Phys And Optical Characteritisics Of Lenses 3 Flashcards
Find the vertical prism induced in the right eye when a patient looks 10mm below the optical center of the following lens
OD +2.00 -1.50x 135
Do the power cross and find where it is at 90
- 25BU
- 25x10/10=1.25
A binconvex lens is clocked with the following properties: Sag of front surface=4.5mm Sag of back surface=3.2mm Diameter=44mm N=1.50 What is the power of each lens surface?
F=(2(n2-n1)S/(h^2)
- 298D
- 6D
Remember to change the -6.6 to a plus since it is BICONVEX
Using the lens clock to differentiate between progressive and single lens
After initial measurement, lens clock can be oriented along the vertical meridian to check for variance in power across the front surface
Total power of the lens when read from a lens clock
Sum of the front and back surface powers, however, this ignores thickness. Can cause the back vertex power of plus Rx to be underestimated when adding surface powers
Lens thickness
Describes the edge or center thickness of a spectacle lens
Minus lens thickness
Thicker in the periphery than the center
A fixed center thickness
Plus lens thickness
Thicker in the center than edges
A fixed peripheral thickness
Approximate sag formula
S=h^2/2r
What equation is used to estimate the sag from the surface power without calculating radius
S=(Ph^2)/(2(n-1))
Front surface sag
S-(PH^2)/(2000(n-1))
Back surface sag power
(PH^2)/(2000(1-n))
What sign are Tc and Te always
Positive
If there is a flat surface, than S1 or S2 will be
0
Change in thickness for plus lenses
It is positive. Center thickness is greater than edge thickness
- h is half the lens diameter
- BC or lens form have no impact on this formula
-5.00D N=1.6 Diameter=56mm Center thickness=1.5mm Calculate edge thickness
-5x28^2/2000(1.6-1)=-3.3mm
Must make it positive so it is 3.3mm
3.3+1.5=4.8mm
Calculate maximal edge thickness Rx=-2.00 -2.00 X 146 Center thickness=2mm Diameter=52mm N=1.42 Assume optical center is at geometric center
Want the thickest to be at the highest power meridian so doing a lens cross, what would make -4.00 our highest meridian
(-4.00(26^2))/(2000(1.42-1))=-3.219
Make it positive 3.219
3.219+2=5.219