PHYS BRITTON Flashcards
if a question asks for non active nmr nuclei, what are we looking for?
even numbers because to be spin active we need odd numbers of electrons. HOWEVER 2h is an exception as this can be NMR active
magnetic moment of spinning nucleus
u = yP
mag moment = magnetogyric ratio x angular momentum
nb p = I
formula for orientations of spin states in a mag field
2I +1
Energy associated with each state =
- (mhyB0) / (2pi)
where m = state eg 1/2 or -1/2
Energy ( that we need to apply to cause NMR signal) =
delta E = hv = hbar x y x Bo = hyBo/2pi
order of energy levels in nmr dependent on … (2)
m and y
larmor freq is defined as ….
frequency at which a nucleus precesses
larmor frequency dependent on (2)
strength of magnetic field Bo
and magnetogyric ratio y
larmor freq (rad s-1) =
w = -y Bo
larmor freq (Hz)
v = -yBo/ 2pi
why does H nmr have higher signal and senistivity than c nmr?
because magnetogyric ratio of H (yH) > yC
also signal is effected by natural abundance and 1H = 100% 13C=1%
why is NMR a sensitive technique compared to other soectroscopies?
because the gap between the energy levels is small
spin up nuclei have m =
1/2
spin down nuclei have m =
-1/2
what has higher/ lower energy, spin up or spin down nuclei?
spin up lower (alpha)
spin down higher (beta)
eqn for boltzmann distribution of spin up ans spin down nuclei =
N1/2
——– = e ^(deltaE/KT)
N -1/2
eqn for contribution to nmr =
dif in population of spin up spin down / total polulation
how do stronger magents affect population difference and thus intensity of signal?
Stronger magnets , bigger population difference, more signal, more intense signal
how do stronger magnets effect resolution?
higher field strength gives better resolution
eigenvalues for hamiltonian operator for ψ-1/2?
opposite sign because hamiltonian operator is negative
eigenvalue = 1/2yHbarBo
eigenvalues for hamiltonian operator for ψ1/2?
opposite sign because hamiltonian operator is negative
eigenvalue = -1/2yHbarBo
how can population of energy levels be changed?
by applying larmor frequency
what effect does a 90 degree pulse have on spin populations?
there is no difference in spin populations after a 90 pulse - populations of spin up and spin down are equal
what effect does a 180 pulse have on spin populations?
spin populations are inverted , so there are now more spin down than spin up
Mo now points down -z axis
Angle of an Rf pulse determined by (2)
its power (B1)
its duration (tp)
equation for angle of rf pulse =
theta (angle) = (360y/2pi) x B1Tp
what effect does doubling the duration of a 90 degree pulse have?
you get a 180 degree pulse
where does magnetisation point after a 90 y pulse
along x axis (Mx)
where does magnetisation point after a 90 x pulse
down the y axis (My)
what is the reference point for nmr ?
TMS usually at 0
what is free induction decay
the oscillating voltage induced by the magnetisation vector the coil
what effect does amount of magnetisation in transverse axis (x) have on intensity of nmr signal
they are linked. the more magnetisation in the transverse axis(x) , the stronger the nmr signal
maxiumum intensity is when the magnetisation vector is where?
on the x axis
The chemical shift, , for a peak in a 1H NMR spectrum is 3.5 ppm. What is the
difference in frequency between this peak and TMS (at 0 ppm) on a 500.4 MHz
spectrometer?
omega = v-vo (Hz)
delta = (v-vo)/vo x 10^6
delta = omega/vo x 10^6
delta x vo = omega x 10^6
(delta x vo) / 10^6 = omega
3.5 x 500.4 / 10^6 = omega mhz
we need to consider changing 500.4MHz to Hz
(3.5 x 500.4 x 10^6 )/ 10^6 = omega Hz = 1751.4 Hz
A: 1751.4 Hz
The chemical shift, , for a peak in a 1H NMR spectrum is 8.1 ppm. If the transmitter
frequency is set to 0 = 400.4 MHz, what is the offset frequency, , for this peak?
omega = v-vo (Hz)
delta = (v-vo)/vo x 10^6
delta = omega/vo x 10^6
delta x vo = omega x 10^6
(delta x vo) / 10^6 = omega
8.1 x 400.4 / 10^6 = omega mhz
we need to consider changing 400.4MHz to Hz
(8.1 x 400.4 x 10^6 )/ 10^6 = omega Hz = 3243.2 Hz
treu or false
The Larmor frequency for a nucleus is proportional to the strength of the static
magnetic field B0.
true
true or flase
NMR signal intensity is dependent on population diff between spin states
true
true or false
j cpupling is dependent on field strength
false
true or false
line width of a peak in a nmr spectrum is dependent on the t2 relaxation time of the protons accociated with that peak
true
true or false
spin spin coupling is repsonsible for peak splitting in nmr spectrum
true
photons from which region of EM spectrum will most liekly induce a rottional transition ?
microwave
List, in order of energy (highest to lowest), the energy levels for the 17O nucleus in a
static magnetic field.
Y (
17O) = −36.26 106
rad s−1 T−1
I = 5/2
amount of levels = 2i+1 = 6
usually we have positive values of gamma and lowest energy is positive eg 1/2m lowest then -1/2 m for I=1/2
however, here we have a rare case where gamma is positive so this trend is flipped
therefore lowest energy = -5/2 for I=5/2
therefore highest to lowest energy =======
m5/2, m3/2, m1/2, m–1/2, m–3/2 m–5/2
true or false
The Larmor frequency is in the MHz range for superconducting NMR
magnets.
true
true or flase
the nmr signal is stored in KHZ
true