Projectile Motion

Question 1

Horizontal Position

Answer 1

x= Vicosθ t

Question 2

Vertical Position

Answer 2

y= vi sinθ t - 1/2 gt^2

Question 3

Maximum Height

Answer 3

(Vi^2 sin(θ)^2)2g

Question 4

Horizontal Range

Answer 4

R= (Vi^2sin(2θ))/g

Question 5

Maximum Range

Answer 5

Vi^2/g @ 45 degrees