Prokaryotic Genetic Systems Flashcards

1
Q

What occurs during rapid growth of bacterial cells?

A

No B period and replication cycles overlap (not possible in eukaryotes)

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2
Q

What is DAPI and what does it do?

What did DAPI staining reveal?

A

Fluorescent due that stains AT rich regions of the genome

DAPI staining revealed the bacterial nucleoid occupies 50-75% of the cell volume

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3
Q

How big is the E.coli chromosome?

What is the problem with this?

Why do many bacterial cells often contain more DNA than this?

A

4.7Mb chromosome in a circle of 1.5mm (minimum amount of DNA required in E.coli cell)

Needs to fit into a cell of 1 by 0.5 um

The have accessory DNA and rapidly growing cells undergo multiple rounds of replication simultaneously = more than one chromosome

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4
Q

To what size would condensation by thermal motion (Brownian motion randomly coiling the DNA) reduce the DNA?

A

10um; greater degree of condensation required

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5
Q

How can nucleoids be isolated? What are the differences in the two structures produced?

A

With membrane associated or membrane free (MA or MF)

MA has much more protein and also has phospholipid and four stable DNA binding proteins
HNS, HU, FIS, And IHF

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6
Q

How can nucleoid be disrupted?

What does this show?

A

Heat, RNase, DNase, proteinase

Held together by weak interactions and DNA RNA and protein each have role in maintaining structures

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7
Q

What are the prokaryotic analogues of histones?

How do they structure DNA?

How is it similar to eukaryotic?

What is special about these loops?

How was this found originally?

A

DNA binding proteins like HU and H-NS (non sequence specific)

At low concentrations HU bends DNA compacting the nucleoid, at high concentrations HU dimers interact with DNA to form extended filaments

H-NS (histone like nucleoid structure in protein) has two DNA binding domains that it uses to bridge between distant sites on DNA

Dimers plus bringing creates scaffold on which nucleoid can be organised, like eukaryotic DNA, the chromosomes is organised into loop domains

They are topologically independent of one another; a nick in one loop will not relax neighbouring loops

Electron microscopy

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8
Q

What do the evidence for loop domains in prokaryotic nucleoid (also evidence for size of loop domains)?

What size were they approximated to be?

What size does supercooling reduce the nucleoid to?

A

Originally Electron microscopy:

Later cells irradiated with x Rays and it was found that 160 nicks (one dose of X-ray assumed to equate to one Nick and 160 doses were required) relaxed >95% of super helical tension

Suggests approx 120 loops or chromosome as loops are topologically independent of one another; a nick in one loop will relax that loop but not neighbours

50kb like in eukaryotes (50-100kb)

1um

The size loops were estimated to be from this experiment were found to be incorrect with later experiment with SwaI

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9
Q

How are loop bases thought to be anchored?

Not quite sure so look into further

A

Scaffold associated regions SAR using BIME and REP

REP has 1-12 tandem repeats of 40bp palindromic sequences which bind gyrase (a enzyme like eukaryotic topoisomerase II)

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10
Q

How was it concluded that DNA loops are variable in size and position and nucleoid is fluid?

A

Restriction endonuclease SwaI was expressed in living cells (got gene into cells by plasmid uptake). Specific 6bp cleavage sequence of enzyme known so knew where the 117 cleavage sites of the enzyme were in DNA. Cleavage relaxed loop the site was in but not neighbouring loops (topologically independent) Knew of 300 genes in E.coli whose expression varied with supercoiling so used these as reporters when DNA microarray with RNA harvested form cells (shows which genes were transcribed) used to assess effects of cleavage on expression (by seeing which RNA transcripts were absent they could tell which genes had been switched off) Genes showed little response to cleavage if cleavage site more than 10kb away from gene - the size of loops is 10kb

Then introduced new cut sites by genetic engineering for SwaI at varying distances from supercoiling sensitive genes. If domain boundaries fixed to genes should see discrete switches between expression, did not see that so boundaries fluid

This experiment corrected the earlier x-Ray experiment which estimated loops to be 50kb

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11
Q

How have fluorescence and atomic force microscopy shown nucleoid structure to be dynamic?

A

They have facilitated observance of nucleoid through the different growth stages and revealed that it changes, in particular nucleoid is condensed in non-growing bacteria and more open whilst in log phase

Fluidity in macroscopic structure as well as microscopic

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12
Q

How is eubacteria DNA coiled?

How is negative supercoiling introduced?

How is supercoiling maintained?

What does negative supercoiling mean for the expression of the DNA?

A

Negatively supercoiled or under wound

DNA gyrase (type II topoisomerase) requiring ATP which makes cuts in both strands of the DNA

Topoisomerase I removed supercoils without ATP by cutting one strand and allowing it to wind around the other to release stress

Antagonistic action of the isomerases a maintains constant level of supercoiling

Negative supercoiling Is slightly under wound and makes DNA more open and accessible for transcription

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13
Q

How is DNA supercoiled and linked (geometry)

What is Lk when DNA is not supercoiled?

What is it when it is supercoiled?

What causes writhe?

A

The two strands are wrapped around one another in a double helix with negative supercoiling

Two strands in helix are linked by H bonds and base pair surface interactions but also linked geometrically by intertwining of DNA backbones into T twists

One inter-link for each twist of double helix

Lk = linkage between the strands when the helix is not supercoiled = the twist

When the DNA is supercoiled, Lk = W + T

W = writhe = number of times backbone crosses itself
Writhe results from a slight undoing (4%) of the helix turns

antagonistic action of DNA gyrase (supercoils) and topo I which releases stress, (relaxation of helix turns introduces writhe)

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14
Q

What is the eukaryotic cell cycle?

What is the prokaryotic cell cycle?

What period also features in each cell cycle?

A

G1 phase - growth is mass
S phase - replication of DNA
G2 phase - growth in mass
Mitosis - separation of sister chromatids
Cytokinesis - separation of daughter cells

B period - growth in mass
C period - replication of DNA
(No second growth phase)
D period - separation of daughter chromosomes and daughter cells

G0 in eukaryotic cells and persister formation in prokaryotes, used to think only cells in limiting conditions would enter dormancy phase but many bacterial cells exist in this state even when nutrients are available, makes them very stress resistant (problem in disease)

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15
Q

What two experiments we’re used to estimate the size of prokaryotic DNA loops?

A

X-Ray (incorrectly estimated to be 50kb)

SwaI estimated to be 10kb

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16
Q

Why can translation and traction ion be coupled in prokaryotes?

What does this allow?

A

Lack of nuclear membrane

Regulation of transcription by attenuation

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17
Q

What is attenuation?

What does it rely on?

A

Mechanism of control in bacterial operons which results in premature termination of transcription

The fact that transcription and translation occur simultaneously in prokaryotes

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18
Q

How is the trp operon regulated?

What is the depressor protein, where is it transcribed ad what does it do?

How does it work and what does it rely on?

What does this make tryptophan?

A

By a combination of attenuation and repression

Repressor protein is a tetramer of proteins resulting from expression of trpR genes upstream of operon

When tryptophan is present the Repressor protein binds to operator region blocking the promoter so RNA polymerase can’t bind

Relies on the fact that the operon and promoter overlap

Makes tryptophan a co-repressor of the operon

19
Q

How does the attenuation part work?

A

The trp operon contains an attenuation region with sequences 1-4

These sequences can form different structures in the mRNA they will be transcribed into. The structures they form depend on the supply of amino acids, if plenty of tryptophan is supplied to the ribosomes then the ribosomes move quickly over the mRNA, quickly covering 1 and 2 regions so the 3:4 termination hairpin forms (3 can’t bind to 2 so it binds to 4)

The hairpin throws off the polymerase before it reaches the amino acid biosynthesis genes, preventing further transcription

If amino acid supplies of tryptophan are low the ribosome can’t move quickly so stalls over region one allowing the 2:3 loop to form, preventing the termination loop from forming so transcription proceeds

20
Q

Why is attenuation only useful for control of amino acid biosynthesis genes?

A

Because it relies on the supply of amino acids determining the speed at which ribosomes progress

21
Q

Is E.coli DNA circular?

A

Yes

A lot of prokaryote genomes are circular but there are also linear chromosomes and vast differences in genome size

Bacteria in more constant environments will my need as much variation in the genome so will have smaller genomes (dont have to cope with as many different changes)

22
Q

What are plasmids increasingly viewed as?

A

Individual parasitic elements because they facilitate their own autonomous replication and move horizontally between bacteria (don’t really. Have species of bacteria because they can share info with all by conjugation)

23
Q

Why do bacteria need plasmids?

A

To carry accessory info like pathogenicity, metabolic properties, resistance, provision of additional repair systems (eg to protect from ionising radiation)

They lack sex do my get homologous recombination to shuffle genes, need plasmids to create variation for evolution

24
Q

What is an advantage of a circular chromosome in replication?

How is this solved for linear bacterial chromosomes?

A

No ends so no telomeres

Have one of these models:
Endless linear structure - single stranded loop connecting the ends
Racket frame model - inverted repeats and proteins covalently bound to 5’ end

25
Q

What are the two groups of plasmids that exist?

A

(Aside from small, multicopy and then large plasmids which is one way of classifying) you have plasmid selfish genes which promote their own proliferation in environment (selective advantage)and plasmids that have arisen and survived through chance as a result of natural selection because they convey properties that allow host to cope with transient conditions in their environment

26
Q

Plasmids maintenance includes distribution of plasmid to daughter cells, what are the two methods this is achieved by and which plasmids use them?

A

Low copy plasmids - active partitioning

High copy plasmids - random distribution

27
Q

What is the controlling mechanism of active partition in terms of genes?

How many families of these are there?

A

The partition cassettes/operons

Two have been identified:
Those for the P1 and F types
A different type for R plasmids

28
Q

How does the P1. Type cassette work (note it works the same as the sop cassette for F as they are the same type)

A

ParB protein binds to parS (lowercase and italics because it is DNA) (centromere like region of plasmid needed to partition plasmids) forming the partition complex
This complex then binds to ParA protein, activating its ATPase activity and causing it to dissociate from the DNA. ParA binds to promoter region to regulate transcription of partition cassette and hence partitioning. ATP hydrolysis provides every to drive separation of plasmid products

29
Q

How does the R1 plasmid work?

A

Plasmids duplicated at mid-cell by replication factory
Par R binds parC
ParR-parC complex
Products of replication paired by ParR-parC complex
ParM is an ATPase that binds ATP
ParR-parC complex nucleates ParM polymerisation
Par M polymerisation using ATP hydrolysis generates force required to push plasmids to cell poles

Note ParM and Par R are proteins so have capital letter, parC should be lowercase and in italics as it is DNA

30
Q

What was used to visualise the sub-cellular location of actively partitioned plasmids?

What was the result?

A

Fluorescence microscopy

Plasmids are mid cell in new born cell but rapidly move to 1/4 and 3/4 positions

31
Q

What causes dimerisation of plasmids?

What does this cause?

How is this resolved?

What does the same in E.coli?

A

Homologous recombination between sister chromosomes during replication

Causes failing of partitioning

Site specific homologous recombination resolves dimers to monomers eg Cre recombinase mediated recombination between repeated loxP sites in P1 prophage. Recombinases bind to specific short sequences in DNA and participate in stand cutting, exchange between lox sites and religation. The first pair of strand exchanges generates a Holliday junction intermediate

Xer-dif does this in E.coli by binding The recombinases XerC and XerD with ArgR and Pep A proteins

32
Q

Where does the evidence for the Par M mechanism come from?

A

From visualisation of plasmid movement by fluorescence microscopy

33
Q

Why is site specific recombination different to homologous recombination?

A

It doesn’t require extensive DNA sequence homology

34
Q

What can cause plasmid instability?

A

Too great a metabolic load on the cell which slows growth and replication. As load conveyed by plasmid increases the rate at which plasmids disappear from culture increases

Plasmid multimerisation

35
Q

What is an Holliday junction?

A

A common recombination intermediate in prokaryotes and eukaryotes

36
Q

What challenges the random distribution hypothesis?

A

The fact that experiments tracking plasmids and nucleoids in the cell have shown plasmids to be in clusters

Possibly:
Docking to cellular structures
Failure to separate post replication
Artefact caused by the method of visualisation - clustering may be caused by the tagging process

37
Q

What is a problem of dimerisation?

A

Dimers have a lower copy number than monomers as they outcompete monomers for polymerase because they have two origins but then replicate more slowly, preventing monomers from replicating.

Leads to increase in dimers over monomers in small proportion of population where they are concentrated (dimer catastrophe) but overall low plasmid copy number.

If plasmid number drops below 20 chances of plasmid few cells arising increases

38
Q

How is dimerisation resolved and what are the two models proposed?

A

By site specific Recombination as explained before

Two models proposed for this:
Oxford model - recombining sites must wrap around one another three times before they can recombine. Only achievable when sites are in the same supercoiled molecule
Cambridge model - accessory proteins ArgR and PepA form a bridge due to charge interactions between proteins, complex is stabilised by spring clip effect of DNA supercoiling. Doesn’t work if recombination sites are on different monomers hence recombination is unidirectional (only converts to monomers, doesn’t make multimers)

39
Q

How is bacterial conjugation carried out?

How is transfer during conjugation carried out

A

Different systems exist between gram negative and positive Bacteria

Gram negative direct synthesis of extra cellular pilus encoded for within plasmid
The pilus makes initial contact and retraction of pilus brings cells in closer proximity and cell to cell contact
Disassembly also establishes a DNA transport pore

Sequence specific Nick on donor plasmid, 5’ end is transferred to recipient and 3’ end remains
Complementary strand synthesis occurs in both donor and recipient so get leading strand synthesis in one cell and lagging in another

40
Q

What is the structure of the F pilus?

How many genes in bacterial plasmid are dedicated to conjugation and what does this show?

A

Hollow cylinder of 8nm diameter with 2nm axial hole

One third of genes in the F plasmid, shows how important conjugation is as a method of gene transfer

41
Q

What are transposases and what are they also known as?

What is there structure and his does this work?

How can this be used to mobilise other genes?

A

They are mobile elements of the genome also known as insertion sequences.

The are flanked by terminal inverted repeat sequences that provide binding sites for transposases

Transposase cleaves insertion sequence from original site then introduces staggered cut at target site and ligates into new location

If two IS sequences flank a gene the gene can be moved

42
Q

What provides genetic flexibility to eukaryotes?

A

Plasmids and transposable elements

43
Q

Need to do the bit about the Tn3 family of mobile elements at end of lecture pack

A

High