Pulmonary Physiology Flashcards

1
Q

Define lung volumes and capacities.

A

• Tidal volume (TV) = Volume of gas inspired and passively expired with normal breathing
• Expiratory reserve volume (ERV) = Volume of gas that can be maximally exhaled from rest
• Residual volume (RV) = Volume of gas remaining in the lung after maximal exhalation
• Functional residual capacity (FRC) = ERV + RV
• Inspiratory reserve volume (IRV) = Volume of gas that can be maximally inhaled above a TV
• Inspiratory capacity (IC) = IRV + TV
• Vital capacity (VC) = IRV + TV + ERV
• Total lung capacity (TLC) = IRV + TV + ERV + RV
(Fig. 6.1).

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2
Q

Describe the mechanics of respiration.

A

The combination of surface tension of water within the alveoli and the intrinsic elastic properties of the lung create a force (Flung) favoring collapse, whereas the chest wall force (Fchest) favors expansion. These two forces directly oppose one another, creating a spring-like physiology, opposing any deviation in lung volume above or below FRC. For example, following a forced inhaled volume above FRC, the recoil force of the lung (Flung) is greater than the expansion force of the chest wall (Fchest), facilitating a passive return to FRC. Likewise, following a forced exhaled volume below FRC, Fchest is greater in magnitude than Flung, causing a passive return to FRC.

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3
Q

What is FRC? What factors affect it?

A

FRC results when the opposing forces of the expanding chest wall and the recoil forces of the lung are equal. In other words, lung volume is at FRC when Fchest + Flung = 0.

The average FRC for a 70-kg, 5’10” male in the supine position around 2.5 L.

FRC is increased by:
• Body size (increases with height)
• Age (increases slightly with age)
• Asthma and chronic obstructive pulmonary disease (COPD)
FRC is decreased by:
• Female sex (females have a 10% decrease in FRC compared with males)
• Muscle relaxation (anesthetic agents and neuromuscular blocking agents decrease diaphragmatic muscle tone
and other accessory muscles of respiration)
• Posture (FRC is greatest in standing >sitting >prone >lateral >supine)
• Decreased chest wall compliance (e.g., obesity, thoracic burns, kyphoscoliosis, abdominal compartment
syndrome, ascites, laparoscopy)
• Decreased lung compliance (e.g., interstitial lung disease, acute respiratory distress syndrome [ARDS])

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4
Q

How long will it take for an apneic patient to develop hypoxemia following induction of anesthesia?

A

In a healthy, 70-kg, 5’10 (body mass index [BMI] 22), male preoxygenated (or denitrogenated) to an end-tidal O2 =100%, it will take approximately 10 minutes. At rest (i.e., a metabolic equivalent of 1), the O2 consumption
(3.5 mL/kg/min) for a 70-kg adult male is approximately 250 mL/min. Following induction in the supine position, this patient’s lung volume will equal FRC, which is approximately 2.5 L. Assuming this lung volume contains 100% O2, it will take 2500 mL O2/(250 mL O2/min) = 10 minutes.

However, the earlier is under ideal conditions for a healthy, nonobese patient, assuming an FRC volume equal to 100% oxygen.

Realistically, preoxygenation would yield a more commonly obtained end-tidal O2 of approximately 80% (not 100%), which will decrease the effective volume of O2 in the FRC by 20%. Also muscle relaxation caused by either anesthetic agents or paralytics will reduce FRC by 20%. Therefore the effective FRC volume containing oxygen is 2500 mL O2 x 80% x 80% = 1600 mL O2, yielding 6.4 minutes before the onset of hypoxemia.

Further, given the high prevalence of obesity and its effects on reducing FRC (decreases outward Fchest) and increasing O2 consumption (increased body mass), the time to hypoxemia can be severely reduced in the general population. Assume the aforementioned patient is 30-kg overweight and now weighs 100 kg (BMI 32). Because obesity decreases FRC by approximately 30 mL/kg for each kg above normal body weight, his effective O2 volume in FRC, although apneic, will be (2500 mL – 900 mL) x 80% x 80% = 1024 mL O2 and his O2 consumption will
increase to 350 mL O2/min. Therefore time to hypoxemia will be 1024 mL O2 /(350 mL O2/min) = 2.9 minutes. This is a more realistic time to hypoxemia for a large percentage of patients who are obese (BMI 32) but otherwise healthy.

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5
Q

What is closing capacity and what factors affect it? What is the relationship between closing capacity and FRC?

A

Closing capacity (CC) is the lung volume at which small, noncartilaginous airways begin to close, resulting in atelectasis and subsequent hypoxemia. It is calculated by the following equation:

Closing capacity = Closing volume + RV

In a young, healthy patient, CC is approximately equal to RV. The clinical significance of this is that having a closing volume at RV effectively provides a large physiological oxygen reserve, that is, atelectasis will not occur at FRC. With age, CC increases. At approximately 45 years old, CC equals FRC when supine and at 65 years of age, equals FRC when standing. The end result is a greater likelihood of resting hypoxemia in older patients because of atelectasis.

Although FRC is dependent on position and only slightly correlated with aging, CC is independent of position and increases with aging. CC is thought to be an independent pathological process responsible for decreased pulmonary reserve and hypoxemia in the elderly patient.

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6
Q

Discuss the factors that affect resistance to gas flow. How is laminar versus turbulent flow different?

A

Resistance to gas flow through a tube can be separated into two components: (1) physical properties of the tube (e.g., length and radius), and (2) physical properties of the gas flowing through the tube (e.g., laminar vs. turbulent flow). At low flow rates, flow is laminar and the relationship between flow and pressure is linear as shown by the Hagen-Poiseuille equation:

Δ P = 8 l μ x Q
πr4

Notice how the pressure gradient (ΔP) increases linearly with increasing flow (Q_) with a slope governed by resistance, R = 8lμ/πr4.

Resistance (R) increases with tube length and gas viscosity (μ), while resistance decreases as radius (r) increases by the fourth power. At high flow rates (e.g., bronchospasm, asthma, and COPD), gas velocity significantly increases, resulting in turbulent flow, and the relationship between flow and pressure becomes nonlinear, where√ΔP∝Q_ implying a much higher pressure will be necessary for a given flow(Q_) relative to laminar flow, where ΔP∝Q_. During turbulent flow, resistance is proportional to the density(ρ) of the gas and inversely proportional to the radius of the tube (r) to the fifth power: R ∝ ρ/r5.

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7
Q

Give an example of how gas flow resistance applies to clinical practice.

A

Patients who are intubated must exchange gas through a smaller diameter than their normal airway. Recall, resistance is inversely proportional to radius to the fourth power for laminar flow. Because of the smaller radius of the endotracheal tube, resistance will increase, requiring increased work of breathing if unassisted by the ventilator. This increased work of breathing can be reduced by assisting the patient with a synchronized ventilator mode, such as pressure support. Pressure support allows the patient to trigger the ventilator, which can provide positive pressure to “overcome” the resistance of the endotracheal tube and decrease the work of breathing on inspiration. However, the work of breathing will still be increased on expiration as the ventilator only assists on inspiration. Other examples that pertain to increased airway resistance include bronchospasm, secretions, postextubation stridor, and a kinked endotracheal tube.

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8
Q

What determines laminar versus turbulent flow? What are the clinical implications of this?

A

Laminar flow is more efficient than turbulent flow for gas exchange, as turbulent flow will require a larger pressure gradient to obtain the same amount of flow. Reynolds number (Re) is a dimensionless number that can be used to predict if flow will be turbulent or laminar. A lower Re is associated with laminar flow, and a higher Re is associated with turbulent flow. Re can be calculated by the following equation: Re 1⁄4 2rvρ/η, where r is tube radius,
v is gas velocity, ρ is gas density, and η is gas viscosity. Notice how increasing gas velocity increases Re, leading to more turbulent flow and decreasing gas density lowers Re, leading to more laminar flow.

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9
Q

Discuss clinical interventions that may mitigate turbulent flow.

A

Increased airway resistance (e.g., bronchospasm) can lead to turbulent flow because of an increased inspiratory flow or gas velocity (see equation for Reynolds number). One method to treat problems related to turbulent flow is to lower the gas density. This can be accomplished with the addition of helium. When helium and oxygen are combined, the result is a gas composition called heliox, which has a similar viscosity as air, but importantly, has a much lower density. This accomplishes the following: (1) decreases Reynolds number, allowing for less turbulent and more laminar flow, and (2) decreases turbulent flow resistance. Recall that resistance during turbulent flow
is R ∝ ρ/r5 (where ρ is gas density). A common mixture is 70% helium and 30% oxygen. Applications where heliox may prove helpful include postextubation stridor and status asthmaticus.

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10
Q

What is compliance? How is it calculated?

A

Compliance is a measurement that reflects the amount of volume the pulmonary system can store for a given pressure. The overall compliance of the pulmonary system is determined by the lung, chest wall, and state of the patient’s respiratory cycle (inhalation or exhalation). Pulmonary compliance (C) can be calculated by measuring the change in volume for a given change in pressure:

C = ΔV/ΔP

Two factors that affect the compliance of the lung itself are: (1) water tension, (2) amount of functional lung connective tissue, such as elastin and collagen. A patient may exhibit decreased compliance from the lung itself (e.g., pulmonary fibrosis) or from decreased outward chest wall force (Fchest) and/or increased abdominal pressure (e.g., obesity, ascites, pregnancy).

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11
Q

Describe how pulmonary compliance changes with inspiration and expiration.

A

How the state of the respiratory cycle can impact lung compliance can be demonstrated as follows: at the end of exhalation, certain areas of the lung will favor atelectasis (i.e., zone 3 dependent regions) compared with others (i.e., zone 1 nondependent regions). Assume a patient takes a large breath from RV to TLC. At the start of inhalation, pulmonary compliance is low, because the atelectatic regions of the lung contain alveoli that are collapsed and water filled, thereby creating a less energetically favorable state (i.e., requiring more energy to inflate). After these alveoli are recruited, compliance increases until the lung is maximally inflated, at which point lung and chest wall compliance begin to decrease, impairing further inhalation. Here, the elastic recoil forces of the lung itself increase, and the chest wall, which normally favors lung expansion, reaches its maximum limit.

On exhalation, the pulmonary compliance for a given volume or pressure is higher than it is on inhalation. At the beginning of inhalation, atelectatic alveoli are recruited from closed to open, which initially decreases lung compliance (think of blowing up a deflated balloon); however, at the end of inhalation, these formerly atelectatic alveoli are now opened, favoring a higher overall compliance for a given volume or pressure during exhalation (it is easier to keep a balloon inflated once inflated). This concept is known as hysteresis, where the current state of a system
(i.e., pulmonary compliance) is dependent upon its past state (i.e., inhalation or exhalation).

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12
Q

What is surface tension? How does it affect pulmonary mechanics?

A

Surface tension occurs whenever you have an interface between two mediums (e.g., liquid and gas), where one consists of polar molecules (i.e., water) and the other of nonpolar molecules (i.e., oxygen and nitrogen). To minimize the interface between water (a polar molecule) with air (nonpolar molecules), water will preferentially form the shape of a closed sphere. This shape will yield the largest volume to surface area ratio possible. The large volume of the sphere will facilitate maximum hydrogen bonding between water molecules, while minimizing the exposed surface area (i.e., the interface that is exposed to nonpolar molecules, which cannot undergo hydrogen bonding with oxygen and nitrogen).
In a patent alveolus, water forms a coat on the surface (analogous to a bubble) with a surface tension that wants to collapse this bubble into sphere of water (resulting in atelectasis). Surface tension, resulting from hydrogen bonding, is the primary underlying force contributing to lung recoil and the promotion of atelectasis. However other factors, such as alveolar interdependence between walls of shared alveoli, prevent collapse. Further, the structure of alveoli is not spherical but rather more polygonal in shape. Taken together, alveolar interdependence, their polygonal shape, and probably other factors prevent the formation of perfectly spherical, collapsed alveoli, despite the natural tendency of water to do so.
To summarize, alveoli are coated by a layer of water, which creates an alveolar wall surface tension at the liquid-gas interface. This force plays an important role in understanding atelectasis and pulmonary compliance.

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13
Q

Discuss Laplace’s law. How does it apply to pulmonary physiology?

A

Laplace’s law describes the relationship of pressure across an interface (ΔP), wall-surface tension (T), and the radius (R) of a sphere. It can be used to model the physical properties of an alveolus. ΔP = 2T/R
The Laplace equation states that as the diameter (or radius) of an alveolus decreases, the pressure inside that alveolus will increase, assuming surface tension is constant. This implies that the pressure inside smaller alveoli is greater relative to larger alveoli, causing gas to preferentially flow from small to large alveoli. This would cause small alveoli to get smaller and smaller until atelectasis occurs, although the large alveoli would get larger and larger leading to volutrauma. Note, this phenomenon only occurs if the alveolar surface tension remains constant (i.e., patients who are deficient in pulmonary surfactant). As will be explained, surfactant plays an important role in stabilizing alveoli and preventing this problem from occurring.

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14
Q

What is surfactant?

A

Pulmonary surfactant is a phospholipid substance that contains both polar and nonpolar regions at opposite ends. It is produced in the lung by type II alveolar cells and coats the water already present in the alveoli. This coating forms an interface in the alveoli between the water (polar regions of surfactant) and air (nonpolar regions of surfactant) that reduces surface tension, thereby enabling alveoli to remain open at smaller lung volumes. Because water surface tension is responsible for approximately two-thirds of the recoil force of the
lung, pulmonary surfactant plays an important role in preventing atelectasis and increasing pulmonary compliance.

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15
Q

What role does surfactant play in pulmonary physiology?

A

Surfactant plays an important role in stabilizing alveoli.

When an alveolus becomes smaller (e.g., during exhalation), the concentration of surfactant increases, thereby decreasing water surface tension. Conversely, when the alveolus becomes larger, the concentration of surfactant decreases, causing water surface tension to increase.

Note how surface tension and alveolar radius are intrinsically linked; surface tension increases as radius increases and decreases as radius decreases. Thus this relationship helps minimize any differences in ΔP between smaller and larger alveoli (Laplace’s law).

Surfactant also plays a role in elastic recoil. As previously discussed, the concentration of surfactant is a function of alveolar size. Thus surfactant enables the lung to exhibit elastic properties similar to a rubber band, where its recoil force increases as the rubber band is stretched. This property allows the lung to exhibit a higher compliance at low TVs, while also facilitating exhalation at larger TVs.

Because surface tension plays such a large role in contributing to the lung’s elastic recoil forces, disorders associated with surfactant deficiency are readily apparent.

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16
Q

What clinical scenarios might result in an absolute or relative surfactant deficiency?

A

Patients with surfactant deficiency will exhibit reduced lung compliance and will be more prone to atelectasis and volutrauma (see question on Laplace’s law). The classic example of absolute surfactant deficiency is that of the premature newborn, resulting in respiratory distress syndrome. Inflammation and other factors can cause decreased production of surfactant and/or surfactant dysfunction. This may be seen in conditions such as ARDS, asthma, COPD, interstitial lung disease, or following lung transplantation. Although exogenous surfactant is life-saving in the premature newborn, studies to date have not shown benefit in these latter conditions.

17
Q

What are the different zones of the lung?

A

The physiology of the lung is classically divided into three zones characterized by variations between ventilation (V) and
perfusion(Q_).Thethreezonesofanuprightlungbeginattheapices(zone1)andendatthebase(zone3).Note,Palvis
alveolar pressure, Ppa is pulmonary artery pressure, and Ppv is pulmonary vein pressure.

• Zone 1: Palv > Ppa > Ppv, which causes a high ventilation-perfusion mismatch ( V =Q_ > 1) and a propensity for
alveolar dead space (V =Q_ 1⁄4 ∞). Both ventilation and perfusion are at their lowest in this zone; however,
ventilation is greater than perfusion
• Zone 2: Ppa > Palv > Ppv, which yields an ideal ventilation-perfusion match (V =Q_ % 1). Both ventilation
and perfusion increase whereby ventilation % perfusion (oxygen volume for 1 liter of dry air is 210 mL and
oxygen capacity for 1 L of blood is 200 mL).
• Zone 3: Ppa > Ppv > Palv, which causes a low ventilation-perfusion mismatch (V =Q_ < 1) and a propensity

for shunt because of atelectasis (V =Q_ 1⁄4 0). Both ventilation and perfusion are at their highest in this zone;
however, perfusion is greater than ventilation.
Historically, gravity was theorized to explain the variation behind the zones of the lung with the implication that a zero-gravity environment would abolish this variation. However, studies by NASA and on the MIR space station show that ventilation-perfusion matching, as depicted earlier, persist in microgravity. In the upright position, gravity only accounts for about 25% of ventilation-perfusion distribution and 75% of this distribution was retained independent of gravity. The primary mechanism for the different lung zones is resistance to blood and gas flow caused by the geometry of the vasculature and bronchial tree, directing blood and gas to the base of the lungs. Further, these same studies found that perfusion was more evenly distributed throughout the lung in the following order (prone&raquo_space; supine > upright), thereby, supporting the utility of prone positioning for severe ARDS.

18
Q

What is the alveolar gas equation? What is the normal alveolar oxygen partial pressure at sea level on room air?

A

The alveolar gas equation is used to calculate the alveolar oxygen partial pressure PAO2:

PAO2 = FiO2 (Pb - PH2O) -PaCO2 / R

where PAO2 is the alveolar oxygen partial pressure, FiO2 is the fraction of inspired oxygen, Pb is the
barometric pressure, PH2O is the partial pressure of water vapor (47 mm Hg), PaCO2 is the partial pressure of carbon dioxide, and R is the respiratory quotient. The respiratory quotient is approximately 0.8 and is dependent on metabolic activity and diet.

At sea level, the alveolar partial pressure (PAO2) would be the following:
PAO2 = 0.21 (760 -47) - 40/0.8 = 99.7 mm Hg

19
Q

How would room air PAO2 compare between Denver, CO (elevation 5280 ft) and New York, NY (elevation near sea level)?

A

The FiO2 at room air (21%) is the same in New York City and Denver. However, because the barometric pressure, Pb, in Denver is lower, the alveolar oxygen partial pressure, PAO2, will also be lower.

20
Q

What are the causes of hypoxemia?

A

The five classic pathophysiological causes of hypoxemia are:
• Low inspired oxygen: this can be caused by high altitude, inadvertent swap of nitrous oxide and oxygen
gas lines, or simply neglecting to “turn on” the oxygen. Measures to prevent the latter problems include fail-proof safety connectors (i.e., pin indexed safety system and diameter index safety system) and the oxygen analyzer on the inspiratory limb of the anesthesia ventilator
• Alveolar hypoventilation: patients under general anesthesia (breathing spontaneously) and in postanesthesia care unit, following surgery, are often incapable of maintaining an adequate minute ventilation. Reasons for this include the following: residual paralysis from neuromuscular blocking agents, respiratory depressant effects from opioids and other anesthetic agents, shallow breathing from pain (i.e., splinting), or upper airway obstruction (e.g., obstructive sleep apnea). Hypoventilation results in an elevated alveolar CO2 (PACO2) which, by the alveolar gas equation, decreases alveolar O2 (PAO2), leading to hypoxemia. Of note, hypoventilation affects the arterial partial pressure of CO2 (PaCO2) to a much greater degree than it does the arterial partial pressure of O2 (PaO2). For example, high frequency (jet/oscillatory) ventilation and apneic oxygenation with high- flow nasal cannula are all methods which demonstrate that ventilation, in the traditional sense, is not necessary to oxygenate the blood. Further, pulse oximetry is a poor method to assess for hypoventilation and is often normal despite high levels of CO2. In addition, it is important to recognize that clinically significant hypoxemia that results from hypoventilation and does not respond to supplemental oxygen is likely because of more than just elevated alveolar CO2. For example, a patient with multiple bilateral rib fractures may initially hypoventilate because of pain (i.e., splinting), causing a small decrease in PaO2, which is easily treated with supplemental oxygen. However, hypoventilation can lead to atelectasis from small TVs, causing significant hypoxemia.

• Ventilation-perfusion(V=Q_)mismatch:alveolarventilationandperfusionwouldideallybeclosetoaone-to-
one relationship, promoting efficient oxygen exchange between alveoli and blood. However, when
alveolar ventilation and perfusion to the lungs are unequal (V =Q_ mismatch), hypoxemia results. Pathological
examples of V =Q_ mismatch include COPD, asthma, pulmonary embolism, bronchospasm, and mucus
plugging. Note, these conditions often contain elements of both elevated and decreased V =Q_ mismatching.
For example, a patient with a large pulmonary embolism will have increased dead space ðV =Q_ 1⁄4 ∞)
in one region of the lung, resulting in high blood flow to another region, potentially causing V =Q_ mismatch
(V =Q_ < 1) and subsequent hypoxemia. In general, hypoxemia because of V =Q_ mismatch can usually be
overcome with supplemental oxygen.

• Right-left shunt: although often listed separately, shunt is really just a subset of V =Q_ mismatch, where V =Q_ 1⁄4 0.

Some of the pathological examples listed later may have an element of V =Q_ mismatch in certain regions of
the lung where V =Q_ < 1, but not technically zero. There are two kinds of shunts: (1) physiological shunting, and (2) pathological shunting. Normal physiological shunt (2%–3% of cardiac output) is caused by venous drainage into the left heart by the bronchial and Thebesian veins. Examples of pathological shunt include arteriovenous malformations, right-to-left cardiac shunt, ARDS, atelectasis, pneumonia, and pulmonary edema. An important distinguishing characteristic of shunt is that hypoxemia cannot easily be overcome with supplemental oxygen alone and, depending upon the pathological condition, often requires alveolar recruitment strategies. Such strategies include: raising the head of bed to greater than 30 degrees, incentive spirometry, ambulation, noninvasive positive pressure ventilation, such as continuous positive airway pressure/bilevel positive airway pressure and, if intubated, increasing positive end expiratory pressure/performing alveolar recruitment maneuvers.
• Impaired diffusion: efficient oxygen exchange depends on a healthy interface between alveoli and the bloodstream. Pulmonary edema, intestinal lung disease, and emphysema are examples of pathological conditions that can impair the diffusion of oxygen into the blood.

21
Q

What is the most common cause of hypoxemia in the perioperative setting?

A

The two most common pathophysiological mechanisms for perioperative hypoxemia is right-left shunt and hypoventilation. Atelectasis (right-left shunt) is likely the most common condition leading to clinically significant hypoxemia, and usually results from factors such as alveolar hypoventilation, obesity, supine positioning, splinting, and “absorption atelectasis” from the use of 100% FiO2.

22
Q

Define anatomic, alveolar, and physiological dead space.

A

Physiological dead space (VD) is the sum of anatomic and alveolar dead space. Anatomic dead space includes
the nose, oral cavity, pharynx, trachea, and bronchi. This is about 2 mL/kg in the spontaneously breathing individual and accounts for the majority of physiological dead space.

Endotracheal intubation decreases total anatomic dead space because the volume occupied by the endotracheal tube is smaller than the oral cavity, nose, and pharynx.

Alveolar dead space is the volume of gas that reaches the alveoli but does not undergo gas exchange because of poor perfusion (i.e., zone 1 of the lung). In healthy patients, alveolar dead space is negligible.

23
Q

How does dead space affect alveolar ventilation?

A

The main goal of ventilation is to facilitate gas exchange at the level of the alveolus. However, as mentioned, there is a significant amount of anatomic dead space between the air we breathe and well perfused alveoli undergoing gas exchange. This can be demonstrated by the following equation: VT 1⁄4 VA + VD where VT is tidal volume, VA is alveolar volume, and VD is physiological dead space volume (anatomic and alveolar). Assuming a (physiological) dead space volume of 2 mL/kg, a 70-kg person would have approximately 140 mL of dead space. Therefore TVs need to be greater than 140 mL to guarantee alveolar ventilation to facilitate gas exchange. Note, this is the classic teaching of this concept and evidence to date shows some alveolar ventilation (and CO2 gas exchange) can occur with apneic oxygenation using high flow nasal canula (60 LPM) or open-lung ventilation strategies (e.g., high frequency jet/oscillatory ventilation).

24
Q

How does PaCO2 relate to alveolar ventilation?

A

PaCO2 is inversely related to alveolar ventilation and is described by the following equation:

PaCO 2 = VCO2 / V alveolar

V CO 2 , CO2 production;
V alveolar , alveolar ventilation

Therefore increasing the minute ventilation will decrease the PaCO2, provided TVs are greater than the anatomic dead space.

25
Q

How can dead space be quantified? How does arterial partial pressure of CO2 (PaCO2) relate to mixed, expired CO2 (PeCO2)?

A

Dead space can be quantitated using the Bohr equation:
VD=VT 1⁄4ðPaCO2 PeCO2Þ=PaCO2
VD, dead space volume; VT, tidal volume; PaCO2, arterial CO2 partial pressure; PeCO2, mixed expired CO2 partial pressure
The Bohr equation is a method to calculate the physiological dead space (VD) by measuring the tidal volume (VT), the mixed expired CO2, and arterial CO2 partial pressures. In a healthy 70-kg patient with a VD % 150 mL (2 mL/kg)
and VT % 500 mL (6–8 mL/kg), the dead space is normally 1/3 of the tidal volume (i.e., VD/VT % 0.3). Similarly, in a healthy patent with a PaCO2 of 40 mm Hg, the measured mixed PeCO2 will equal 28 mm Hg. Applying these parameters to the Bohr equation will yield the following: VD / VT 1⁄4 (40 – 28)/40 1⁄4 0.3. The PeCO2 is lower than the PaCO2 (arterial CO2) because the CO2 free gas from the physiological dead space dilutes and lowers the PACO2 (alveolar CO2). Note, that CO2 is perfusion limited (not diffusion limited like oxygen); therefore in well-perfused alveoli, the PACO2 % PaCO2.

26
Q

What is the difference between end-tidalCO2 (ETCO2) and mixed, expiredCO2 (PeCO2)? Which one is used clinically?

A

The ETCO2 is the CO2 measured by capnography at the end of exhalation, whereas the PeCO2 is the final CO2 partial pressure measured in a volume of gas following complete exhalation. Clinically, the ETCO2 is most often used (not PeCO2) and reflects alveolar ventilation (i.e., PACO2). The ETCO2 will decrease in pathological conditions associated with increased alveolar dead space (e.g., pulmonary embolism, cardiac arrest, COPD). Note, because ETCO2 reflects alveolar ventilation, it is less affected by anatomic dead space. Therefore the difference between PaCO2 and ETCO2 is generally minimal (i.e., 4–5 mm Hg), where the PeCO2 will be much lower because it is diluted by both anatomic and alveolar dead space.

27
Q

How is CO2 transported in the blood?

A

CO2 exists in three forms in blood: as dissolved CO2 (7%), as bicarbonate ions (HCO3 ) (70%), and combined with hemoglobin (23%).

28
Q

What is hypoxic pulmonary vasoconstriction?

A

Hypoxic pulmonary vasoconstriction (HPV) is a localized response of vascular smooth muscle in the pulmonary system
that redirects blood flow from hypoventilated regions (i.e., low PAO2 and high PACO2) to better ventilated regions.
Specifically, low PAO2, high PACO2, and low pH cause pulmonary vasoconstriction and high PAO2, low PACO2, and high

pH cause vasodilation. This serves to improve overall V =Q_ matching. It is important to know that this response in the pulmonary system is the opposite of what occurs in the systemic vasculature. Although vasodilating agents and older volatile anesthetic agents (e.g., halothane) may blunt HPV, studies show that the newer volatile agents (i.e., sevoflurane and desflurane) in addition to intravenous agents (i.e., propofol) do not inhibit HPV in commonly used clinical doses.
Knowledge of HPV plays an important role in managing patients with pulmonary hypertension, as any episode of hypoxemia, hypercarbia, or acidosis will increase pulmonary vascular resistance (PVR). Any increase in PVR
will cause the pulmonary artery pressure to increase, potentially leading to right heart failure. Avoiding episodes of hypoxemia and hypercarbia in patients with severe pulmonary hypertension is crucial.

29
Q

What is arterial oxygen content (CaO2) and how is it calculated?

A

Arterial oxygen content is the amount of oxygen carried in arterial blood (mL of O2/dL of blood). It is calculated
by summing the oxygen bound to hemoglobin (Hgb) and the oxygen dissolved in blood (PaO2) by the following equation:
CaO2 = (1.34) (Hgb) SaO2 +(0.003) PaO2

Where 1.34 is the oxygen binding capacity of hemoglobin (mL of O2/gram of Hgb), SaO2 is the hemoglobin saturation, Hgb is the hemoglobin concentration (g/dL), 0.003 is the solubility coefficient for oxygen (mL/dL/mm Hg), and PaO2 is the partial pressure (mm Hg) of arterial oxygen.

30
Q

What is oxygen delivery?

A

One of the primary roles of blood flow is to provide oxygen delivery (ḊO2) to peripheral tissues. This can be represented by the following equation:

ḊO2 = CO x CaO2

DO2, oxygen delivery (mL of O2/min); CO, cardiac output (liter of blood/min); CaO2, oxygen content (mL of O2/dL of blood)
This equation states that there are two methods to increase oxygen delivery to tissue: (1) increase cardiac output, or (2) increase arterial oxygen content. Because PaO2 is multiplied by 0.003, dissolved oxygen plays a minor role in determining arterial oxygen content and there is little utility in administering high FiO2 to raise the PaO2 when the SaO2 is normal. More useful methods to increase oxygen delivery are to maintain normal (SaO2 >90%), transfuse packed red cells in the setting of anemia, or administer inotropic agents in the setting of cardiogenic shock. As an example, administering blood to a patient in hemorrhagic shock will increase oxygen delivery by two methods: (1) increasing hemoglobin, which increases CaO2, and (2) increases stroke volume, thereby increasing cardiac output.

31
Q

Where is the respiratory center located?

A

The respiratory center is located bilaterally in the medulla and pons. Three major centers contribute to respiratory regulation. The dorsal respiratory center is mainly responsible for inspiration, the ventral respiratory center for both expiration and inspiration, and the pneumotaxic center for controlling breathing rate and pattern. A chemosensitive area also exists in the brainstem just beneath the ventral respiratory center. This area responds to changes in cerebrospinal fluid pH, sending corresponding signals to the respiratory centers. Anesthetics depress the respiratory centers of the brainstem.

32
Q

What role do carbon dioxide and oxygen play in the regulation of breathing?

A

During hypercapnic and hypoxic states, the brainstem will be stimulated to increase minute ventilation, whereas during periods of hypocapnia and normoxia, minute ventilation will be repressed. Carbon dioxide (indirectly) and hydrogen ions (directly) work on the chemosensitive areas of the brainstem, whereas oxygen interacts with the peripheral chemoreceptors in the carotid and aortic bodies. Of the two, carbon dioxide is, by far, more influential than oxygen in regulating respiration.

33
Q

What are pulmonary function tests, and how are they used?

A

The term pulmonary function test (PFT) refers to a standardized measurement of a patient’s airflow, lung volumes, and diffusing capacity for carbon monoxide. These values are always reported as a percentage of a predicted normal value, which is calculated based on the age and height of the patient. They are used in combination with the history, physical examination, blood gas analysis, and chest radiograph to facilitate the classification of pulmonary disease into an obstructive, restrictive, or mixed disorder.

34
Q

What is the benefit of obtaining PFTs?

A

The primary goal of obtaining preoperative PFTs, also called spirometry, is to recognize patients who are at high risk for developing postoperative pulmonary complications. However, it is important to note that no single test or combination of tests will definitively predict which patients will develop postoperative pulmonary complications.

35
Q

What are the measures of pulmonary function and their significance?

A

These are effort dependent and require a motivated patient (Fig. 6.2).
• Forced expiratory volume in 1 second (FEV1)
• Forced vital capacity (FVC)
• The ratio of FEV1 and FVC, or FEV1/FVC ratio. The FVC may be normal or decreased as a result of respiratory
muscle weakness or dynamic airway obstruction
• Forced expiratory flow at 25% to 75% of FVC (FEF 25–75). A decreased FEF 25–75 reflects collapse of the
small airways and is a sensitive indicator of early airway obstruction. It is thought to be the most effort independent measurement