Population Genetics Flashcards
Population genetics
quantitative study of the distribution of genetic variation in populations and how the frequencies of genes and genotypes are maintained or changed
Hardy-Weinberg principle
- applied to populations to estimate genotype frequencies in the population when allele frequency is known.
- If p is the frequency of allele A and q is the frequency of allele a in a gene pool:
- –The chance of an AA genotype is p2
- –The chance of an aa genotype is q2
- –Then chance of an Aa genotype is 2pq
Hardy-Weinberg equation
(p+q)2 = p2 + 2pq + q2
The Hardy-Weinberg is used to determine
the frequency of genotypes based on expressed phenotypes for autosomal recessive diseases
Phenotypes of homozygotes for recessive mutant alleles can be identified and their frequency is equal to _______ in the Hardy-Weinberg eqn
q2
Taking the square root of _______ and subtracting it from 1 yields _______
q2 p (the number of wild-type alleles in the population)
Plugging p and q back into the equation gives the frequencies of the _______ and_______ genotypes (genotypes that we would not be distinguishable based on phenotype alone)
AA
Aa
In order for the Hardy Weinberg principle to be upheld, a number of assumptions are made (4)
- The population is large and mating is random
- Allele frequencies remain constant over time (meaning no new mutations)
- All individuals are equally capable of mating and passing on their genes (certain alleles are not selected for)
- There has been no significant immigration of individuals with significantly different allele frequencies
_______ is the main determinant in whether or not a mutant gene is passed onto future generations in order to become stable in a population
Fitness
Fitness
describes the number of offspring of persons affected by a mutation survive to reproductive age
For an autosomal dominant disease: µ =
0.5 F (1-f)
For an autosomal recessive disease: µ =
F(1-f)
For an X-linked recessive disease: µ =
0.333 F (1-f)
A mutant allele that is as likely to represented in the next generation as the wild-type allele has a fitness of
1 (f=1)
a mutant allele that causes death or sterility has a fitness of
0 (f=0)