Polar, Parametric and Vector Flashcards
x(t) =
When initial velocity is given
V(0)cos(theta)t + x(0)
y(t) =
When initial velocity is given
0.5gt^2+ v(0)sin(theta)t + y(0)
g = -9.8 m/s^2 or -32ft/s^2
dy/dx =
Given x(t) and y(t)
(dy/dt)/(dx/dt)
Same thing with theta instead of t
d^2y/dx^2
Given x(t) and y(t)
((dy/dx)’)/(dx/dt)
Arc length from t1 to t2
Given x(t) and y(t)
integral from t1 to t2 of sqrt((dx/dt)^2 + (dy/dt)^2)
What does this derivative tell you?
dx/dt
The gives the horizontal velocity of the — at time t
What does this derivative tell you?
dy/dt
This gives the vertical velocity of the — at time t
What does this derivative tell you?
dy/dx
This gives the slope of the curve/path the — takes/travels on
Speed
When you have a vector
abs(sqrt((x’(t))^2 + (y(t))^2)
This is just the length of the velocity vector
Area under a parametric equation
From t1 to t2
integral from t1 to t2 of (y(t) * (dx/dt))
Period of a circle
pi
Period of a limaçon
2pi
Period of a rose curve
2pi/n for odd petals
pi/n for even petals
n = number of petals
Convert Cartesian to Polar
x=
rcos(theta)
Convert Cartesian to Polar
y=
rsin(theta)