Pharmacology- Plested Flashcards
name the main receptor types
- ionotropic (ion channel and electrochemical gradient)
- metabotropic (G protein cascade activation)
- TyrK (phosphorylated)
- nucleotropic
a modulator…
a. binds and activates receptor
b. binds at a different site from agonist, does not activate it but changes the response of the drug-receptor complex
c. blocks receptor
d. increases transcription of receptor
b
what is ‘on-rate’ K-on?
the second order rate at which a drug binds to receptor. limited by diffusion to be ≤10^8. in order to get the forward rate–> multiply by concentration
–> the on-rate depends on the concentration of the drug
what is the ‘off-rate’ K-off?
the first order rate at which a drug unbinds from receptor. It is the inverse of the life time of the drug-receptor complex. the off rate is independent of concentration but it is dependent on the time the drug acts on the receptor;
- units 1/s
the difference between K-on and K-off is…
a. K-on is independent of concentration and K-off is dependent on concentration.
b. K-on is dependent on concentration and K-off is independent of concentration, but is depending on the time the drug acts on the receptor
c. both K-on and K-off are dependent on drug concentration, bur K-on is a measure of the drug affinity
d. K-off depends on number of available receptors and K-on depends on drug concentration
b
What is the dissociation constant - Kd?
- the ratio between K-off/K-on –> (K-1)/(K+1) (in Molar)
agonist Kd- Ka
antagonist Kd- Kb
why is the dissociation constant Kd is K-off/K-on?
it is the ratio between K-off/K-on because if it were the other way around we would get units of 1/M which is hard to understand in terms of drug potency.
what is the Hill-Langmuir equation? (equation + meaning), where did it originate ?
- originally: y= (N/(k’ +kN)) -M –> which is a rectangular hyperbola;
with: y= the response ; N= nicotine concentration ; M= threshold ; k and k’ are constants. - the Hill Langmuir equation is an extreme case of the equation above–> It describes the fraction of the occupied receptors as depending on the concentration of the agonist [A] and Kd.
Therefore:
Par = Pr * ([A]^n/(Kd +[A]^n)) –> n is the Hill Slope; Par is the bound receptor and drug; Pr = free receptor
–> the response Par is the response of the unbound receptor to the concentration of [A]
the Hill-Langmuir equation…
a. the Hill-slope n indicates the the number of binding sites
b. indicates the efficacy of the agonist
c. is purely empirical, and doesn’t tell us how receptor work
d. gives information about the binding affinity
c
describe the 3 state model
the 3 state model says that we much have at least 3 states of drug-receptor interaction:
- A + R- receptor is vacant, and agonist is unbound
- AR- agonist is bound to receptor –> formation of the drug receptor complex but it is inactive
- AR*- drug-receptor complex is active
competitive antagonism…(which answer is WRONG?)
a. a competitive antagonist binds at the same site as the agonist
b. low affinity antagonist unbinds quickly from receptor so agonist can bind
c. the potency of antagonist can be determined by the time it stays bound to receptor
d. only if the receptor is constitutively active in the absence of ligand the antagonist can work
e. it is hard to determine the difference between a weak partial agonist and a competitive antagonist
d
which of the following statements is true?
a. the affinity of a true competitive antagonist can be understood using the Schild method
b. the affinity of a true competitive antagonist can be better understood using the Hill equation or IC50
a
what is the Schild equation?
r = 1+ ([B]/Kb)
with: r= dose ratio; [B] antagonist concentration; Kb= inhibition constant, the concentration of B that inhibits the max. response by 50%
the Schild method…(which answer is WRONG?)
a. is independent of choice of agonist
b. enables us to obtain a microscopically correct binding constant Kb from any experiment
c. can be used to classify receptors in different tissues
d. is a null method
e. can be used to determine the quality of both competitive and non-competitive (irreversible) antagonist
e
what are the essential postulates of the Schild method?
- equal response: receptor response only depends on the mean occupancy of the receptor by the agonist
- exclusive bunding: the binding of a competitive antagonist and agonist are mutually exclusive
- binding only: antagonist binding doesn’t alter the shape of the receptor
- equal affinity: if there are multiple sites, then B has the same affinity at all sites
- equilibrium: measurements are made at equilibrium