Organic Analysis Flashcards

1
Q

What can organic analysis/identifying organic substances be used for ?

A

Modern instrumental methods
- such as mass spectrometry
- and infrared spectroscopy
have made the identification
of organic substances much simpler.

Mass spectrometry can identify chemical composition of a sample
based on mass:charge ratio.
— Can be used to:
• detecting banned drugs in sport
• monitor and track pollutants in the air or in water supplies
• detect toxins in food
• locate oil deposits by testing rock samples
• determine the extent of damage to human genes due to the environment
• identify the country of origin of diamonds.

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2
Q

What happens in Mass spectrometry of organic compounds

A

When an element sample of passes through a mass spectrometer,
- the spectrum produced consists of several lines.
- The lines are due to different isotopes of the element

When an organic compound passes through a mass spectrometer
- the spectrum produced also consists of several lines.
- In this case, lines are due to original molecule and fragments of molecule.
> The line with largest m/z ratio is known as the molecular ion.
> This line has been produced by a molecule wch lost one electron.

Eg. A simplified version of mass spectrum of pentan2one diagram 1
- The lines on spectrum are due to molecular ion
- and ions produced by fragments of molecule. The molecular ion is at 86.

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3
Q

What are The mass spectra of compounds containing chlorine like

A

There are two molecular ion peaks in mass spectra of compounds containing a single chlorine atom.
- because chlorine exists as two isotopes, 35Cl and 37Cl.
-
- The peak at m/z ratio 78 is due to molecular ion (CH3CH35ClCH3)+
- containing atom of 35Cl.
- The peak at m/z ratio 80 is due to molecular ion (CH3CH37CICH3)+
- containing an atom of 37Cl.

> > The ratio of the peaks is 3:1.
-This ratio reflects abundance of the chlorine isotopes; 35Cl:37Cl is 3:1.
diagram 2

..

Are three molecular ion peaks in mass spectrum of 2,2-dichloropropane, two chlorine atoms
- They correspond to
(CH3C35Cl35CICH3)+
(CH3C35Cl37CICH3)+ and
(CH3C37Cl37CICH3)+.
>
> The three peaks are in a ratio 9:6:1.
&raquo_space; The ratio can be understood by working out probability of 35Cl or 37Cl being present in the molecule.
- Remember there is 3/4 chance of a chlorine atom being 35Cl
- and 1/4 chance of a chlorine atom being 37Cl.
- In a molecule containing two chlorine atoms the possible combinations are:
** DIAGRAM 3** - LEARN!

This gives a distinctive pattern in a mass spectrum.
A pattern of 3 molecular ions, M, M+2 and M+4, in a ratio of 9:6:1
is an indication molecule has 2 Cl atoms.

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4
Q

What are The mass spectra of compounds containing bromine like (2)

A

Bromine exists as two isotopes,
79Br and 81Br,
> an almost 1:1 ratio (50.5:49.5).

The mass spectrum of 2-bromopropane will show two molecular ions
- one at 122; (CH3CH79BrCH3)+
- and at 124; (CH3CH81BrCH3)+.
These molecular ion peaks will be in the ratio 1:1
reflecting the relative abundance of bromine isotopes.

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5
Q

Whats high resolution mass spectrometry (do questions on!)

A

Consider the three mass spectra (diagram 6)
> which are of three High resolution mass spectrometry
- different organic compounds pentane and structural isomers, butanone and butanal.
- Each spectrum has a molecular ion peak at a mass:charge ratio of 72.

..

High resolution mass spectrometry
> can help distinguish between these three compounds.
- It can measure relative atomic masses to 4 decimal places.
-
- A more accurate value of relative molecular mass of molecular ion can establish wch compound is pentane.
- The Ar of 12C is exactly 12.0000 by definition.
> Relative atomic masses of other atoms are measured relative to 12C isotope.
>
> Using these values (on diagram), relative molecular mass of pentane is 72.0939
- and the relative molecular mass of butanone and butanal is 72.0575.

In diagram 6
Spectrum A is pentane as m/z ratio of molecular ion
on high resolution mass spec is 72.0939.

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6
Q

What is Infrared spectroscopy (do questions!!)

A

Pairs of atoms joined by a covalent bond continually vibrate.
> The frequency of vibration is unique to atom combo of bond
> differs if bond is single/double/triple.
> A C-C single bond vibrates at a diff frequency to C-C double bond
> or an O-H bond.

These vibrations have a frequency in infrared region of EM spectrum.
— called the natural frequency of vibration of the bond.
..

When a beam of infrared radiation is shone onto an organic compound
- some energy is absorbed and amplitude of vibration of covalent bond increases.
- bond only absorbs radiation that has same freq as natural freq of bond.
-
- Each type of bond has a natural vibration freq
- and same bond surrounded by diff groups of atoms has a diff natural freq of vibration.
&raquo_space; This knowledge enables chemists to identify groups of atoms in a molecule
&raquo_space; and enviro. surrounding this group.
&raquo_space;
Eg. analysis of an IR spectrum of a compound may indicate
A C=O group is present and will also indicate if it is part of a
-CHO group in an aldehyde, or part of a
-COOH group in a carboxylic acid.
All organic compounds absorb infrared radiation.
Bonds in molecules absorb infrared radiation at characteristic wavenumbers.

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7
Q

What are infrared spectra (the graph?)

A

The spectrum begins at top of graph
and consists of a series of dips,
> wch represent infrared frequency absorbed by particular bonds.
>These dips are called ‘peaks’.
> dips are troughs in other cases.

Another unusual aspect of an infrared spectrum is the scale.
- The x-axis scale of infrared spectrum is diff to right and left of 2000 cm-1.
- begins at 4000 cm-1 and ends at 500.
-
- An infrared spectrometer doesnt contain any glass or quartz
>as these absorb infrared radiation.
>
>All internal reflecting and refracting surfaces
>are from polished sodium chloride crystals.
The samples can easily be prepared.
The mass of sample required is very small; approximately 1 mg is needed.

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8
Q

How would we analyise infrared spectra

A

The functional group(s) of a molecule can be found by analysing infrared spectra
- in region between 4000 and 1500cm-1.

diagram 6
> shows IR spectra of ethanol, ethanoic acid and propanone.
> All the compounds
have C—H bonds,
two have OH groups,
two have C=O groups in molecule.

..

The C-H bond is in almost all organic compounds.
> A peak just under 3000 cm-1 is probably due to C—H bonds.
>
> Absorption of O-H bond varies slight, depending on compound sort it is in.
- The -OH bond in alcohol absorbs at higher wavenumber than in an acid.
- its easily recognised as produces a broad peak in an alcohol
- and a very broad peak in an acid.

The C=O produces a peak present in spectra for ethanoic acid and propanone.
- an absence of broad OH peak in spectrum of propanone.
- small absorbance at approx 2900 cm- is probably due to C-H bonds.

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9
Q

The fingerprint region in IR spectra

A

The area of spectrum below 1500 cm-1
> known as fingerprint region of spectra.
>
The absorptions are complex
- caused by varied and complicated vibrations of entire molecule.
- This part of spectrum is unique to the molecule.

..
- IR spectra of many known organic molecules have been recorded and are available in a database.
- To identify a molecule, the IR spectra is produced and compared to this database.
-
- The infrared spectra of ethanoic acid and butanoic acid are in diagram 7
> is an C=O group and a broad peak indicating OH in both
> These peaks indicate that both the compounds are carboxylic acids.

the infrared spectra of ethanoic acid and butanoic acid are compared
- The region between 1500 cm-1 and 4000 cm- 1 are very similar
- but the fingerprint region below 1500 cm-1 is unique to each compound.

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10
Q

Checking purity with IR spectra

A

Infrared spectra can be used to check the purity of a compound.
- When the infrared spectrum of a known compound is produced extra peaks can indicate that the compound is not pure.

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11
Q

How is greenhouse effect related to absorbing IR radiation

A

The greenhouse effect shows how the greenhouse gases,
> carbon dioxide, water and methane
absorb infrared radiation, leading to the greenhouse effect and global warming.

The bonds in these gases are very efficient at absorbing infrared radiation.
- Infrared spectra of carbon dioxide, methane and water have deep bands
- indicating their high efficiency in absorption of infrared radiation.
- When infrared radiation hits a molecule of these gases
- its absorbed and causes bonds to vibrate.

Oxygen and nitrogen, the other major gases in the atmosphere do not have this property.
> It is the absorption of infrared radiation by greenhouse gases that contributes to global warming.

diagram 8

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12
Q

Identification of functional groups by test-tube reactions (4)

A

Some simple chemical tests can be used to identify presence of functional groups
» most organic comidont mix with water
&raquo_space; but short chain alcohols and carboxylic acids do

• Alkenes (C=C)
The reagent is bromine water
> solution goes orange to colourless if positive

• alcohols (OH)
Reagent is acidified potassium dichromate
• primary/secondary
> orange to green solution if positive
• tertiary
> orange solution remains orange

• aldehydes (C=O)
Tollens Reagent
> colourless solution to silver ppt / silver
mirror form on test tube sides if positive
Fehlings solution
> blue solution to orange/red ppt formed
if positive

• carboxylic acids (COOH)
solid sodium carbonate is reagent
> turns from white solid, to producing effervescence (CO2 tested w limewater)

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