Practical 2 - SDS-PAGE and Western Blotting Flashcards
insulin is the stimulus for trafficking to the plasma membrane. If disruption via CRISPR/Cas9 has been successful will there be trafficking of the protein to the plasma membrane?
no
what is the function of SDS in this practical?
to denature and add a negative charge evenly over the proteins
what is the blocking agent normally made of in this experiment?
what is its function?
made of milk powder, casein or BSA
prevents non-specific binding of antibody to membrane
if the adipocyte has been given insulin, where would you expect to find the GLUT4 protein within the cell?
why?
on the cell membrane, so that glucose can be transported out of the blood stream and into cells to reduce blood sugar levels back to normal
name a viral disease in which western blotting can be used to confirm the presence of the disease
HIV or BSE
using a whiteboard, you have 50ml of solution. it needs diluting 1 in 1000. How many microliters of solution will be used?
if 1ml in 1000ml
then 0.1ml in 100ml
then 0.05ml in 50ml
so therefore need 0.05ml or 50 microliters of solution
using a whiteboard, if you have 50ml of solution and it needs diluting 1 in 5000, how many microliters will you need?
1ml in 5000ml
=0.2 in 10000ml
=0.02 in 100ml
=0.01 in 50ml
so 0.01ml or 10 MICROLITERS
what is the function of the Tween 20 used in the blotting solutions?
to act as a solubilizing agent and as a blocking agent to improve sensitivity of antibody detection
what is the consequence of using too much Tween20 in the blotting solutions?
it could wash away the bound antibody or antigen from the blot
what does the primary antibody bind specifically to?
the protein of interest only
what does the secondary antibody bind to?
why is it used?
the primary antibody
used to amplify signal and increase sensitivity
why is the secondary antibody coupled to an enzyme?
to catalyse a reaction which results in a coloured/chemiluminescent band = shows location of protein
using a whiteboard, if you had a 10x stock of transfer buffer how would you calculate the amount of water required to make up a 1x working solution?
you would dilute the stock solution by adding 9 parts of water for every 1 part of the stock solution
using a whiteboard, work out how you would make up 25ml of 1 in 1000 primary antibody?
divide 25 by 1000 to get the volume of antibody:
= 0.025ml
minus 0.025 from 25 to give you how much water you would need:
= 24.975ml
this gives you a 1mg/ml primary antibody solution.
using a whiteboard, work out how you would make up 40ml of 1 in 5000 secondary antibody?
divide 40 by 5000 to give the ml of antibody needed:
= 0.008ml
minus 0.008 from 40 to give ml of water needed for dilution:
= 39.992 ml