas with calcium hydroxide solution (limewater)
Effervescence, CO2 gas produced, limewater turns cloudy

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6
Q

Test to identify sulfate

A

HCl then barium chloride
Production of white precipitate

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7
Q

Test to identify chloride (aq)

A

Nitric acid, then silver nitrate then add dilute ammonia solution
Production of white precipitate, precipitate dissolves

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8
Q

Test to identify chloride (solid)

A

Add concentrated H2SO4
Production of steamy fumes of HCl

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9
Q

Test to identify bromide (aq)

A

Nitric acid, then silver nitrate then add concentrated ammonia solution
Production of cream precipitate and precipitate dissolves

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10
Q

Test to identify bromide (solid)

A

Add concentrated H2SO4
Production of steamy fumes HBr, and red/brown Br2, and pungent smelling SO2

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11
Q

Test to identify iodide (aq)

A

Nitric acid then silver nitrate then concentrated ammonia solution
Production of pale yellow precipitate and no visible change

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12
Q

Test to identify iodide (solid)

A

Add concentrated H2SO4
Production of steamy fumes of HI, H2S (smells of rotten eggs), black sold iodine and sometimes yellow sold sulfur

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13
Q

Test to identify thiosulphate ion

A

Add sulphuric/hydrochloric acid
Yellow precipitate forms

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14
Q

Test to identify lead (II)

A

Add potassium iodide solution
Bright yellow/canary yellow ppt formed

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15
Q

Addition of OH- and then excess OH- to [Cu(H2O)6]2+

A

Blue precipitate
No visible change

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16
Q

Addition of OH- and then excess OH- to [Fe(H2O)6]2+

A

Green precipitate
No is visible change

17
Q

Addition of OH- and then excess OH- to [Cr(H2O)6]3+

A

Grey precipitate
Precipitate dissolves forming a green solution

18
Q

How do we go from gdm^-3 to moldm^-3?

A

To moldm^-3 = multiply by Mr
The other way is divide

19
Q

Factors to consider when using a method, apart from cost

A

Rate of reaction
Atom economy
Temperature
Catalysts
Formation of side products

20
Q

Why can’t the molar % of each compound be used to find the percentage by mass of each component if the relative molecular mass of each component differs?

A

If relative molecular masses are different, the number of moles present in the chromatogram is not directly related to the mass of each component