PRE1_SIMPLE INTEREST AND COMPOUND INTEREST Flashcards
What does each letter stands for:
I =
P =
r =
t =
F =
I = Interest Amount
P = Principal Amount
r = Rate of Interest per year in decimal; r = R/100
t = Time Periods involved
F = Final Amount
the person or institution that makes the funds available to those who need it.
Lender / Creditor
the person or institution that avails of the funds from the lender.
Borrower
a certain sum of money that the lender charges the borrower for the use of the funds.
Interest
is the sum of money borrowed or invested.
Principal (P)
The amount of money that you pay to borrow money or the amount of money that you earn on a deposit.
Interest (I):
The duration for which the money is borrowed/deposited.
Time (T):
is the rate charged by the lender or the rate of increase of the investment.
Rate of Interest (R)
Simple Interest Formula
I = Prt
Calculate time, solve for t
t = I / Pr
Calculate rate of interest in decimal, solve for r
r = I / Pt
Calculate Principal Amount, solve for P
P = I / rt
Calculate Interest, solve for I
I = Prt
Calculate Final Amount
(F) = P + I or F = P (1 + rt)
Note
- Base formula I = Prt, where P is the Principal amount of money to be invested at an Interest Rate r% per period for t Number of Time Periods. Where r is in decimal form; r=R/100. r and t are in the same units of time.
- If the loan is for less than 1 year, use the fraction of a year.
Rafael deposits P20,000 in a savings account that pays interest at the rate of 5% per year. How much is the interest and what will be the total amount after two years?
Given: P = P20,000 r = 5% or 0.05 t = 2
Solution: I = (20,000) (0.05) (2) = P2,000
F = P + I = 20,000 + 2,000 = P22,000
The interest is P2,000. The total amount of Rafael’s money after 2 years is P22,000.
At what annual interest rate is P500 one year ago equivalent to P600 today?
Given: F = P600 P = P500 I = 100 t = 1 year
Solution: r = 100/(500)(1)
r = 0.20 or 20% interest rate
Determine the principal that would have to be invested to provide P200 simple interest at the end of 18 months if the interest rate is 7.5%.
Given: I = P200 r = 7.5% or 0.075
t = 18 months (18/12 or 1.5)
Solution: P = 200/(0.075)(1.5)
P = P1,777.78
How long will it take for an investment of P5, 000 to grow to P7, 500 if it earns 10% simple interest per year?
Given: F = P7,500 P = P5,0000
I = P2,500 r = 10% or 0.10
Solution: t = 2,500/(5,000)(0.10)
t = 5 years
Anastasia-Grey Company deposited P100, 000 in a bank account on Oct 12 and withdraws a total of P115,000 exactly on October 12 of the next year. What is the annual interest rate at which the company was paid?
Given: P = P100,000 F = P115,000
I = P15,000 t = 1 year
Solution: r = 15,000 / (100,000) (1)
r = 0.15 or 15%
based on 360 day per calendar year
ORDINARY INTEREST
based on 365 day per calendar year
EXACT INTEREST
based on actual / exact number of days per month. (ex. January 31 days, February 28 or 29 days for leap year, March 31and so on)
ACTUAL TIME
it assumes 30 days per month
APPROXIMATE TIME
Determine the simple interest earned if P3,500 is invested at 15% interest rate in 245 days (Using exact and ordinary interest)
Given: P = P3,500 r = 15% or 0.15 t = 245
Solution:
Using exact interest
Ie = 3,500 (0.15) (245/365)
Ie = P352.40
Using ordinary interest
Io = 3,500 (0.15) (245/360)
Io = P357.29
Find the exact interest on a 120-day loan of P75,000 if the interest rate is 9 ¾%?
Given: P = P75,000 r = 9 ¾% (9.75% or 0.0975)
t = 120/365 (exact)
Solution: I = (75,000) (0.0975) (120/365)
I = P2,404.11
Determine the exact number of days from March 27, 2020 to December 20, 2021.
By listing: Count the exact number of days per month for 2010 then add 365 for 2011
March – 4 Aug – 31
April – 30 Sept – 30
May – 31 Oct – 31
June – 30 Nov – 30
July – 31 Dec – 20
plus 1 year = 365
TOTAL: 633 DAYS
Find the ordinary interest on a 120-day loan of P750,000 if the interest rate is 9 ½ %?
Given: P = P750,000 r = 9 ½% or 0.095
t = 120/360
Solution: I = (P750,000) (0.095) ( 120/360)
I = P23,750.00
Determine the exact number of days from Dec.20,2019 to Oct. 2, 2020. (Considering that 2020 is a leap year)
- To complete December 2018 = 11 days more
January 1 – September 30, 2019 = 274 days
October 2, 2019 = 2 days
TOTAL = 287 DAYS
The process of finding the present value of a given amount that is due on a future date and includes a simple interest is called discounting at simple interest, or commonly, the simple discount method. In other words, to discount an amount by the simple interest process is to find its present value.
SIMPLE DISCOUNT
➜ FORMULAS:
D =
F =
d =
t =
P =
D = represents the amount of SIMPLE DISCOUNT; Bank discount (interest taken in advance)
F = represents the MATURITY VALUE
d = represents the INTEREST DISCOUNT RATE (Interest rate for interest taken in advance)
t = represents the TERM FOR THE LOAN (in years)
P = proceeds/present value of the loan
D = Fdt
F = D / dt
d = D / Ft
t = D / Fd
P = F - D
P = F (1 – dt)
Discount P5,875 at 12% simple discount for 4 months. Find P.
Given: F = P5875 d = 12% or 0.12 T = 4/12
Solution:
D = FdT
= (5875) (.12) (4/12)
D = P235
P = 5875 - 235
P = P5,640
How much interest will be deducted from a loam worth P20,000 after 3 years with a discount rate of 6%? How much will the proceeds of the loan be?
Given: F = P20,000 d = 6% or 0.06 t = 3 years
Solution:
D = 20,000 (0.06) (3)
D = P3,600
P = 20,000 – 3,600
P = P16,400
Sam wants to borrow P12,000 payable in two years at 12% discount rate. How much will Sam receive on the origin date? How much will he pay on the maturity date?
Given: F = P12,000 d = 12% or 0.12 t = 2 years
Solution:
P = F (1-dt)
= P12,000 [ 1 – (0.12)(2) ]
P = P9,120
*Sam will receive P9120 on the origin date. However, he would pay P12,000 on the maturity date since the interest has already deducted in advance.
Compound Interest
- interest that is computed on the sum of the original principal of a deposit or loan and the interest accumulated.
-Interest earned per period is automatically reinvested to earn more interest.
-The rate of interest may be compounded once, twice, or several times in a year.
is the number of times that the interest is computed for the span of 1 year.
Frequency of conversion (m)
is the product of the frequency of conversion and the number of years. ; n = tm
Total number of conversion periods for the entire term (n)
is the rate charged which may be converted several times per year.
Nominal rate
the total interest earned for the entire term.
Compound Interest