Projectile Motion Case 1 and 2

Question 1

What is the formula in Case 1 x-axis?

Answer 1

dx = Vfxt

Question 2

What are the three formulas in Case 1 y-axis?

Answer 2

Vfy = Viy - gt, dy = Viy - 1/2gt^2, and t = Viy/g

Question 3

What are the 2 assumptions from case 1?

Answer 3

X-Velocity is constant and Viy = 0

Question 4

A rock is thrown horizontally from a height of 88m with a horizontal speed of 25m/s. Find time.

Answer 4

T = 4.24s

Question 5

What are the three assumptions from Case 2?

Answer 5

At max height, Vfy = 0, T at max height is 1/2 of the total time of flight, and Vix = Viy

Question 6

How do you solve for Vix and Viy?

Answer 6

Vix = ViscosTheta and Viy = VisinTheta

Question 7

What are the three additional equations used in Case 2?

Answer 7

time of flight = 2 (visinTheta)/g, R/dx = Vi^2 sin2Theta/g, and time at max height = 1/2 (time of flight)

Question 8

A projectile fires with a Initial velocity of 75m/s 35 degrees above the ground. Find the max height.

Answer 8

dy = 94.42m

Question 9

Using the given and answer from question 8, find the total time in the air.

Answer 9

T = 8.78s

Question 10

Using the given and answer from question 8, find the range/dx.

Answer 10

dx = 539.36m