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physics lab final Flashcards

1
Q

What is the physical unit for Volume?

A

m^3

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2
Q

How many significant figures in 78.9 plus-or-minus 0.2?

A

3

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3
Q

How many significant figures are there in 3.788 *10^8

A

4

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4
Q

The radius of a circle is 10.5 space plus-or-minus space 0.5. What is the area?

A

346+-33

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5
Q

The radius of a circle is 10.5 space plus-or-minus space 0.5. What is the circumference?

A

65.9+-31

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6
Q

A caliper is an instrument that measures length (T/F)

A

true

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7
Q

The micrometer is an instrument that measures time (T/F)

A

false

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8
Q

Please look up in the lab manual the density for copper and type it. The physical unit is gr/cm3

A

8.93 g/cm3

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9
Q

In the figure below, part-a shows a block of mass 20Kg hanging from three cords. Figure part-b shows the free body diagram of the system. Which one of the following options reflects the correct relationship between TA and TB?

A

TB=TA cos28/cos47

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10
Q

In the figure below, part-a shows a block of mass 20Kg hanging from three cords. Figure part-b shows the free body diagram of the system. Which one of the following options reflects the correct relationship between TA , TB , and TC?

A

TC=TAsin28+TBsin47

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11
Q

In the figure below, part-a shows a block of mass 20Kg hanging from three cords. Figure part-b shows the free body diagram of the system. Acceleration of gravity is 9.8 m/s2. What is the magnitude of TC?

A

196

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12
Q

In the figure below, part-a shows a block of mass 20Kg hanging from three cords. Figure part-b shows the free body diagram of the system. What is the magnitude of TA?

A

138.4

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13
Q

In the figure below, part-a shows a block of mass 20Kg hanging from three cords. Figure part-b shows the free body diagram of the system. What is the magnitude of TB?

A

179.2

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14
Q

In a two-dimensional tug-of-war, Alex, Betty, and Charles pull on ropes that are tied to an automobile tire. The ropes make an angle with each other as indicated in the figure below part-a, top view. Alex pulls with a force FA (220N) while Charles exerts a force FC (170N). Figure part-b shows a force diagram for this system. What is the correct relationship between FA and FC?

A

FAcos47=FCcos(phi)

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15
Q

In a two-dimensional tug-of-war, Alex, Betty, and Charles pull on ropes that are tied to an automobile tire. The ropes make an angle with each other as indicated in the figure below part-a, top view. Alex pulls with a force FA (220N) while Charles exerts a force FC (170N). Figure part-b shows a force diagram for this system. What is the correct relationship between FA , FB , and FC?

A

Fb=FAsin47+FCsin(phi)

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16
Q

In a two-dimensional tug-of-war, Alex, Betty, and Charles pull on ropes that are tied to an automobile tire. The ropes make an angle with each other as indicated in the figure below part-a, top view. Alex pulls with a force FA (220N) while Charles exerts a force FC (170N). Figure part-b shows a force diagram for this system. What are the x-axis (x with hat on top) and y-axis (y with hat on top) components for FA? This is the same as asking for the vectorial notation of FA.

A

FA=-220cos47x+220sin47y

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17
Q

In a two-dimensional tug-of-war, Alex, Betty, and Charles pull on ropes that are tied to an automobile tire. The ropes make an angle with each other as indicated in the figure below part-a, top view. Alex pulls with a force FA (220N) while Charles exerts a force FC (170N). Figure part-b shows a force diagram for this system. What is the value of the angle ϕ?

A

28

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18
Q

In a two-dimensional tug-of-war, Alex, Betty, and Charles pull on ropes that are tied to an automobile tire. The ropes make an angle with each other as indicated in the figure below part-a, top view. Alex pulls with a force FA (220N) while Charles exerts a force FC (170N). Figure part-b shows a force diagram for this system. What is the magnitude of the force that Betty applies?

A

241

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19
Q

Please look at equation 3.2c for your calculation. The mass of planet Mars is 6.42 times space 10 to the power of 23 space left square bracket k g right square bracket and its average radius is 3.40 times space 10 to the power of 6 space left square bracket m right square bracket. Calculate the acceleration of gravity in Mars.

A

3.71

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20
Q

Lets say your weight is 160 pounds. On Earth the equivalent of 1 pound is 4.448222 Newtons. Using physical units of Newtons, What would be your weight in Mars?

Compute your mass in mass in kilograms
Calculate your weight in mars using mars acceleration of gravity

A

269

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21
Q

If you could jump vertically 5 feet on Earth, how high would you be able to jump on planet Mars (in meters)?
Note: 1 ft is 0.3048 m

A

4

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22
Q

When an elevator starts moving up you experience more weight (T/F)

A

T

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23
Q

When an elevator starts moving down you experience less weight (T/F)

A

T

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24
Q

As you enter in an elevator. For you to feel a weight similar to what you would experience in Mars. Which way should the elevator go?

A

down

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25
Q

What should be the magnitude of the acceleration of an elevator so that you experience the weight your would have in Mars?

A

6.1

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26
Q

What is the physical unit of acceleration of gravity?

A

m/s^2

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27
Q

Velocity is change of position in time (T/F)

A

T

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28
Q

Acceleration is change of velocity in time

A

T

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29
Q

Which one of the alternatives below is incorrect.

A

Scalars have magnitude and direction

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30
Q

In an elastic collision kinetic energy is conserved (T/F)

A

T

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31
Q

In an inelastic collision none of the energy is lost. (T/F)

A

F

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32
Q

In a perfectly inelastic collision bodies stick together for a brief moment and then separate from each other so that each one moves with independent and different velocities. (T/F)

A

F

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33
Q

Select the option below that does not indicate a vectorial physical entities.

A

Energy

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34
Q

Ball A, moving at 12 m/s, collides elastically with ball B, initially at rest, as presented in the figure below. Consider both balls have the same mass. What is the initial speed of ball A?

A

12

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35
Q

Ball A, moving at 12 m/s, collides elastically with ball B, initially at rest, as presented in the figure below. Consider both balls have the same mass. What is the magnitude of the final velocity of ball A?

A

6

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36
Q

Two 1-Kg carts with spring bumpers undergo a collision on a frictionless track as shown in the before (initial) and after(final) figures below. Consider the horizontal axis the x-axis. What is the initial linear momentum of the cart that is moving to the right?

A

4x

37
Q

Two 1-Kg carts with spring bumpers undergo a collision on a frictionless track as shown in the before (initial) and after(final) figures below. Consider the horizontal axis the x-axis. What is the total initial linear momentum of the carts?

A

4x-4x

38
Q

Two 1-Kg carts with spring bumpers undergo a collision on a frictionless track as shown in the before (initial) and after(final) figures below. Consider the horizontal axis the x-axis. What is the total final linear momentum of the carts?

A

4x-4x

39
Q

A horizontal rod, see figure below, is 10m long. The rod weights 500.0N and with a center of mass located at C, is 3.00m from point A in the figure below. At point A, a force of 1000.0N acts downward. At point B, a force of 750N acts downward. At point D, 2.00m from point B, a force of 400.0N acts upward. At point E, 1.00m from point A, a force of 750.0N acts upward.

What is the magnitude and direction of the force that must be employed to establish translational equilibrium?

A

1100N, upward

40
Q

A horizontal rod, see figure below, is 10m long. The rod weights 500.0N and with a center of mass located at C, is 3.00m from point A in the figure below. At point A, a force of 1000.0N acts downward. At point B, a force of 750N acts downward. At point D, 2.00m from point B, a force of 400.0N acts upward. At point E, 1.00m from point A, a force of 750.0N acts upward.

Consider point A as a pivot. Consider clockwise torques as negative, and counter clockwise as positive. Remember there is a force with magnitude F that is pointing upward located at some distance $$x$$ from the pivot.

Write the summation of all positive torques.

A

1750+8400+x*F

41
Q

A horizontal rod, see figure below, is 10m long. The rod weights 500.0N and with a center of mass located at C, is 3.00m from point A in the figure below. At point A, a force of 1000.0N acts downward. At point B, a force of 750N acts downward. At point D, 2.00m from point B, a force of 400.0N acts upward. At point E, 1.00m from point A, a force of 750.0N acts upward.

Consider point A as a pivot. Consider clockwise torques as negative, and counter clockwise as positive. Remember there is a force with magnitude F that is pointing upward located at some distance $$x$$ from the pivot.

Write the summation of all negative torques.

A

-3500-10750

42
Q

A horizontal rod, see figure below, is 10m long. The rod weights 500.0N and with a center of mass located at C, is 3.00m from point A in the figure below. At point A, a force of 1000.0N acts downward. At point B, a force of 750N acts downward. At point D, 2.00m from point B, a force of 400.0N acts upward. At point E, 1.00m from point A, a force of 750.0N acts upward.

Consider point A as a pivot. Consider clockwise torques as negative, and counter clockwise as positive. Remember there is a force with magnitude F that is pointing upward located at some distance $$x$$ from the pivot.

From which of the following expressions can you solve for x provided you know the value of F?

A

1750-3500+8400-10750+x*F=0

43
Q

A horizontal rod, see figure below, is 10m long. The rod weights 500.0N and with a center of mass located at C, is 3.00m from point A in the figure below. At point A, a force of 1000.0N acts downward. At point B, a force of 750N acts downward. At point D, 2.00m from point B, a force of 400.0N acts upward. At point E, 1.00m from point A, a force of 750.0N acts upward.

Consider point A as a pivot. Consider clockwise torques as negative, and counter clockwise as positive. Remember there is a force with magnitude F that is pointing upward located at some distance $$x$$ from the pivot.

What is the value of x in meters, provided F equals 1100 N upward?

A

4.59

44
Q

A uniform 200-lb boom, 24ft long, is supported by a cable as shown in the figure below. The boom is hinged at the wall, and the cable makes a 30 to the power of o angle with the boom, which is horizontal. A load of 500lb is hung from the right end.

What is the correct vectorial notation for F with rightwards arrow on top

A

Fcos(theta)x + Fsin(theta)y

45
Q

A uniform 200-lb boom, 24ft long, is supported by a cable as shown in the figure below. The boom is hinged at the wall, and the cable makes a 30 to the power of o angle with the boom, which is horizontal. A load of 500lb is hung from the right end.

What is the correct vectorial notation for T with rightwards arrow on top?

A

-Tcos30x+Tsin30y

46
Q

A uniform 200-lb boom, 24ft long, is supported by a cable as shown in the figure below. The boom is hinged at the wall, and the cable makes a 30 to the power of o angle with the boom, which is horizontal. A load of 500lb is hung from the right end.

Consider Rotational Equilibrium. Consider clockwise torque as negative and counter clockwise torque as positive. What is the correct expression that would help to solve for T subscript y?

Note. You are not converting to Metric System, you are working in English System. Recall that in the English System of units, force is measured in Pounds abbreviated as “lb” and distances are measured in Feet abbreviated as “ft”. In consequence torque is expressed in apostrophe apostrophe f o o t times space p o u n d s apostrophe apostrophe abbreviated as f t times space l b, which is the product of distance and force.

A

-12200-24500+24*Ty=0

47
Q

A uniform 200-lb boom, 24ft long, is supported by a cable as shown in the figure below. The boom is hinged at the wall, and the cable makes a 30 to the power of o angle with the boom, which is horizontal. A load of 500lb is hung from the right end.

Considering Translational and Rotational Equilibrium. What is the vertical component of the force exerted by the hindge? Your answer is in pounds.

Note. You are not converting to Metric System, you are working in English System. Recall that in the English System of units, force is measured in Pounds abbreviated as “lb” and distances are measured in Feet abbreviated as “ft”. In consequence torque is expressed in apostrophe apostrophe f o o t times space p o u n d s apostrophe apostrophe abbreviated as f t times space l b, which is the product of distance and force.

A

100

48
Q

A uniform 200-lb boom, 24ft long, is supported by a cable as shown in the figure below. The boom is hinged at the wall, and the cable makes a 30 to the power of o angle with the boom, which is horizontal. A load of 500lb is hung from the right end.

Considering Translational and Rotational Equilibrium. What is the horizontal component of the force exerted by the hindge? Your answer is in pounds.

Note. You are not converting to Metric System, you are working in English System. Recall that in the English System of units, force is measured in Pounds abbreviated as “lb” and distances are measured in Feet abbreviated as “ft”. In consequence torque is expressed in apostrophe apostrophe f o o t times space p o u n d s apostrophe apostrophe abbreviated as f t times space l b, which is the product of distance and force.

A

1039

49
Q

In order to calculate centripetal force we have to use Newton’s second law (T/F)

A

T

50
Q

F equals m a is Newton’s First Law. (T/F)

A

F

51
Q

Which of Newton’s Laws of Motion relates to inertial frames?

A

First Law

52
Q

Centripetal Force is tangential to the circumference in a circular motion (T/F)

A

F

53
Q

What produces acceleration in a circular motion?

A

The change in direction of the velocity

54
Q

In a uniform circular motion tangential speed is not constant hence we have acceleration (T/F)

A

F

55
Q

Torque is a vectorial quantity (T/F)

A

T

56
Q

A wrench does not utilize the principles of torque (T/F)

A

F

57
Q

A seesaw in a playground does utilize principles of torques (T/F)

A

T

58
Q

Centripetal acceleration is directed tangentially along the circular motion (T/F)

A

F

59
Q

In Hiook’s Law the relationship between restoring force of the spring and elongation is quadratic., that is, not linear. (T/F)

A

F

60
Q

What is the physical unit of the spring constant, k?

A

N/m

61
Q

The meaning of the negative sign in the restoring force of a spring F equals negative k x is that the force applied by the spring is always against the force exerted on it. (T/F)

A

T

62
Q

The “reference circle” of Simple Harmonic Motion indicates that there is no relationship between circular motion and oscillatory motion. (T/F)

A

F

63
Q

The position as a function of time for mass hanging of a spring is x equals A c o s left parenthesis omega times space t plus ϕ right parenthesis. Consider the veracity of the following statement ``To have a maximum stretch of A at initial time of t equals 0 then the constant ϕ must equal zero’’ (T/F)

A

T

64
Q

The position as a function of time for mass hanging of a spring is x equals A c o s left parenthesis omega times space t right parenthesis. The velocity as a function of time for mass hanging of a spring is v equals negative A omega times s i n left parenthesis omega times space t right parenthesis. Suppose you stretch the spring a certain amount. Consider the veracity of the following statement ``The velocity is maximum possible when you let go of the mass at t equals 0’’

(T/F)

A

F

65
Q

The position as a function of time for mass hanging of a spring is x equals A c o s left parenthesis omega times space t right parenthesis. The acceleration as a function of time for mass hanging of a spring is a equals negative A omega squared times c o s left parenthesis omega times space t right parenthesis. Suppose you stretch the spring a certain amount. Consider the veracity of the following statement ``The acceleration is maximum possible when you let go of the mass at t equals 0’’ (T/F)

A

T

66
Q

The total Mechanical Energy of a spring is 1 half k A squared (T/F)

A

T

67
Q

In a vertically oscillating spring from which a mass is attached to, the kinetic energy is at a maximum possible value when when the spring is stretched the most. (T/F)

A

F

68
Q

In a vertically oscillating spring from which a mass is attached to, the total mechanical energy of the system is constant, that is, it does not change regardless at what oscillating point the mass is at.

A

T

69
Q

A standing wave does not have an stationary appearance and a standing wave does propagate (T/F)

A

F

70
Q

A node is characterized by zero-amplitude (T/F)

A

T

71
Q

An antinode is characterized by maximum-amplitude (T/F)

A

T

72
Q

A specific sinusoidal wave traveling along a taut string is modeled by the equation:

y left parenthesis x comma t right parenthesis equals 3.27 times space 10 to the power of negative 3 end exponent times space c o s left parenthesis 72.1 x minus 2.72 t right parenthesis

What is the amplitude of this wave?

A

0.00327

73
Q

A specific sinusoidal wave traveling along a taut string is modeled by the equation:

y left parenthesis x comma t right parenthesis equals 3.27 times space 10 to the power of negative 3 end exponent times space c o s left parenthesis 72.1 x minus 2.72 t right parenthesis

What is the angular frequency of this wave?

A

2.72

74
Q

A specific sinusoidal wave traveling along a taut string is modeled by the equation:

y left parenthesis x comma t right parenthesis equals 3.27 times space 10 to the power of negative 3 end exponent times space c o s left parenthesis 72.1 x minus 2.72 t right parenthesis

What is the wavenumber of this wave?

A

72.1

75
Q

A specific sinusoidal wave traveling along a taut string is modeled by the equation:

y left parenthesis x comma t right parenthesis equals 3.27 times space 10 to the power of negative 3 end exponent times space c o s left parenthesis 72.1 x minus 2.72 t right parenthesis

What is the velocity this wave?

A

0.038

76
Q

The speed of a traveling transverse wave in a stretched string is given by square root of T over mu end root. Provided the Tension is 2 Newtons and the linear density of the string mu equals 0.5 K g divided by m What is the speed of the wave?

A

2

77
Q

The frequency for a given number of antinodes, n, in a string is given by f subscript n equals fraction numerator n over denominator 2 L end fraction times square root of T over mu end root, where L is the length of the string, Provided the Tension is 2 Newtons, the linear density of the string mu equals 0.5 K g divided by m, the length of string is 1meter, and number of antinodes equal to 1. What is the frequency of the wave?

A

1

78
Q

The frequency for a given number of antinodes, n, in a string is given by f subscript n equals fraction numerator n over denominator 2 L end fraction times square root of T over mu end root, where L is the length of the string, Provided the Tension is 2 Newtons, the linear density of the string mu equals 0.5 K g divided by m, the length of string is 1meter, and number of nodes equal to 2. What is the frequency of the wave? Note that the statement does not provide the number of antinodes but the number of nodes.

A

1

79
Q

Which one of the following is a correct unit for Latent Heat?

A

cal/gr

80
Q

The Latent Heat of Vaporization of water L=540 gr/cal. If 300 grams of water went from room temperature of 22oC to 50oC in the calorimeter, how much steam (expressed in grams) would be produced?

A

0

81
Q

If a metal block initially at 22oC with a mass of 150gr were dropped from a height of 6m into 250gr of water in a container. Water is also initially at 22oC and assume the container absorbs no heat. What would be the change in temperature in the water? Note: you are not answering for the final temperature of the water but for the change from 22oC. Note: use the conversion relation 1 cal = 4.186 Joule in your calculation.

A

0.0084

82
Q

When you calculate for the heat necessary for a phase change such from water to steam, you don’t need a temperature in your calculation (T/F)

A

T

83
Q

When you calculate for heat (energy transfer) that is not a phase change you need the initial and final temperatures in your calculation. (T/F)

A

T

84
Q

When ice at zero degrees (oC) melts to water at zero degrees (oC) it is what we call a Phase Change (T/F)

A

T

85
Q

Joule/Kg is not a unit for specific heat (T/F)

A

T

86
Q

Check the Specific Heats Table provided in your laboratory manual and type the value for Iron from the fraction numerator c a l over denominator g r to the power of o C end fraction column.

A

0.107

87
Q

Please convert 10.76 fraction numerator c a l over denominator g r to the power of o C end fraction to units of fraction numerator J over denominator K g to the power of o C end fraction

A

45041

88
Q

Suppose you have the same mass of water and brass, please see table in laboratory manual. Please consider the veracity of the following statement “More energy is required in brass than in water to change the temperature by one degree Celsius. (T/F)

A

F

Biolology (7 decks)

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