Peter Knowles Flashcards

1
Q

Isogyric

A

describes a chemical reaction in which the number of electron pairs is conserved

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2
Q

isodesmic

A

describes a chemical reaction in which the numbers of each type of chemical bond are
all equal for reactant and product. This means not only distinguishing C – C bonds from C – H,
but also counting separately single, double and triple bonds.

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3
Q

Why is there a large difference between the HF and MP2 atomisation energies

A

There is much more electron correlation energy in the molecules than in the atoms, because
in the atoms there are a number of unpaired electrons that do not have opposite-spin correlation.
Consequently, Hartree-Fock strongly underestimates the dissociation energy. MP2 improves on HF method by adding electron correlation effects

cc-pVTZ contains more functions than cc-pVDZ, therefore a larger fraction of the correlation energy
is recovered.

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4
Q

Explain why a DFT electronic structure method is more appropriate for this problem
than (i) Hartree-Fock; (ii) CCSD(T).

A

Hartree-Fock misses electron correlation effects; CCSD(T) includes them, but would be far too expensive.

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5
Q

Would you expect DFT to predict an activation energy for this reaction that is too high or
too low?

A

Like Hartree-Fock, DFT does not dissociate covalent bonds correctly, with an energy that
goes much too high. Transition state is part of the way towards broken bonds, and so,
compared to the equilibrium geometry, its DFT energy will be too high, i.e. activation energy
overestimated.

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6
Q

Why is the 6-31G(d) basis set appropriate for this study? You should consider the
desirability or otherwise of adopting specific alternatives, including minimal, 6-31G, and
cc-pVQZ sets.

A

Minimal vs 6-31G(d): No possibility for orbitals to grow or shrink; DZ set allows mixture of
diffuse and compact basis orbital.
6-31G vs 6-31G(d): No possibility for orbitals to bend; DZP allows polarisation of d by p.
cc-pVQZ: Would normally be used in CI-like calculations to support good representation of
2-electron wavefunctions, but for just the DFT orbitals it makes not much difference.

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7
Q

Why is there no mention of link atom, or other, termination techniques for the interface
between QM and MM regions?

A

Because there is a natural separation across the non-covalent interactions between solute
and solvent, so no need to cut any covalent bonds.

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8
Q

Variation method

A

Adjust the shape of the orbitals until the energy is as low as possible. These orbitals will be the best ones

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9
Q

Covalent bond

A
  • As H+ approaches H the potential energy goes up
  • At the same time, the Kinetic energy goes down as there is now a larger space for the electron to move. On reducing the kinetic pressure the molecule can then lower its energy further by shrinking
  • Overall potential energy reduction
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10
Q

requirements for basis sets to lower energy

A

shrink, expand and bend

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11
Q

Error in Hartree Fock

A

Error largest when covalent bonds are stretched or pairs of electrons are created or destroyed. This is because correlation is absent in HF.

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12
Q

Method for treatment of electron correlation

A

DFT

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13
Q

What computational method is needed for:

  • Electrostatic
  • Induction
  • Dispersion
A
  • Electrostatic (HF or DFT)
  • Induction (HF or DFT)
  • Dispersion (correlated wavefunction)

HF and DFT do not represent dispersion interaction at all

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14
Q

Mode of Attraction for and distance dependence:

  • Electrostatic
  • Induction
  • Dispersion
A
  • Electrostatic (orientation dependent R-1/R-3)
  • Induction (Attractive R-4/R-6)
  • Dispersion (Attractive R-6)
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15
Q

Local correlation

A
  • Even HF is quartic scaling because orbitals are delocalised.
  • So all N^4 2e intergrals are non zero and must be calculated and manipulated.
  • Instead mix the orbitals so they are as local as possible, then discard small interactions between orbitals on distant atoms.
  • All methods can be reduced to NlogN
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16
Q

Resource scalling of methods:

  • HF and DFT
  • MP2
  • CCSD
  • CCSD(T)
A
  • HF and DFT (N^4)
  • MP2 (N^5)
  • CCSD (N^6)
  • CCSD(T) (N^7)
17
Q

What method should be used to compute:

-Very large systems where there is a particular spatial region of interest

A

Multiscale modelling (QM/MM)

18
Q

What method should be used to compute:

Large molecule for which ab initio wavefunction computations would be too expensive

A

DFT

19
Q

What method should be used to compute:

Low accurarcy computation

A

DFT

20
Q

What method should be used to compute:

Non-covalent interaction e.g. dispersion

A

correlation wavefunction

21
Q

What method should be used to compute:

Strong correlation effects e.g. breaking chemical bonds

A

correlation wavefunction

22
Q

What method should be used to compute:

Very high accuracy needed

A

correlation wavefunction

23
Q

If using a single wavefunction method

A
  • Standard choice is CCSD(T). Somtimes too expensive and forced to use a MP2 instead (HF with e correlation)
  • Orbital basis set of cc-pVTZ quality should be used, better to use larger basis set and extrapolate to basis set limit
24
Q

An effective way to minimise both basis set and method errors?

A

Use a combination method:

  • Use CCSD(T) is a small basis set
  • Then use MP2 extrapolated to basis set limit
  • Gaussian 2 formalises this
25
Q

Static correlation

A

Structures cannot be described by a single set of MOs

26
Q

Dynamic correlation

A
  • Instantaneous electron-repulsion rather than averaged

- Hartree-Fock averages the fluctuations in shape to give spherical atoms, so no attraction between atoms

27
Q

DFT vs Correlation interaction

A
  • Configuration interaction and related methods can describe electron correlation with high accuracy
  • Density functional theory (DFT) offers similar accuracy for much less computing power
28
Q

DFT problems

A
  • not a variational method

- poor description of van der Waals or dispersion forces

29
Q

first order properties

A

dipole moment

  • first order doesn’t require the evaluation of the perturbed wavefunction
  • Dipole moment can be obtained directly from wavefunction
30
Q

second order properties

A

Nuclear magnetic resonance

  • requires evaluation of a first order wavefunction
  • Computational effort increases linerally with number of perturbations
31
Q

For excited states what method needs to be done?

A
  • Time-dependent linear response theory

- Give the resonant excitation freq for a KS-DFT or CCSD ground state subjected to an oscillating electric field