Physical Quantities (Theory) Flashcards
Solve: P = ab^n
ln P = ln a + ln b^n
ln P = ln a + n ln b
ln p = n ln b + ln a
This has the same structure as
y = mx + c
Solve: P = ca^b
ln P = ln c + ln a^b
ln P = ln c + b ln a
ln p = b ln a + ln c
This has the same structure as
y = mx + c
Solve:
F = K α ρ V
K = 6π
α = Length
ρ = Density
V = Speed
Force = mass • acceleration
Force = kgms^-2
Force = MLT^-2
α = L
ρ = ML⁻³
V = LT⁻¹
F = k αˣ ρʸ vᶻ
M¹ L¹ T⁻² = k Lˣ (ML⁻³)ʸ (LT⁻¹)ᶻ
M¹ L¹ T⁻² = Lˣ Mʸ L⁻³ʸ Lᶻ T ⁻ᶻ
M¹ L¹ T⁻² = Mʸ Lˣ ⁺ ⁻³ʸ ⁺ ᶻ T ⁻ᶻ
Y = 1
-z = -2 > divide (-) on both sides > z = 2
1 = x + (-3y) + z
1 = x + (-3(1)) + (2)
1 = x - 3 + 2
1 = x -1 > add one on both sides
2 = x
Since x = 2, y = 1, and z = 2
F = k αˣ ρʸ vᶻ
Then:
F = k α² ρ v²
F = 6π α² ρ v²