Pentose Phosphate Pathway Flashcards

1
Q

Pentose Phosphate Pathway

A

The purpose of the pathway is to generate NADPH (reducing power) and 5-carbon sugars

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2
Q

What are the 5-carbon sugars used for?

A

Nucleotide biosynthesis

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3
Q

What is NADPH used for?

A
  1. Used in fatty acid synthesis, nucleotide biosynthesis, steroid synthesis
  2. NADPH detoxifies some compounds for us
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4
Q

Phase 1 of pentose phosphate pathway (oxidative step)

A

Glucose 6-Pi + 2 NADP+ + H2O –> ribulose 5-Pi + 2 NADPH + 2 H+ + CO2

Glucose is oxidatively decarboxylated to form a 5-carbon ketose, generating NADPH and CO2

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5
Q

Phase 2 of pentose phosphate pathway (non-oxidative step)

A

Interconverts sugars among each other. Non-oxidative because no NADPH is produced.

3 ribulose 5-phosphate sugars are rearranged to yield 2 fructose-6-Pi and 1 glyceraldehyde-phosphate. The net reaction is the conversion of three pentoses into two hexoses and one triode.

“3 ribs 2 form 1 gal”
3 ribose-5-P –> 2 fructose-6-P + glyceraldehyde-3-P

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6
Q

Glucose 6-phosphate dehydrogenase

A

The enzyme that catalyzes the first step in the oxidative decarboxylation of glucose 6-Pi.

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7
Q

Regulation of non-oxidative phase

A

Le Chatelier only

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8
Q

The Fate of Glucose 6-Pi

A

Depends on the need for NADPH, Ribose 5-Pi, and ATP

The pentose phosphate pathway can operate in 4 distinct modes that result from various combinations of the oxidative phase, the non oxidative phase, glycolysis, and gluconeogenesis.

  1. Ribose 5-Pi needs exceed the needs for NADPH (there’s a high need for ribose during cell division)
  2. The NADPH and ribose 5-Pi needs are balanced
  3. More NADPH is needed than ribose 5-Pi
  4. NADPH and ATP are both required
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9
Q

Case 1: Need more ribose than NADPH

A

We would run the non-oxidative stage backwards. We need 2 molecules of fructose-6-Pi and 1 molecule of glyceraldehyde-Pi to make ribose. We can get both from the forward reaction of glycolysis.

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10
Q

Case 2: We need ribose and NADPH

A

Any time we need NADPH, we have to run the oxidative phase. The oxidative phase will give us 2 molecules of NADPH and 1 molecule of ribulose, which can be converted easily to ribose.

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11
Q

Case 3: We need more NADPH than ribose

A

Again, we need to run oxidative phase to generate NADPH. We could also run non-oxidative phase forward to generate fructose-6-Pi and glyceraldehyde-Pi

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12
Q

Case 4: NADPH and ATP are both needed

A

Run oxidative phase to generate NADPH. Then run oxidative phase to get fructose-6-Pi and glyceraldehyde-3-Pi, which we can funnel into glycolysis to generate ATP.

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13
Q

Regulation of pentose phosphate pathway

A
  • -Non-oxidative phase is only regulated by Le Chatelier
  • -Oxidative phase regulation:
    1. glucose 6-phosphate dehydrogenase step, the first in the pathway, is the rate-limiting step. It is also the committed step. Once you decarboxylate glucose-6-Pi, you can’t go back.
    2. If NADP+ is in short supply, the pathway cannot run. If you are doing a lot of synthetic reactions, NADP+ would be high in concentration. NADPH competes for the binding site. So if NADPH is high and NADP+ is low, pentose phosphate pathway is inhibited
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14
Q

Tissues using NADPH

A

adrenal glands - steroid synthesis
liver - fatty acid and cholesterol synthesis
testes- steroid synthesis
adipose tissue - fatty acid synthesis
ovaries - steroid synthesis
mammary glands - fatty acid synthesis
red blood cells - maintenance of reduced glutathione

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15
Q

Red blood cells use of NADPH

A

RBC’s are exposed to a lot of oxidations circulating in the blood, so they have a mechanism to neutralize strong oxidation agents using a molecule called glutathione. Glutathione becomes oxidized instead of your proteins or lipids in the membrane and then to get it reduced again so it can do another reaction, NADPh is used.

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16
Q

Where is pentose phosphate pathway located?

A

cytoplasm

17
Q

Glutathione

A

In its reduced form, it’s composed of 3 amino acids linked together (glutamate, cysteine, glycine). The thiol group on cysteine is what is oxidized.

Oxidized glutathione: 2 chains of these amino acids are hooked together by a disulfide bond, which occurs when glutathione is oxidized.

Glutathione must be reduced by NADPH again so it’s available to deal with reactive oxygen species such as peroxides again.

18
Q

hemolytic anemia

A

Occurs when glutathione is lacking in red blood cells. The hemoglobin tends to aggregate, forming Heinz bodies.

Lack of glucose-6-Pi dehydrogenase makes it even more difficult to have functioning glutathione.

19
Q

Evolutionary advantage of lack of glucose-6-Pi

A

Glucose-6-Pi dehydrogenase deficiency protects against malaria by depriving the parasites of NADPH that they require for growth.