P9 - Motion (Year 9) Flashcards
what is the equation for calculating speed?
speed = distance / time
m/s = m / s
what equation is used to calculate acceleration?
a = …
a = (v - u) / t
acceleration = (final velocity - initial velocity) / time
(m/s)2 = m/s / s
how is constant speed calculated?
Speed & Distance-Time Graphs
∆ distance / ∆ time
–>
∆y / ∆x
–>
(basically find the gradient of the straight line)
what does the gradient of a distance-time graph tell you?
Speed & Distance-Time Graphs
the speed
rearrange the equation for speed to calculate distance
Speed & Distance-Time Graphs
speed = distance / time
–>
distance = speed x time
(distance would be at the top of the triangle)
rearrange the equation for speed to calculate time
Speed & Distance-Time Graphs
speed = distance / time
–>
time = distance / speed
(distance would be at the top of the triangle)
speed = ? and velocity = ?
what is the difference between speed and velocity?
Velocity & Acceleration
speed = scalar
velocity = vector*
Speed is just how fast you’re going (e.g. 30mph or 20m/s) with no regard to the direction.
Velocity is speed in a given direction. e.g. 30 mph or 20 m/s, 060°.
(RG p60)
*(the orange dude from despicable me who talks about dircetion and magnitude)
how do we calculate acceleration?
- a = Δv / t
- acceleration = Δ velocity / time
- acceleration = (final velocity - initial velocity) / time
what is the difference between acceleration and deceleration?
acceleration: speed (or velocity) is increasing
deceleration: speed (or velocity) is decreasing
note: deceleration of 5m/s squared = acceleration of -5m/s squared
what does a horizontal line on a velocity-time graph tell you?
no acceleration; constant speed (or velocity)
(sketch a velocity-time graph of an object decelerating)
n/a
what does the area under a velocity-time graph tell you?
the distance
how do we calculate acceleration from a velocity-time graph?
‘for constant…’ and ‘for increasing (or decreasing I guess)…’
constant acceleration:
∆ velocity / ∆ time
–>
∆y / ∆x
–>
(basically find the gradient of the straight line)
increasing acceleration (or decreasing deceleration I guess):
1. draw a tangent for whatever point you need to find the acceleration for; it has to be parallel to the curve at that point
2. draw a triangle (with the tangent line as the hypotenuse)
3. ∆ velocity / ∆ time –> find the gradient of the tangent.
how do we calculate distance from a velocity-time graph?
calculate the area under the line
how do we calculate speed from a distance-time graph where the object is accelerating?
- draw a tangent for whatever point you need to find the speed for; it has to be parallel to the curve at that point
- draw a triangle (with the tangent line as the hypotenuse)
- ∆ distance / ∆ time
–>
∆y / ∆x
–>
(basically find the gradient of the straight line)