Pure Year 1 Flashcards
How do you get from e to ln(x)
e^ln(x)=x
a^x x a^y
a^(x+y)
(a^x)^y
a^xy
(a^x)/(a^y)
a^(x-y)
(ab)^x
a^x x b^x
a^-x
1/a^x
(a/b)^-x
(b/a)^x = b^x/a^x
a^(p/q)
(qroota)^p
a^0
1
root ab =
roota x rootb
root a/b =
roota/rootb
Coordinate geometry length
root [(y2-y1)²+(x2-x1)²]
Coordinate geometry gradient
(y2-y1)/(x2-x1)
Coordinate geometry midpoint
(x1+x2)/2 , (y1+y2)/2
Perpendicular
m1xm2=-1
Perpendicular bisector
A line that passes through the midpoint of two points and is 90° to the original line
Linear modelling
Y=ax+b
Why may a linear model not be suitable
May not account for other factors (named)
Why may a linear model be suitable if drawn on a graph
The data/points lie close to a straight line
Interpret the meaning of a and b in y=ax+b
a= the increase in y as x increases by
The value of (named y) increases/decreases per (x)
Completed square form
y = a(x-b)^2 + c