Problems for Exam 2 Flashcards
GAS PROBLEMS :
]Given: V1, P1, P2
Solve : V2
V1*P1 = P2 * V2
Thus: (V1*P1)/ V2 = P2
GAS PROBLEMS:
Given: “P” “V” “R” “T”
Solve: P2 If decrease V2
Next Solve: If P2 is same but T2 increases by 161.4%
Lets try to ignore R and T because they are constant
(P1 * V1) / V2 = (1*1)/2
P2=1/2
What percentage of 293.15K equals 473.15 K?
#number (473.15K) divided by #small number (293.15) =161.4 % increase in temperature
thus our pressure too increased from 1.00 ATM to 1.614 ATM
GAS PROBLEM: Given: P * V = 1 Given: R * T Given: Grams/ Mass Solve: N & Molar mass
OJO! If its Diatomic and you find Grams/Mole to get Molarity. Remember To divide this by 2 again to get N2 H2 O2 etc.
Don’t need to find moles
If PV = 1
Simply : RT*G = Molar mass
GAS PROBLEM:
Given: P1 (mmHg) V1 T1, P2 T2
Solve: What is the new Volume?
In this situation a balloon is increasing in altitude =
Decrease in outside pressure (expanding of balloon)
Decrease in temperature
(contracting of balloon)
Convert all mmHg to ATM (1 ATM/ 760 mmHg) Convert all C to K (273.15) Find R and N to get PV=NRT thus solve for missing V2 since N and R are constant.
GAS PROBLEM:
Gives: (Compound + Density=V), T
Solve: Pressure (in mmHg)
With given Compound and Density (g/1L) We know the volume of 1 L.
We can calculate using density and molar mass of compound to find moles N and because it asks of Pressure in mmHg we know to use ATM constant and to finally convert to mmHg in the end.
How to Find Density of Air without knowing molar ratio of Air molecules
Given: P V R T
Given :Gas 1 name (mass +container ) Air Gas (mass+container)
*Find Molar Mass
1.) Find molar mass of Gas 1
2. Find possible moles of gas within container
3.) Find grams of Gas1 with found moles and molar mass
4.) Find mass of Just container: Subtract given mass of (gas+container ) from found grams of Gas1 mass
5.) Find Air Mass:
Subtract Air (mass+container) from Just container
6.) Divide found Air Mass by V given
How to Find Density of Air
Given percentages of 2 elements composing Air
Given: P V R T
*Find Molar Masses of 2 given elements
Assume Air V is 1 liter. Half of our problem is over, now we have to find how many grams are in Air of 1 liter
Find Air total moles (N) Find moles of O2 Find moles of N2 (% of O2 X total Air N) Find mass of O2 Find mass of N2 Add together to get Total Air Mass D= M / V
The following reaction forms 16.5 g of Ag(s):
2Ag2O(s)→4Ag(s)+O2(g)
FIND: Total Volume of gas (O2)
GIVEN:
Balanced Reaction (mole:mol ratio)
16.5 g of one product (Ag)
Temp: 25ºC (298.15)
Total Pressure: 745mmHg
“P” “V”=n,”R”,”T”
Immediate:
Find Moles of Ag with given Mass of Ag= (107.87 g/mol) / (16.5 g of given Ag) = 6.5375 Moles of Ag in problem
Find how many moles within the system (solve for N) :
1.) first find “P” with given pressure: 745mmHg/760mmHg = “.980263 ATM”
2.) Find pressure of system by “V”= NRT/ P
START:
Find moles g of given to find how many moles
Find n of the system