Projectile Motion

Question 1

Equation for Horizontal Distance (x)

Answer 1

x = Vix t
x = Vi cos θ t

Question 2

Velocity of the Horizontal Motion will not change

Answer 2

Vfx = Vix

Question 3

Equation for Vertical Distance (y)

Answer 3

y = Viy t + 1/2gt^2
y = Vi sin θ t + 1/2gt^2

Question 4

Formula for Final Vertical Velocity (Vfy)

Answer 4

Vfy = Viy + gt
(Vfy)^2 = (Viy)^2 + 2gΔy

Question 5

Formula for Velocity of Vector

Answer 5

V = √[(Vx)^2 + (Vy)^2]

Question 6

Formula for Maximum Range

Answer 6

R = (Vi^2 sin 2θ)/g

Question 7

Formula for Maximum Height

Answer 7

H = (Vi^2 sin^2 θ)/2g

Question 8

Derived Formula for Vertical Motion (y)

Answer 8

y = (tan θ)x + [g/(2Vi^2 cos^2 θ)]x^2

Question 9

Formula for Time (projectile is fired horizontally)

Answer 9

t = √(2h/g)

Question 10

Formula for Horizontal Distance (projectile is fired horizontally)

Answer 10

x = Vit

Question 11

Formula for Velocity (projectile is fired horizontally)

Answer 11

V = √[(Vx)^2 + (Vy)^2] ;
Vx = Vi, Vy = gt

Question 12

Equation for Vertical Distance (y) from Elevated Position

Answer 12

Δy = Viy t + 1/2gt^2
y = y0 + Vi sin θ t + 1/2gt^2