PART B Flashcards
According to the Second Law of Thermodynamics, the entropy of the Universe always increases for a spontaneous process. Since entropy S = q/T, heat transfer always occurs from a body of higher temperature to a body of lower temperature because:
the entropic decrease for a hotter body is outweighed by the entropic increase for a colder body.
the entropic increase for a hotter body is outweighed by the entropic decrease for a colder body.
the entropic increase for a hotter body is outweighed by the entropic increase for a colder body.
the entropic decrease for a hotter body is outweighed by the entropic decrease for a colder body.
the entropic decrease for a hotter body is outweighed by the entropic increase for a colder body.
If 14.5 kJ of heat were added to 485 g of liquid water, how much would its temperature increase, given that the specific heat of water is 4.18 J.g-1.K-1?
280 oC
- 15 oC
- 9 oC
none of these
7.15 oC
A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C. What is the specific heat of the substance?
2.56 J.g-1.℃-1
none of these
- 390 J.g-1.℃-1
- 390 J.g.℃-1
0.390 J.g-1.℃-1
Calculate the ΔH for the process:
Sb(s) + Cl2 (g) → SbCl5 (g)
From the following information:
Sb(s) + Cl2 (g) → SbCl3 (s) ΔH = -314 kJ
SbCl3 (s) + Cl2 (g) →SbCl5 (g) ΔH = -80 kJ
- 394 kJ
- 234 kJ
394 kJ
+234 kJ
-394 kJ
Calculate ΔH for the process:
Hg2Cl2 (s) → 2 Hg (l) + Cl2 (g)
from the following information:
Hg (l) + Cl2 (g) → HgCl2 (s) ΔH = -224 kJ
Hg (l) + HgCl2 (s) → Hg2Cl2 (s) ΔH = -41.2 kJ
- 182.8 kJ
- 265 kJ
182. 8 kJ
265 kJ
265 kJ
Calculate the standard molar enthalpy of formation of NO(g) from the following data:
N2 (g) + 2 O2 (g) → 2 NO2 (g) ΔH = 66.4 kJ
2NO (g) + O2 (g) → 2 NO2 (g) ΔH = -114.1 kJ
Hint: be careful because you should calculate the formation for one mole only.
- 180.5 kJ mol-1
180. 5 kJ mol-1
90. 3 kJ mol-1 - 90.3 kJ mol-1
90.3 kJ mol-1
For the species, NaCl, CH4 and CO2, the bonds between the atoms/ions would be respectively:
ionic, polar covalent, non-polar covalent
ionic, non-polar covalent, polar covalent
polar covalent, non-polar covalent, ionic
polar covalent, ionic, non-polar covalent
ionic, non-polar covalent, polar covalent
Explain why the HOH molecule is bent, whereas the HBeH molecule is linear.
The oxygen in water has four pairs of electrons, two involved in bonding with hydrogen, the other two pairs in a non-bonding arrangment. According to VSEPR theory, these four pairs would tend to form a tetrahedral arrangement with bond angles of about 109 degrees to minimize repulsion between these electron pairs.
Explain how a molecule that contains polar bonds can be nonpolar.
As long as the polar bonds are compensated (for example. two identical atoms are found directly across the central atom from one another), the molecule can be nonpolar. For example, for carbon dioxide, the molecule is linear in accordance with VSEPR Theory: O=C=O this means that, although the C=O bonds are polar, because each oxygen pulls with the same amount of force in equal directions, the polarity is effectively cancelled, making the molecule non-polar overall
Which of the following molecules have net dipole moments?
a) CS2
(b) H2Se
(c) CCl2F2
(d) PCl3 (P is the central atom
(b), (c) and (d)
The bond angles between the central nitrogen and hydrogen in ammonium ion and ammonia would be respectively:
107o and 107o
107o and 109o
109o and 109o
109o and 107o
109o and 107o
The molecule XF3 has a dipole moment. Based on this information, X could be:
boron or phosphorus
boron, phosphorus or nitrogen
boron or nitrogen
nitrogen or phosphorus
nitrogen or phosphorus
A spray can is used until it is empty except for the propellant gas, which has a pressure of 1344 torr at 23 oC. If the can is thrown into a fire (T = 475 oC), what will be the pressure in the hot can?
- 40 x 103 torr
- 40 torr
1344 torr
none of these
3.40 x 103 torr
A 2.50 L volume of hydrogen measured at –196 oC is warmed to 100 oC. What is the volume of the gas at the higher temperature, assuming no change in pressure?
740 L
25 L
- 1 L
- 1 L
12.1 L
A weather balloon contains 8.80 moles of helium at a pressure of 0.992 atm and a temperature of 25 oC at ground level. What is the volume of the balloon under these conditions? The Ideal Gas Constant is 0.08206 L atm mol-1 K-1.
0.992 L
217 L
2170 L
100 L
217 L