Organic Chemistry - Topic 6.1 - 6.2 Flashcards
What are organic molecules
Covalent molecules based on the element carbon
What is the hydroxyl functional group
OH
What is the functional group
A group of atoms which gives an organic compound its characteristic properties and determines how it reacts
What is a homologous series
A series of Organic molecules with the same functional group but each successive member has an additional CH2
Why can carbon form so many compounds
- carbon can form chains, chained branches and rings of varying sizes which other molecules can attach to
- Carbon forms inert bonds with C-C and C-H due to its relatively high bond enthalpy
What are saturated hydrocarbons
Hydrocarbons with only single covalent bonds between carbon atoms
What is an unsaturated hydrocarbon
A hydrocarbon with a double or triple bond
Prefixes for alkanes and number of carbon atoms up to 10 carbon atoms
Meth - 1 c atoms
Eth - 2 c atoms
Prop - 3 c atoms
But - 4 carbon atoms
Pent - 5 carbons atoms
Hex - 6 c atoms
Hept - 7 carbon atoms
Oct - 8 c atoms
Non - 9 c atoms
Dec - 10 c atoms
Why are alkanes unreactive
- they are non polar as carbon atoms and hydrogen atoms have similar Electronegativity
- the bonds are relatively strong and require a lot of energy to break
What is a free radical
Any species with an unpaired electron
Stages in the free radical substitution with methane and bromine
1) initiation stage
UV light is shon onto the bromine molecule, the energy of the UV light causes the single covalent bond between the two bromine atoms to break. When the bond breaks each electron from the covalent bond (as one covalent bond consists of a pair of electrons) goes to each bromine atom, and as they have unpaired electrons they form bromine free radicals
Br- Br → Br. + Br.
When a covalent bond splits this way scientist calls it homolytic fission
2) Propagation stage
1st step - a bromine free radical reacts with a methane molecule and forms a covalent bond by taking a hydrogen atom(with its electron in the hydrogen atom) from the methane to form hydrogen bromide and a methyl free radical (as the carbon atom will have an unpaired electron)
2nd step - the methyl free radical reacts with a bromine molecule producing bromomethane and another bromine free radical, this causes a chain reaction as the bromine free radical in step 2 can be used in step one to react with methane until it reaches the termination stage
3) termination stage
Two bromine free radicals react together to form a bromine molecule with no free radicals
OR
Two methyl free radicals can form a molecule of ethane
OR
A methyl free radical and a bromine free radical can form a molecule of bromomethane
Problems with free radical substitution with bromine and methane
A lot of side products can form
E.g
Bromomethane + bromine free radical → dibromomethane
Dibromomethane + bromine free radical → tribromomethane
Tribromomethane + bromine free radical → tetrabromomethane
What is homolytic fission
When a covalent bond breaks evenly and each bonded atom takes one of the shared pair of electrons
General formulas for alkanes
CnH2n+2
What are the bond angles in alkanes
109.5 as they have a tetrahedral structure
What is the general formula of alkenes
CnH2n
Bond angles of alkenes
120
What does the double bond in alkenes consist of
A sigma bond and a pi bond
Properties of alkenes
- as it contains a pi bond due to its double bond, the pi bond cannot rotate as any rotation will reduce the overlap of any p orbitals this means the alkenes can form stereoisomers
- they are highly reactive as the bond enthalpy of the pi bond is less than the sigma bond as the pi bond is a sideways overlap of orbitals whilst a sigma bond is a direct overlap, meaning that it will take less energy to break the pi bond making alkenes very reactive
- the double bond contains two pairs of electrons - one in the pi and one in the sigma - so the double bond is a region of high electron density making alkenes highly reactive
How do alkanes react
Free radical substitution
How do alkenes react
Electrophilic addition
Process of electrophilic addition of hydrogen halide and alkenes ( ethene and hydrogen bromide)
1) the hydrogen bromide molecule (which is already polar due to the bromine being more electronegative than the hydrogen) approaches the ethene, the electrophile (the positive hydrogen atom on the HBr) is attracted to the high electron density of the double bond and attracts the pair of electrons in the pi bond of the alkene, causing it to move towards the hydrogen atom in the HBr, but as the hydrogen atom can only form one covalent bond at the same time the pair of electrons between the hydrogen atom and bromine move onto the bromine atom, which is called heterolytic fission
2) this forms a positively charged carbocation intermediate (which contains a positively charged carbon atom) which is positively charged as it lost its electron pair that were in the pi bond (so it has lost its double bond and is now single bonded with an extra h atom from 1st step) and a negatively charged bromide ion
3) the electron pair on the bromide ion are attracted to the positive carbon atom in the carbocation and this electron pair forms a covalent bond with the bromide ion and the carbocation to form bromoethane
What is an electrophile
Any positive ion or molecule that is attracted to a region of high electron density
What is markowinoffs rule
when a hydrogen halide reacts with an asymmetric alkene the hydrogen halide is more likely to bond to the carbon atom with the greater number of hydrogen atoms attached to it
What is a carbocation intermediate
An unstable molecule that exist for a short period of time
What does the stability of the carbocation depend on
The number of alkyl groups bonded to the carbon atom with the positive charge
What is an alkyl group
A group containing carbon and hydrogen atoms
What is a primary secondary and tertiary carbocation
Primary- when there is only one alkyl groups attached to the positive carbon atom
Secondary- when there is two alkyl groups attached to the positive carbon atom
Tertiary - where there are three alkyl groups attached to the positive carbon atom
Why is the secondary carbocation more stable and more likely to form a major product than the primary carbocation
As there are more alkyl groups attached to the secondary carbocation so has a stronger inductive effect,this is because the greater number of alkyl groups means that more electrons are pushed towards the positive charge, this provides it better stability as the positive charge is more reduced and because of this extra stability the secondary cation is more likely to form, resulting in it to form a major product
How to tell which product is major or minor in electrophilic addition
The one with the most alkyl groups attached to it is the major product
What are structural isomers
Compounds with the same molecular formula but different structural formula
What are chain isomers, position isomers and functional isomers
Chain isomers- isomers with different chains of carbon atoms
Position isomers - isomers with different positions of the same functional group
Functional isomers - isomers with different functional groups
What are stereoisomers
Molecules with the same structural and molecular formula but have different spatial arrangements of bonds (arranged differently in space)
Types of stereoisomers
Geometrical isomers
Optical isomers
Naming systems for geometric isomers
E/Z isomerism
Cis/Trans isomerism
Why can alkenes only form cis/trans isomers
As they contain double bonds which cannot fully rotate but can only flex slightly
What conditions do alkenes have to have to form cis/trans isomers
- carbon atoms on double bond must be attached to two different groups
- one of the groups on both carbon atoms of the double bond must be the same
- there must be a restriction to rotation about a bond
How to determine if cis or trans isomer
If the group which is the same on both carbon atoms in the double bond are on the same side then it’s a cis isomer and if its on different sides then it’s a trans isomer
CIP priority rules (for naming E/Z isomers with four different groups all attached to the carbon atoms involved in double covalent bonds)
- the element with the greatest atomic number is given the higher priority on each side of the double bond
- the we assign the higher priority groups using the E/Z isomerism if the higher priority groups are on the same side the it is an Z isomer and if the higher priority groups are in opposite sides it’s is the E isomer
- if the carbon atom is attached to two of the same groups (e.g two o atoms) then we use the atom next to it (e.g in this case the next atom to o) to establish priority
Conditions for free radical substitution
UV light, room temperature