Pearly 10

Question 1

Schlesinger’s test depends upon the principle of reaction between urobilin and iodine.

Answer 1

-True

Question 2

The result of Schlesinger’s test is said to be positive if the filtrate exhibits green fluorescence upon exposure to UV light.

Answer 2

-True

Question 3

Chloroform can be used as a substitute for ethanol in the first step of Schlesinger’s test.

Answer 3

-False

Question 4

Formation of green precipitates is the positive result in Schlesinger’s test.

Answer 4

-False (green Fluorescence)

Question 5

Bile pigments interfere in Schlesinger’s test therefore should be removed by filtration.

Answer 5

-True

Question 6

Both urobilinogen and urobilin are yellow-brown pigments.

Answer 6

-False (urobilin - brown pigment)

Question 7

The second step of Schlesinger’s test is to add 1ml urine and 1ml tincture of iodine in a test tube containing the zinc acetate:alcohol solution.

Answer 7

-False (5mL iodine)

Question 8

The first step of Schlesinger’s test is to add and mix 10ml Zinc acetate and 1ml alcohol in a test tube.

Answer 8

-False (1mL Zinc acetate)

Question 9

Urobilin is one of the normal pigments of urine together with urochrome and bilirubin that contribute to the normal color.

Answer 9

-False (Urobilinogen)

Question 10

Some urobilinogen is reabsorbed from the gut into the portal blood and transported into the kidneys, where it is converted into yellow bilirubin and excreted.

Answer 10

-False (yellow urobilin)