QP2 Flashcards
(178 cards)
Nucleus of the atom diameter
approx. 10^-14m
Electrons orbit the nucleus at a distance of
approx. 10^-10m
The electrons and the nucleus should have been drawn to each other due to them being opposite charges. What did Rutherford suggest to this
Rutherford suggested that the electrons orbited the nucleus, but in doing so they should have lost energy and slowly circled down into the nucleus.
What was a consequence of Rutherford’s model of the atom
That as the electrons orbited down, their angular speeds would change continuously. However, observed spectra consisted of discrete energy lines, which disagreed with Rutherford’s suggestion.
What was Bohr’s solution for the model of the atom?
Bohr suggested stable orbits, meaning electrons would orbit the nucleus at a fixed distance and would not radiate energy.
Bohr’s model of the atom
Bohr’s model stated that there was a definite energy associated with each available stable orbit, and an electron only emits energy if it moves from one orbit to another.
What is the energy emitted with an electron moving from one orbit to another?
The energy emitted in such a transition is in the form of a photon, and the energy of that photon is given by the equation: E = hf = E_initial - E_final
What is the angular momentum of an electron?
The angular momentum of the electron is a multiple of ℏ, i.e its quantised.
We know: L = mvr = nℏ.
Where each value of n (1, 2, 3… ) corresponds to a valid orbit of radius r_n and corresponding velocity v_n.
Principle Quantum Number definition
The Principle Quantum Number is the value of n for each orbit.
Hydrogen atom composition
The hydrogen atom is the simplest in the periodic table. With one electron orbiting around a nucleus containing one proton.
Force for an electron in a given orbit (for Hydrogen Atom)
For the radius to remain constant in the Bohr model, the force must provide exactly the radial motion force. So, for the hydrogen atom, where both charges involved carry the same magnitude of charge e…
F = mv^2 / r = 1/4pƐ . e^2/r^2
Kinetic Energy for an electron in a given orbit
Kn = 0/5mv^2 = 1/Ɛ^2 . me^4 / 8n^2h^2
Potential Energy for an electron in a given orbit
Un = -1/4pƐ . e^2/r = -1/Ɛ^2 . me^4 / 4n^2h^2
The total Energy for an electron in a given orbit
En = Kn + Un = -1/Ɛ^2 . me^4 / 8n^2h^2
What do we apply the Schrodinger equation for?
As Bohr models isn’t perfect, we apply the Schrodinger equation to find the wave functions for states with definite energy values for the hydrogen atom.
Reduced Mass
The electron does not orbit the proton, they both orbit their common centre of mass. Thus, we use the reduced mass, which is when you have two masses orbiting each other, then the reduced mass is given by:
m_r = m1m2 / (m1+ m2)
The Schrodinger equation for the hydrogen atom solutions:
The solutions are obtained by separating the variables involved. This means we express the wave function as a product of three function, one associated with each of the coordinates: y(r,q,f) = R(r)Q(q)F(f)
Boundary equation for the Schrodinger equation for the hydrogen atom.
-R(r) tends to zero as r increases: this is because we are dealing with bound states that are close to the nucleus of the atom.
-F(f) must be periodic, i.e. it must repeat every 360 degrees or 2p radians: for example, (r,q,f) and (r,q,f + 2p) describe the same point, so F(f + 2p) = F(f). Also, the solutions to the functions must be finite – i.e. cannot take zero or infinity as solutions.
Solving the boundary conditions produces a relation for the energy levels as follows:
En = - 1/(4pƐ_o)^2 . me^4 / 2n^2h^2 = -13.60 eV / n^2
Where n is the principle quantum number of the energy level En. The negative sign indicates that the electrons are in bound states, as you need to provide a positive energy to remove the electron.
Angular momentum formula
L = ( l( l+1) )^0.5
Orbital angular momentum quantum number (l)
Given by: l = 0, 1, 2, … , n - 1
There are n different possible values of …
L for the nth energy level. The Bohr model said there was one value: Ln = nℏ
Z - component of angular momentum is given by:
Lz = mlℏ
Orbital magnetic quantum number
ml also called the orbital angular momentum projection quantum number. It can take values m = 0, ±1, ±2, … , ±l.