PZT, Bandwidth, Q Factor, Frequency Flashcards
Curie temperature
365 C or 680 F
A PZT heated past Curie point will be?
depolarized
Sterilization
complete destruction of all living microorganisms by heat, chemical agents, or radiation
Disinfection
reduce or eliminate infectious organisms
The active element is equal to ____ the wavelength
half
The matching layer has an impedence between the impedences of?
PZT and skin
What is the purpose of the matching layer?
Reduce reflection; increase transmission
The matching layer is equal to _____ the wavelength
1/4
Order of impedences in decreasing order
PZT > matching layer > gel > skin
______ pulses create better images
Short
Bandwidth
Range of frequencies between highest and lowest
Imaging transducers have a ____ bandwidth
wide
Imaging transducers have a _____ Q factor
low
Equation for Q factor
operating frequency/bandwidth
The main frequency is determined by?
thickness of the PZT and speed of sound in the PZT
Equation for operating frequency
prop speed/2xthickness
Thickness of the PZT and frequency are _______ related
inversely
Prop speed of the PZT and frequency are ______ related
directly