Paper 4 Flashcards
Arene
Hydrocarbon containing one or more benzene ring
Why does Kekule’s proposed ring not work?
- Doesn’t react like alkenes eg does not decolourise bromine without a catalyst - no electrophilic addition
- Bond lengths - X-ray crystallography shows all bond lengths are equal when double bonds are actually shorter than single bonds
- Hydrogenation of benzene is less exothermic than expected (-360 vs -208) suggesting benzene is actually more stable
How is bromobenzene formed?
Benzene + Br2 + AlBr3 (halogen carrier)
AlBr3 + Br2 > AlBr4- + Br+ (electrophile)
H+ + AlBr4- > AlBr3 + HBr
ELECTROPHILIC SUBSTITUTION
How is nitrobenzene formed?
Benzene + c.HNO3 + c.H2SO4 Reflux 50degrees Higher temp = further subst. H2SO4 + HNO3 > H2NO3+ + HSO4- H2NO3+ > NO2+ + H2O H+ + H2SO4 > H2SO4 ELECTROPHILIC SUBSTITUTION
Describe the bonding in benzene
Each carbon forms 3 sigma bonds
1 electron left in a p-orbital on each carbon
P-orbitals overlap to form a delocalised pi-system
Electrons are delocalised above and below ring
C-C bond lengths equal
Ring is planar
Compare the reactivity of benzene and cyclohexene (alkene)
Benzene is less reactive towards bromine (needing a catalyst)
The delocalised pi-system means the electrons are spread out
So benzene has a lower electron density than a double bond in which the pi-electrons are localised
Therefore is less attractive to electrophiles and is less able to polarise them
Why does benzene undergo substitution and not addition?
The delocalised pi-system means the electrons are spread out
This reduces repulsion between them and gives benzene extra stability
Substitution allows the delocalised pi-system to be retained
Addition would permanently disrupt the delocalised pi-system
Compare the reactivity of benzene and phenol
Phenol is more reactive than benzene eg does not need a catalyst to react with bromine
In phenol the ring is activated
The lone pair of electrons in a p-orbital on the oxygen is delocalised into the ring
This increases the electron density in the ring
Making it more attractive to electrophiles and more able to polarise them
How is 2,4,6-tribromophenol formed?
Phenol + 3Br2
Br+ + Br- > 3HBr
White ppt - orange bromine decolourises
How is sodium phenoxide formed?
Phenol + NaOH
Phenol + Na > + 1/2 H2
Phenol uses
Antiseptic, disinfectants, detergents, preparation of aspirin
WEAK ACID
Primary amine
A H atom on ammonia has been replaced by an alkyl or aryl (R) group > RNH2
How do amines react?
WEAK BASES
So react with acids > salts
How do you prepare an aliphatic amine?
NUCLEOPHILIC SUBSTITUTION
CH3CH2CH2Cl + NH3 > CH3CH2CH2CH2NH2 + HCl
Propylamine
Aliphatic
In a chain
Aromatic
Contains a benzene ring
How do you prepare an aromatic amine?
Nitrobenzene + Sn + c.HCl
Heat under reflux with [H]
Synthesis of diazonium salt
Phenylamine + Nitrous acid (Sodium nitrite and XS HCl)
Less than 10degrees
NaNO2 + HCl > HNO2 + NaCl
Synthesis of an azo dye
Diazonium salt + phenol in alkaline conditions (>Sodium phenoxide)
Azo group = N=N
Bright orange ppt
Used as a dye in paints
Aldehyde
RCHO
-al
Ketone
R’COR
-one
Alkyl
Alkane with a H atom removed
Aryl
Cyclic compound containing benzene ring
Oxidation of a primary alcohol
ROH + [O] > RHO + H2O
Heat gently and distill
Acidified potassium dichromate (Cr2O72-/H+; K2Cr2O7 + H2SO4; orange > green Cr3+)
Oxidation of an aldehyde
RHO + [O] > ROOH + H2O
Heat under reflux
Acidified potassium dichromate (Cr2O72-/H+; K2Cr2O7 + H2SO4; orange > green Cr3+)
Oxidation of a secondary alcohol
RCOHR’ + [O] > RCOR’ +H2O
Heat gently
Acidified potassium dichromate (Cr2O72-/H+; K2Cr2O7 + H2SO4; orange > green Cr3+)
Reduction of carboxylic acid, aldehyde or ketone
Warm + H2O (solvent) \+NaBH4 Sodium tetrahybridborate (III) > H- 2[H] NUCLEOPHILIC ADDITION
Brady’s reagent
2,4-DNP
Forms an orange ppt with aldehydes and ketones
Recrystallize and can ID derivatives from melting points of known k/a
Silver mirror
Tollens’ reagent/ammonical silver nitrate [Ag(NH3)2]+ warm gently in a water bath - SM forms with aldehydes only as oxidised. Ag reduced.
Carboxylic acid
RCOOH Highly polar bonds Soluble in water up to 4 Cs Weak acids Partially dissociate
Esters
RCOOR’
Perfumes, food flavourings, oils
Formation of esters
- RCOOH + R’OH (c.H2SO4) RCOOR’ + H2O
2. Acid anhydride + alcohol > ester + CA