Physics Mechanical Properties of Matter Flashcards

1
Q

Give the dimensional formula of Stress

A

The dimensional formula of stress is ML^-1T^-2

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2
Q

Define Longitudinal Strain

A

Longitudinal Strain or Tensile Strain is defined as the ratio of change in length to the original length of the body.
Longitudinal Stress is given by ΔL/L

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3
Q

Define Shearing or shear strain

A

Shear Strain is defined as angular deformation produced under the action of tangential forces.

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4
Q

Define Volumetric Strain

A

Volumetric Strain is defined as the change in volume per unit original volume of a body without any change in its shape.
Volumetric Strain = ΔV/V

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5
Q

Draw the graph of the behaviour of a wire under increasing load and also explain it explicitly

A

Consult the book, bhai.

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6
Q

Give the 3 types of Modulus of Elasticity corresponding to the strain

A

The 3 types of the modulus of elasticity corresponding to strain are as follows:

(i) Corresponding to Longitudinal Strain, we have Young’s Modulus
(ii) Corresponding to Volume Strain, we have Bulk Modulus
(iii) Corresponding to Shear Strain, we have Modulus of Rigidity

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7
Q

Define Young’s Modulus

A

Young’s Modulus is defined as the ratio of longitudinal stress to the corresponding strain produced, within elastic limits.

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8
Q

Give the Formula of Young’s Modulus

A

Stress = F/A
Strain = l/L
Now, Young’s Modulus = Tensile Stress / Tensile Strain
= (F/A) / (l/L) = FL/Al
This relation holds good for compressive as well as extensive stress. Since strain has no unit being a ratio, hence Young’s Modulus has the same unit as stress i.e N/m²

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9
Q

Give the formula of Bulk’s Modulus

A

K = P/(-v/V) = -PV/v
The negative sign indicates that by an increase in pressure a decrease in volume occurs
The only stress which a liquid or a gas can permanently sustain is hydrostatic pressure. Hence, the Bulk Modulus is the only elastic modulus that can be experienced by liquids i.e Hydrostatic Pressure. It has the same unit as pressure

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10
Q

Whats Compressibility?

A

The reciprocal of bulk modulus of a substance is called Compressibility.
Compressibility = 1/K = -(v/V)/P

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11
Q

Define Poisson’s Ratio

A

Within elastic limit, there is a complete proportionality between the lateral strain and longitudinal strain, the ratio of lateral strain and longitudinal strain is constant for a material of a body which is called Poisson’s Ratio.

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12
Q

Derive the Poisson’s Ratio

A

Let us consider a rod has its original diameter and length as D and L, respectively and, if an increase in length due to a given longitudinal force is l and reduction in diameter is d, then Poisson’s ratio is given as
σ = (d/D)/(l/L) = (Ld)/(lD)
or
σ = (L/D) dD/dL

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13
Q

Give the two equations equating the 4 elastic constants

γ, K, η, and η

A

The two equations are as follows:
γ = (9ηK) / (3K+η)

and

σ = (3K-2η) / (6K+2η)

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14
Q

Prove that Shearing Shearing Stress is equivalent to an equal Linear Tensile Stress and equal Compressive Stress at right angles to each other

A

Consult the book,bhai.

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15
Q

Derive the relation between γ, K and σ

A

Consult the book, bhai.

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16
Q

Derive the relation between γ, η and α

A

Consult the book, bhai.

17
Q

Derive the relation between Y, K and η

A

Consult the book, bhai.

18
Q

Derive the relation between K, η and σ

A

Consult the book, bhai.

19
Q

Give the limiting values of Poisson’s Ratio

A

We know, 3K(1-2σ) = 2η( 1 + σ)
Since K and η are essentially positive quantities , hence
1. If Poisson’s ratio (σ) is a positive quantity , the both sides of the above equation must be positive, which is possible only when (1-2σ) > 0 ⇒ σ<1/2 or 0.5
2. If Poisson’s ratio(σ) is a negative quantity then the left side of the equation will be positive, It means right hand should also be positive which is possible only when
(1+σ)>0 or σ>-1
Hence, the theoretical value of σ lies between -1 and 0.5 ie -1

20
Q

Define Torsional Pendulum

A

Draw the diagram and describe it a little bit.

21
Q

Give the two uses of Tortional Pendulum

A

The Two uses of Torsional Pendulum are as follows:

(i) Determination of Moment of Inertia of an irregular body
(ii) Determination of Tortional Rigidity

22
Q

Explain using derivation how the moment of inertia of an irregular body is found out

A

Consult the book, bhai.

23
Q

Explain using derivation how the Torsional Rigidity is found out

A

Consult the book, bhai.

24
Q

Define a beam

A

A beam is defined as a rod or bar of uniform rectangular or circular cross-section whose length is very large in comparison to its thickness or radius.

25
Q

Give the 4 assumptions taken when studying bending of beam

A

The 4 assumptions taken when studying bending of a beam are as follows:

(i) In comparison to the load( what they can support), their weight is negligible
(ii) Shearing forces are negligible
(iii) Geometrical moment of Inertia of a beam remains the same which means the cross-section of a beam remains unaltered.
(iv) The curvature of the beam is small.

26
Q

Define a cantilever along with its diagram

A

Consult the book bhai.

27
Q

How is Young’s Modulus determined by bending of beam?

A

Consult the book bhai

28
Q

Give the formula using which a Torsion pendulum is used to determine the moment of inertia of an irregular body

A

I2 = I1 x (T²2-T²)/(T²1-T²)