Parallel Transport and Covariant Differentiation Flashcards
Classical Gravitation
∇²φ = 4πGρ
d’Alembertian
-there is a 4D equivalent for classical gravitation: square = η_μν ∂^ν ∂^μ = (-1/c² ∂²/∂t² + ∇²) -in addition to Newtonian gravity this has an instant response to the presence of a mass, violating relativity
Equivalence Principle Weak Version
-the weak version just says that: ma = mg -i.e. can’t distinguish gravity form any other form of acceleration -BUT g can’t be the same everywhere, this leads to the idea of a local inertial frame, a frame which is not accelerating
Equivalence Principle Einstein’s Variant
-all laws of physics will be the same in all inertial frames -this is expressed using tensor relationships
Local Inertial Frame Definition
-frame which is not accelerating -at a point there is no acceleration -in local coordinates, ε^α, we therefore have: d²ε^α/dτ² = 0 AND ds² = η_αβ dε^α dε^β
Local Inertial Frame General Metric
g_μν(x) = η_αβ dε^α/dx^μ dε^β/dx^ν -symmetric
Local Inertial Frame Generic Line Element
ds² = g_αβ dx^α dx^β
The Geodesic Equation
Γ^ν_αβ = ∂x^ν/∂ε^μ ∂²ε^μ/∂x^α∂x^β -where Γ^ν_αβ is a connection coefficient
What properites do we need in a metric for GR?
-LIF must exist: gμν -> ημν locally by coordinate transformation (where g is general metric and η is the LIF metric) -g_μν must exist, a Riemannian manifold -the line element ds²=g_μν dx^μd x^ν must exist -the connection coefficients, Γ, must exist -if a tensor relation in the LIF is true, it must be true everywhere
Transformation
V^’μ = ∂x^’μ/∂x^ν V^ν
- ∂x^’μ/∂x^ν is NOT a Lorentz transform since ∂²x^’μ/∂x^α∂x^β does not equal zero
- ∂x^’μ/∂x^ν is a function of position
- as long as ∂x^’μ/∂x^ν is not a singular transformation (inverse exists), 4-vectors and 1-forms behcave as normal
Derivative of Scalars
φ_,μ = ∂φ/∂x^μ
-well-behaved because φ has no direction
Derivatives of A^μ
A^μ_, is not well-behaved since ∂²x^’μ/∂x^α∂x^β is not zero
Derivative of A_
∂A_/∂x^β = ∂/∂x^β [A^α e_α]
-use product rule:
= ∂A_/∂x^β e_α + A^α ∂e_α/∂x^β
-define: ∂e_α/∂x^β = Γ^μ_αβ e_μ
=>
∂A_/∂x^β = [A^α_,β + A^μ Γ^α_μβ] e_α
-since e_α is the basis the stuff in the brackets must e
Covariant Derivative
A^α_;β = A^α_,β + A^μ Γ^α_μβ
Covariant Derivative of Scalar
-we make the CHOICE that:
φ_;μ = φ_,μ
-since this makes physical sense (φ has no direction)