paper 2 Flashcards
NORMAL DISTRIBUTION
What are the features of a normal distribution curve?
- a bell shape curve
- a single peak
- symmetrical about the mean
• 50% above and 50% below the data - most of the data is within 1 s.d. of the mean
What proportions of the sample is at which point?
68% = within 1 s.d. of the mean (µ + 1∂ and µ - 1∂)
95% = within 2 s.d. of the mean (µ + 2∂ and µ - 2∂)
99.7% = within 3 s.d. of the mean (µ + 3∂ and µ - 3∂)
What are the notations for normal distribution?
µ = mean
∂ = standard deviation
What is the notation for a random X that is normally distributed?
X ~ N (µ,∂)
What does ∂² mean?
∂² is the standard deviation squared and is called VARIANCE
What are the rules for probability of normal distribution?
If X<15 LEAVE IT
(if it is pointing at number (less than))
If X>15 subtract it from 1
(pointing at X (greater than))
- if the answer is negative then DO THE OPPOSITE
How do you calculate the probability of normal distribution on a calculator?
- Press the MENU button and press 7
- Press ‘2: Normal CD’
- If X>15 (less than) put:
LOWER = -10000000
UPPER = 15 (or whatever number it is)
If X<15 (greater than) put:
LOWER = 15
UPPER = 10000000
What are some other points about finding ND on the calculator?
- calculator value is ALWAYS LESS THAN
- the same rules still apply about whether to subtract from zero or not
INVERSE DISTRIBUTION
What is the inverse normal?
INVERSE NORMAL = Area = probability/percentile
INVERSE DISTRIBUTION
What is the inverse normal?
INVERSE NORMAL = Area = probability/percentile
(e.g. 95% = 0.95
Area = 0.95 )
How do you find inverse normal on a calculator?
- Press the MENU button and press 7
- Press ‘3: Inverse Normal’
- Then input the area (to the left of the boundary), the standard deviation and the mean
EXAMPLE QUESTION OF INVERSE NORMAL
X~N (25,4)
- Find ‘a’ given that P(X = 0.27
- Input the information into the calculator:
Area :0.27
∂ :2
µ. :25
XInv = 23.77 - write as a=23.77
EXAMPLE QUESTION 2 OF INVERSE DISTRIBUTION
X~N (25,4)
P(24
1. find P(X<24) with NORMAL distribution LOWER: -100000 UPPER: 24 ∂: 2 µ: 25 P=0.30854 (the area on the left of the 24 boundary)
- Find P(X
CONFIDENCE INTERVALS
What will CONFIDENCE be based on?
THE SIZE OF THE SAMPLE = the larger the size of the sample, the closer the estimate is likely to be to the true population mean
THE VARIANCE = If readings are generally more varied then the estimate will be less reliable
How do you you calculate the standard error? what is it?
Standard error = ∂/√n
Standard error is how different the population mean is likely to be from a sample mean
(How different the population mean is from the point estimate)
What is the formula for confidence intervals?
x̅ ± 1.96 ∂/√n
(with µ in middle)
x̅ = sample mean n = sample size ∂ = population standard deviation
How does this formula look written out in full?
x̅ - 1.96 ∂/√n < µ < x̅ + 1.96 ∂/√n = 95%
(the numbers will change based on your level of confidence)
- = lower confidence limit \+ = upper confidence limit
What are the decimal numbers that are substituted into the formula for different confidence intervals?
90% = 1.64 95% = 1.96 98% = 2.33 99% = 2.57