organisms exchange substances with their environment TOPIC 3 Flashcards

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1
Q

Describe the relationship between the size and structure of an organism and its SA:V ratio.

A

-As size increases, SA:V decreases
-More thin/elongated structures have a higher SA:V.

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2
Q

Suggest an advantage of calculating SA:mass for organisms instead of SA:V

A

SA:mass is easier to find because it is hard to find volume of irregular shapes.

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3
Q

What is metabolic rate?

A

Amount of energy used by an organism within a given period of time.

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4
Q

How is metabolic rate measured?

A

By measuring oxygen uptake.

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5
Q

Explain the relationship between SA:V and metabolic rate.

A

As SA:V increases, metabolic rate increases because:
-rate of heat loss per unit body mass increases
-so organisms need a higher rate of respiration to release energy in the form of heat
-to maintain a constant body temperature.

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6
Q

Describe the 3 main components that make up the tracheal system of an insect.

A
  1. ๐—ฆ๐—ฝ๐—ถ๐—ฟ๐—ฎ๐—ฐ๐—น๐—ฒ๐˜€: pores on surface that can open/close to allow diffusion.
    2.๐—ง๐—ฟ๐—ฎ๐—ฐ๐—ต๐—ฒ๐—ฎ๐—ฒ: large tubes full of air that allow diffusion
    3.๐—ง๐—ฟ๐—ฎ๐—ฐ๐—ต๐—ฒ๐—ผ๐—น๐—ฒ๐˜€: smaller branches from trachea, permeable to allow gas exchange with cells.
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7
Q

Explain how an insectโ€™s tracheal system is adapted for gas exchange.

A

๐—ง๐—ฟ๐—ฎ๐—ฐ๐—ต๐—ฒ๐—ผ๐—น๐—ฒ๐˜€:
-Thin walls so short diffusion distance to cells
-Highly branched tracheoles so large surface area.
๐—ง๐—ฟ๐—ฎ๐—ฐ๐—ต๐—ฒ๐—ฎ๐—ฒ:
-provide tubes full of air so fast diffusion
๐—–๐—ผ๐—ป๐˜๐—ฟ๐—ฎ๐—ฐ๐˜๐—ถ๐—ผ๐—ป ๐—ผ๐—ณ ๐—ฎ๐—ฏ๐—ฑ๐—ผ๐—บ๐—ถ๐—ป๐—ฎ๐—น ๐—บ๐˜‚๐˜€๐—ฐ๐—น๐—ฒ๐˜€:
-changes pressure in body causing air to move in/out
-maintains concentration gradient for diffusion.

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8
Q

Describe both structural and functional adaptations in terrestrial insects which allow efficient gas exchange while limiting water loss.

A

๐˜๐—ต๐—ถ๐—ฐ๐—ธ ๐˜„๐—ฎ๐˜…๐˜† ๐—ฐ๐˜‚๐˜๐—ถ๐—ฐ๐—น๐—ฒ: increases diffusion distance so less evaporation.
๐˜€๐—ฝ๐—ถ๐—ฟ๐—ฎ๐—ฐ๐—น๐—ฒ๐˜€: can open to allow gas exchange AND close to reduce water loss. ๐—ต๐—ฎ๐—ถ๐—ฟ๐˜€ around spiracles: trap moist air, reducing water potential gradient so less water loss (evaporation).

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9
Q

Explain how gills of fish are adapted for gas exchange.

A

-Gills are made of many filaments covered with ๐—บ๐—ฎ๐—ป๐˜† ๐—น๐—ฎ๐—บ๐—ฒ๐—น๐—น๐—ฎ๐—ฒ increasing surface area for diffusion.
-๐˜๐—ต๐—ถ๐—ป ๐—น๐—ฎ๐—บ๐—ฒ๐—น๐—น๐—ฎ๐—ฒ ๐˜„๐—ฎ๐—น๐—น: short diffusion distance between water/blood.
-Lamallae have ๐—น๐—ฎ๐—ฟ๐—ด๐—ฒ ๐—ป๐˜‚๐—บ๐—ฏ๐—ฒ๐—ฟ ๐—ผ๐—ณ ๐—ฐ๐—ฎ๐—ฝ๐—ถ๐—น๐—น๐—ฎ๐—ฟ๐—ถ๐—ฒ๐˜€- maintains a conc. gradient as O2 is removed quickly and CO2 is taken in.

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10
Q

Explain the counter current flow system in fish.

A

1.Blood and water flow in opposite directions through lamellae.
2.So oxygen conc. is always higher in water, to ensure that oxygen constantly diffuses into blood (high conc. to low)
3. This maintains a conc. gradient of O2 between water and blood.
4.For diffusion along the whole length of lamallae.

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11
Q

What would happen if both blood and water flowed in the same direction?

A

equillibrium would be reached so oxygen wouldnโ€™t diffuse into the blood along lamellae.

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12
Q

Explain how the leaves of a dicotyledonous plant is adapted for gas exchange.

A

-๐—บ๐—ฎ๐—ป๐˜† ๐˜€๐˜๐—ผ๐—บ๐—ฎ๐˜๐—ฎ: large surface area for gas exchange.
-๐˜€๐—ฝ๐—ผ๐—ป๐—ด๐˜† ๐—บ๐—ฒ๐˜€๐—ผ๐—ฝ๐—ต๐˜†๐—น๐—น: contains air spaces- large surface area for gases to diffuse through
-๐˜๐—ต๐—ถ๐—ป: short diffusion distance.

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13
Q

Describe adaptations in xerophytic plants for gas exchange while limiting water loss.

A

-๐—ง๐—ต๐—ถ๐—ฐ๐—ธ๐—ฒ๐—ฟ ๐˜„๐—ฎ๐˜…๐˜† ๐—ฐ๐˜‚๐˜๐—ถ๐—ฐ๐—น๐—ฒ: increases diffusion distance for water so less evaporation
-๐—ฆ๐˜‚๐—ป๐—ธ๐—ฒ๐—ป ๐˜€๐˜๐—ผ๐—บ๐—ฎ๐˜๐—ฎ ๐—ถ๐—ป ๐—ฝ๐—ถ๐˜๐˜€/ ๐—ฟ๐—ผ๐—น๐—น๐—ฒ๐—ฑ ๐—น๐—ฒ๐—ฎ๐˜ƒ๐—ฒ๐˜€/ ๐—ต๐—ฎ๐—ถ๐—ฟ๐˜€: traps water vapour, so reduced water potential gradient between leaf/air, so less evaporation.
-๐˜€๐—ฝ๐—ถ๐—ป๐—ฒ๐˜€/๐—ป๐—ฒ๐—ฒ๐—ฑ๐—น๐—ฒ๐˜€: reduces surface area to volume ratio.

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14
Q

What makes up the human gas exchange system?

A

-Trachea
-Bronchi
-Bronchioles
-Capillary network
-Alveoli
ALL found in lungs

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15
Q

What is the alveolar epithelium?

A

A single layer of cells that line the walls of the alveoli.

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16
Q

Describe how the alveolar epithelium is adapted for gas exchange.

A

-consists of flattened cells: short diffusion distance
-folded: large surface area
-permeable: allows diffusion of O2/CO2
-large network of capillaries: good blood supply which maintains conc. gradient.

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17
Q

Describe how gas exchange occurs in the lungs.

A

-Oxygen diffuses from alveolar air space into blood down its conc. gradient
-first across alveolar epithelium then across capillary endothelium.
(OPPOSITE FOR CARBON DIOXIDE: first capillary endothelium, then alveolar epithelium)

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18
Q

Explain the importance of ventilation.

A

-Brings in air containing a high conc. of O2 and removes air with lower conc. of O2.
-maintains conc. gradient

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19
Q

Describe the process of Inspiration (breathing in).

A
  1. External intercostal muscles contract
  2. Ribcage is pulled up / out
  3. Volume ๐—ถ๐—ป๐—ฐ๐—ฟ๐—ฒ๐—ฎ๐˜€๐—ฒ๐˜€ and pressure ๐—ฑ๐—ฒ๐—ฐ๐—ฟ๐—ฒ๐—ฎ๐˜€๐—ฒ๐˜€ in thoracic cavity
  4. Air moves into lungs down pressure gradient.
20
Q

Describe the process of expiration (breathing out).

A
  1. External intercostal muscles relax
  2. Ribcage moves down / in
  3. Volume ๐—ฑ๐—ฒ๐—ฐ๐—ฟ๐—ฒ๐—ฎ๐˜€๐—ฒ๐˜€ and pressure ๐—ถ๐—ป๐—ฐ๐—ฟ๐—ฒ๐—ฎ๐˜€๐—ฒ๐˜€ in thoracic cavity
  4. Air moves out of lungs down pressure gradient.
21
Q

Suggest why expiration (breathing out) is normally passive at rest.

A

-Internal intercostal muscles do not normally need to contract
-during expiration lungs naturally spring back to their original size (elastic recoil).

22
Q

Suggest how different lung diseases reduce the rate of gas exchange. (3)

A

1.๐—ง๐—ต๐—ถ๐—ฐ๐—ธ๐—ฒ๐—ป๐—ฒ๐—ฑ alveolar tissue (e.g. fibrosis)- increases diffusion distance
2. Alveolar wall ๐—ฏ๐—ฟ๐—ฒ๐—ฎ๐—ธ๐—ฑ๐—ผ๐˜„๐—ป- reduces surface area.
3. ๐—ฅ๐—ฒ๐—ฑ๐˜‚๐—ฐ๐—ฒ๐—ฑ ๐—น๐˜‚๐—ป๐—ด ๐—ฒ๐—น๐—ฎ๐˜€๐˜๐—ถ๐—ฐ๐—ถ๐˜๐˜†- lungs expand / recoil less reducing conc. gradients of O2 / CO2.

23
Q

Suggest how different lung diseases affect ventilation. (3)

A
  1. ๐—ฅ๐—ฒ๐—ฑ๐˜‚๐—ฐ๐—ฒ๐—ฑ ๐—น๐˜‚๐—ป๐—ด ๐—ฒ๐—น๐—ฎ๐˜€๐˜๐—ถ๐—ฐ๐—ถ๐˜๐˜†- lungs expand / recoil less:
    -reducing volume of air in each breath (tidal volume)
    -reducing maximum volume of air breathed out in one breath.
  2. ๐—ก๐—ฎ๐—ฟ๐—ฟ๐—ผ๐˜„ ๐—ฎ๐—ถ๐—ฟ๐˜„๐—ฎ๐˜†๐˜€ / ๐—ฟ๐—ฒ๐—ฑ๐˜‚๐—ฐ๐—ฒ ๐—ฎ๐—ถ๐—ฟ๐—ณ๐—น๐—ผ๐˜„ in and out of lungs (e.g. asthma)
    -reducing maximum volume of air breathed out in ๐Ÿญ ๐˜€๐—ฒ๐—ฐ๐—ผ๐—ป๐—ฑ (forced expiratory volume)
    3.๐—ฟ๐—ฒ๐—ฑ๐˜‚๐—ฐ๐—ฒ๐—ฑ ๐—ฟ๐—ฎ๐˜๐—ฒ ๐—ผ๐—ณ ๐—ด๐—ฎ๐˜€ ๐—ฒ๐˜…๐—ฐ๐—ต๐—ฎ๐—ป๐—ด๐—ฒ- increased ventilation rate to compensate for reduced oxygen in blood.
24
Q

What is tidal volume?

A

Volume of air in each breath.

25
Q

How do you work out the Pulmonary Ventilation Rate (PVR)?

A

tidal volume x breathing rate

26
Q

Suggest why people with lung disease experience fatigue.

A

Cells receive less oxygen (๐Ÿญ), so rate of aerobic respiration is reduced (๐Ÿญ) so less ATP is made (๐Ÿญ).

27
Q

How is a concentration gradient maintained in both insects and humans?

A

๐—œ๐—ป๐˜€๐—ฒ๐—ฐ๐˜๐˜€:
-contraction of abdominal muscles changes pressure in body, causing air to move in / out.
-This maintains a concentration gradient for diffusion
๐—›๐˜‚๐—บ๐—ฎ๐—ป๐˜€:
-Blood in the capillaries flows in the opposite direction to the water, ensuring that the concentration gradient is maintained along the whole length of the capillary.
-A good blood supply from large network of capillaries maintains concentration gradient.

28
Q

Explain what happens in digestion.

A

-Large (insoluble) biological molecules are hydrolysed to smaller (soluble) molecules.
-that are small enough to be absorbed across cell membranes into blood.

29
Q

Describe the digestion of starch in mammals.

A

-Amylase hydrolyses starch to maltose by hydrolysing the glycosidic bonds in starch.
-Membrane-bound maltase hydrolyses maltose to glucose by hydrolysing glycosidic bonds.

30
Q

Where is amylase produced?

A

Produced in the salivary glands and pancreas.

31
Q

Where is membrane-bound maltase produced?

A

Produced in the cells of the mucous membrane lining the small intestine.

32
Q

Maltose hydrolyses intoโ€ฆ

A

Glucose + Glucose

33
Q

Sucrose hydrolyses intoโ€ฆ

A

Fructose + Glucose

34
Q

Lactose hydrolyses intoโ€ฆ

A

Galactose + Glucose

35
Q

Describe the digestion of lipids in mammals.

A

-Bile salts emulsify lipids causing them to form smaller lipid droplets
-this increases the surface area of lipids for increased / faster lipase activity
-Lipase then hydrolyses lipids to form monoglycerides + fatty acids
-Hydrolysis of ester bond

36
Q

Where are lipase enzymes produced and secreted?

A

Produced in the pancreas and secreted into the small intestine.

37
Q

Function of endopeptidases.

A

Hydrolyse peptide bonds in the middle of polypeptides producing shorter polypeptides.
It is produced in the stomach and pancreas.

38
Q

Function of exopeptidases.

A

Hydrolyse peptide bonds at the ends of polypeptide chains to produce dipeptides.

39
Q

Why is the combined action of endopeptidases and exopeptidases more efficient than exopeptidases on their own?

A

because endopeptidases hydrolyse bonds in the middle of the polypeptides, which creates more ends and more SA for hydrolysis by exopeptidases.

40
Q

What are dipeptidases and where are they found?

A

They hydrolyse dipeptides into amino acids which are released into the cytoplasm of the cell.
Found within the cell-surface membrane of the epithelial cells in the small intestine.

41
Q

How are proteins digested?

A

Proteins are hydrolysed into amino acids in following steps:
-In the lumen of the stomach, ๐—ฒ๐—ป๐—ฑ๐—ผ๐—ฝ๐—ฒ๐—ฝ๐˜๐—ถ๐—ฑ๐—ฎ๐˜€๐—ฒ hydrolyse peptide bonds in the middle of polypeptides.
-๐—ฒ๐˜…๐—ผ๐—ฝ๐—ฒ๐—ฝ๐˜๐—ถ๐—ฑ๐—ฎ๐˜€๐—ฒ hydrolyse the peptide bonds at the end of polypeptide chains to produce dipeptides.
-๐—ฑ๐—ถ๐—ฝ๐—ฒ๐—ฝ๐˜๐—ถ๐—ฑ๐—ฎ๐˜€๐—ฒ ๐—ฒ๐—ป๐˜‡๐˜†๐—บ๐—ฒ๐˜€ (which are found within the cell-surface membrane of the epithelial cells in the small intestine) hydrolyse dipeptides into amino acids which are released into the cytoplasm of the cell.

42
Q

Suggest why membrane-bound enzymes are important in digestion.

A

-They are located on cell membranes of epithelial cells lining the ileum
-By hydrolysing molecules at the site of absorption, they maintain concentration gradients for absorption.

43
Q

Describe the absorption of amino acids and monosaccharides in mammals.

A

1) Na+ is actively transported from epithelial cells lining ileum to blood (by sodium-potassium pump).
2)A concentration gradient is established of Na+ (higher in lumen than epithelial cell)
3) Na+ enters epithelial cell down its concentration gradient with monosaccharide / amino acid against its conc. gradient via a co-transporter protein.
4) Monosaccharide / amino acid moves down a concentration gradient into blood via facilitated diffusion.

44
Q

Describe the absorption of lipids by a mammal, including the role of micelles.

A

-Bile salts combine with monoglycerides and fatty acids to form micelles
-micelles make monoglycerides and fatty acids soluble in water
-micelles carry fatty acids and monoglycerides to cells lining the ileum, where they break down to release them
-this maintains a high conc. of fatty acids and monoglycerides near cells lining the ileum
-monoglycerides / fatty acids are absorbed into epithelial cell by diffusion (as now theyโ€™re soluble)
-triglycerides reformed in cells and aggregate into globules.
- globules coated with proteins forming chylomicrons which are then packaged into vesicles
-Vesicles move to cell membrane and fuse with it, releasing chylomicrons via exocytosis. โ€“> chylomicrons enter lymphatic vessels and eventually return to blood circulation.

45
Q

Describe the role of red blood cells and haemaglobin (Hb) in oxygen transport.

A

Red blood cells contain lots of Hb:
-have no nucleus + biconcave- more space for Hb, high SA:V & short diffusion distance.
-Hb associates with oxygen at gas exchange surfaces where partial pressure of oxygen is high.
-This forms oxyhaemaglobin which transports oxygen
-Hb unloads oxygen near cells where pressure of oxygen is low.

46
Q

Describe the structure of haemaglobin.

A

-protein with a quaternary structure
-made of 4 polypeptide chains
-each chain contains a Haem group containing an iron ion.