PART 1 Carbocations Flashcards

1
Q

Hammond Postulate

A

Stability: the more substituents on the carbocation, the more stable the carbocation, and the faster it can form

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2
Q

what can stabilise a carbocation?

A

i
o Inductive effects – 1o, 2o and 3o

o Conjugation – allylic and benzylic

o Heteroatoms – lone pair donation, oxonium/iminium ion

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3
Q

what is sigma congugation

A

sigma bond between c-h can donate e density to a parallel empty p orbital on the carbocation

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4
Q

non bonding allyic structure

A

p——p LUMO

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5
Q

bonding allyic structure

A

HOMO P-P-P

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6
Q

Pi systems

A

p empty orbital overlaps with pi system + e can be delocalised

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7
Q

resonance

A

allows + energy to be delocalise across the system, stabilising it

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8
Q

heteroatoms

A

group 7 or any group with a lone pair can form a pi bond which stabilises the carbocation.

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9
Q

inductive effect

A

, inductive effects occur when the electrons in covalent bonds are shifted towards an nearby atom with a higher electronegativity. In this case, the positively charged carbocation draws in electron density from the surrounding substituents thereby gaining stabilization by slightly reducing its positive charge

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10
Q

how do carbocation react

A

1,2 hydride/alkyl shift
nucleophilic attack
pi bonds

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11
Q

wagner meerwein

A

Relief of strain in the ring expansion from a four- to a five-membered ring makes the alkyl migration
favourable. Despite going from a tertiary carbocation to a secondary one.

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12
Q

what is an aromatic compound?

A
  1. Structure must be cyclic.
  2. Each atom in the ring must have an unhybridized p-orbital.
  3. The structure must be planar to allow for continuous overlap of parallel p-orbitals.
  4. Delocalization of the π-electrons over the ring must result in a lowering of the electronic energy – follows
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13
Q

Huckel’s rule.

A

4n + 2pi

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14
Q

aromatic compound

A

huckel rule
planar
unless with heteroatom, as long it is sp2

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15
Q

antiaromatic

A

4n not huckels law

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16
Q

non aromatic

A

not planar