Phys And Optical Characteritisics Of Lenses 3 Flashcards
Find the vertical prism induced in the right eye when a patient looks 10mm below the optical center of the following lens
OD +2.00 -1.50x 135
Do the power cross and find where it is at 90
- 25BU
- 25x10/10=1.25
A binconvex lens is clocked with the following properties: Sag of front surface=4.5mm Sag of back surface=3.2mm Diameter=44mm N=1.50 What is the power of each lens surface?
F=(2(n2-n1)S/(h^2)
- 298D
- 6D
Remember to change the -6.6 to a plus since it is BICONVEX
Using the lens clock to differentiate between progressive and single lens
After initial measurement, lens clock can be oriented along the vertical meridian to check for variance in power across the front surface
Total power of the lens when read from a lens clock
Sum of the front and back surface powers, however, this ignores thickness. Can cause the back vertex power of plus Rx to be underestimated when adding surface powers
Lens thickness
Describes the edge or center thickness of a spectacle lens
Minus lens thickness
Thicker in the periphery than the center
A fixed center thickness
Plus lens thickness
Thicker in the center than edges
A fixed peripheral thickness
Approximate sag formula
S=h^2/2r
What equation is used to estimate the sag from the surface power without calculating radius
S=(Ph^2)/(2(n-1))
Front surface sag
S-(PH^2)/(2000(n-1))
Back surface sag power
(PH^2)/(2000(1-n))
What sign are Tc and Te always
Positive
If there is a flat surface, than S1 or S2 will be
0
Change in thickness for plus lenses
It is positive. Center thickness is greater than edge thickness
- h is half the lens diameter
- BC or lens form have no impact on this formula
-5.00D N=1.6 Diameter=56mm Center thickness=1.5mm Calculate edge thickness
-5x28^2/2000(1.6-1)=-3.3mm
Must make it positive so it is 3.3mm
3.3+1.5=4.8mm
Calculate maximal edge thickness Rx=-2.00 -2.00 X 146 Center thickness=2mm Diameter=52mm N=1.42 Assume optical center is at geometric center
Want the thickest to be at the highest power meridian so doing a lens cross, what would make -4.00 our highest meridian
(-4.00(26^2))/(2000(1.42-1))=-3.219
Make it positive 3.219
3.219+2=5.219
Calculate center thickness Rx=+5.00 -2.00 x 49 Minimum edge thickness=2mm Diameter=69mm N=1.7 Assume optical center is at geometric center
+5.00 is our highest power meridian based on the lens cross
+5(34.5^2)/2000 (1.7-1)=4.25
4.25+2= 6.25mm
What are the 3 factors affecting lens thickness
Lens power
Lens diameter
Refractive index
Lens power and lens thickness
As lens power increases, thickness increases
Lens power and RI
As RI increases, thickness decreases
Eyesize and lens thickness
If eyesize increases, thickness increases
Base curve and thickness
increased BC increases thickness
Changing the base curve for a -8D lens will not change
The amount of light from the front surface
-it will change the edge lens thickness, the retinal image size, the oblique astigmatism
Rx=-5.00 -4.00 x 45
N=1.65
Diameter=54mm
Central thickness=1mm
What is the power in the horizontal meridian?
What is the thickness at the temporal edge?
P=S+C(sintheta)^2
-5+(-4x0.5)=-7.00D x 180
- 7(27^2)/2000 (1.65-1)
- 3.9mm
3. 9mm+1MM=4.9mm